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Circumference of a circle Solving equations Sine rule Cosine rule Rounding numbers Squares and square rootsThis topic is relevant for:

Here we will learn about calculating **arc length **including how to identify the arc of a circle (minor and major), form and use the formula for the arc length of a circle and calculate the arc length in various scenarios.

There are also arc length worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

The **arc length** is a portion of the circumference of the circle

**Major arc:** a major arc is greater than half the circumference.

**Minor arc:** a minor arc is less than half the circumference.

Arc length = \frac{\theta}{360} \times \pi\times d

*θ – angle of the sector*

* d –*

Or

Arc length = \frac{\theta}{360} \times 2\times\pi \times r

*θ- angle of the sector*

* r – radius of the circle*

In order to find the **arc length** you need to be able to find the circumference of a circle. This is because the arc length is a portion of the circle’s circumference. ‘How much’ of the circle is decided by the angle created by the two radii.

The sum of the angles around a point is equal to 360°

Therefore, the arc length is the **fraction of the circle’s circumference** created by the sector.

The angle is out of 360 or \frac{\theta}{360} , where θ (theta) represents the angle*, *so we can **multiply **this by the circumference to calculate the arc length.

NOTE: At GCSE all angles are measured in degrees. Make sure that your calculator has a small ‘d’ for degrees at the top of the screen rather than an ‘r’ for radians- these are not used until A Level.

**Arc length formula:**

Arc length = \frac{\theta}{360} \times \pi\times d

*θ – angle of the sector*

* d –*

Or

Arc length = \frac{\theta}{360} \times 2\times\pi \times r

*θ – angle of the sector*

* r – radius of the circle*

In order to solve problems involving the arc length you should follow the below steps:

**Find the length of the radius/diameter.****Find the size of the angle creating the arc of the sector.****Substitute the value of the radius/diameter and the angle into the formula for the arc length.****Clearly state your answer**.

Get your free arc length worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free arc length worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREE**Arc length** is part of our series of lessons to support revision on **arc of a circle** and **circles, sectors and arcs**. You may find it helpful to start with the main circles, sectors and arcs lesson for a summary of what to expect, or use the step by step guides below for further detail on individual topics. Other lessons in this series include:

Calculate the arc length of the sector shown below. Give your answer to 3 decimal places.

**Find the length of the radius/diameter.**

The radius of a circle is the length of the line segment from the centre of the circle to the circumference.

Here the radius = 6cm

2**Find the size of the angle creating the arc of the sector.**

Angle = 90° . *Shown by the symbol of the right angle*.

3**Substitute the value of the radius/diameter and the angle into the formula for the arc length.**

As you know the radius you can use the formula which has ‘r’ as a variable.

\[\begin{aligned}
& \text {Arc length} = \frac{\theta}{360} \times 2\times\pi \times r\\
& =\frac{90}{360} \times 2\times\pi \times 6\\
& = 3\pi
\end{aligned}\]

4**Clearly state your answer**.

The question asked you to round your answer to 3 decimal places:

\[\begin{aligned}
& \text {Arc length} = 3\pi cm \\
& = 9.42477796…cm\\
& =9.425cm (3 d.p.)
\end{aligned}\]

*Remember the arc length (length of a curve on the circumference) is a measure of distance and, therefore, the units are **not **squared.*

Calculate the arc length of the semicircle shown below. Give your answer in terms of 𝜋.

**Find the length of the radius/diameter.**

Diameter = 24cm

**Find the size of the angle creating the arc of the sector.**

Angle = 180° . *This is because the shape shown is a semicircle. Therefore, the angle of the straight line is 180 degrees*.

**Substitute the value of the radius/diameter and the angle into the formula for the arc length.**

As you know the radius you can use the formula which has ‘d’ as a variable.

\[\begin{aligned}
&\text {Arc length} = \frac{\theta}{360} \times \pi\times d\\
&=\frac{180}{360} \times \pi\times 24\\
&=12\pi
\end{aligned}\]

**Clearly state your answer.**

The question asked you to round your answer in terms of pi:

Arc length = 12\pi cm

*Remember the arc length (length of the curve on a circumference) is a measure of distance and, therefore, the units are **not **squared.*

Calculate the arc length of the sector shown below. Give your answer to 3 significant figures.

**Find the length of the radius/diameter.**

Radius = 8cm

**Find the size of the angle creating the sector**.

Angle = 115°

**Substitute the value of the radius/diameter and the angle into the formula for the arc length.**

As you know the radius you can use the formula which has ‘r’ as a variable.

\[\begin{aligned}
&\text{ Arc length} = \frac{\theta}{360} \times 2\times\pi \times r\\
&=\frac{115}{360} \times 2\times\pi \times 8\\
&=\frac{46}{9} \pi\\
\end{aligned}\]

**Clearly state your answer.**

The question asked you to round your answer to 3 significant figures:

\[\begin{aligned}
&\text {Arc length} = \frac{46}{9}\pi\\
& =16.0570…cm \\
&=16.1cm (3 s.f.)
\end{aligned}\]

Calculate the arc length of the sector AOB below.

The length of the radius (OB) is 9cm

The length of a chord (AB) is 10cm .

Give your answer to 2 decimal places.

** Find the length of the radius.**

Radius = 9cm

**Find the size of the angle creating the sector. **

In this example you are not given the angle of the sector, you need to calculate it first. Here you can use the triangle created by the two radii and the chord to find the angle:

In this example, you need to apply the **cosine rule** to find the angle.

a^2=b^2+c^2-2bcCos(A)

A is the angle you are trying to find. You can therefore use the rearranged cosine rule to find the angle.

\[\begin{aligned}
\operatorname{Cos} A&=\frac{b^{2}+c^{2}-a^{2}}{2 b c} \\
\operatorname{Cos} A&=\frac{9^{2}+9^{2}-10^{2}}{2 \times 9 \times 9} \\
\operatorname{Cos} A&=\frac{31}{81} \\
A&=\operatorname{Cos}^{-1}\left(\frac{31}{81}\right) \\
A&=67.497977…^{\circ}
\end{aligned}\]

The size of the angle creating the sector (made by the two radii) is 67.498° .

**Substitute the value of the radius/diameter and the angle into the formula for the arc length. **

As you know the radius you can use the formula which has ‘r’ as a variable.

\[\begin{aligned}
&\text {Arc length} = \frac{\theta}{360} \times 2\times\pi \times r\\
&=\frac{67.498}{360} \times 2\times\pi \times 9\\
&=10.60236
\end{aligned}\]

**Clearly state your answer**.

The question asked you to round your answer to 2 decimal places:

\[\begin{aligned}
&\text {Arc length} =10.60236…cm\\
&=10.60cm (2 d.p.)
\end{aligned}\]

Sometimes you may be given the arc length of the sector and asked to find a property of the circle such as the radius.

In this case you need to ‘reverse’ the process.

**Clearly state which of the properties you know and do not know (e.g. radius, angle of sector, arc length of sector)****Using the formula for the arc length create an equation and solve for the unknown property you have been asked to find**.**Clearly state your answer**.

The sector below has an arc length of 20cm and an angle of 125°.

Calculate the length of x.

Give you answer to 2 decimal places.

**Clearly state which of the properties you know and do not know (e.g. radius, angle of sector, arc length of sector)**.

Radius = x

Angle of sector = 25°

Arc length = 20cm

**Using the formula for the arc length create an equation and solve for the unknown property you have been asked to find**.

You are trying to find the radius so use the formula with ‘r’ as the variable

\[\begin{aligned}
\text { Arc length }&=\frac{\theta}{360} \times 2 \times \boldsymbol{\pi} \times r \\
20&=\frac{125}{360} \times 2 \times \boldsymbol{\pi} \times x \quad \quad \quad \text {simply the fraction (if possible)} \\
20&=\frac{25}{36} \times \boldsymbol{\pi} \times x \quad \quad \quad \text {divide each side of the equation by the fractio} \\
\frac{144}{5}&=\boldsymbol{\pi} \times x \quad \quad \quad \text {divide each side of the equation by pi} \\
9.16732…=x
\end{aligned}\]

**Clearly state your answer**.

The question asks you to give your answer to 2 decimal places:

\[\begin{aligned}
&x=9.16732…\\
&=9.17 (2d.p.)
\end{aligned}\]

The sector below has an arc length of 62cm and a radius of 18.5.

Calculate the length of x.

Give you answer to 2 decimal places.

**Clearly state which of the properties you know and do not know (e.g. radius, angle of sector, arc length of sector)**.

Radius = 18.5

Angle of sector = x°

Arc length = 62cm

**Using the formula for the arc length create an equation and solve for the unknown property you have been asked to find**.

You are trying to find the radius so use the formula with ‘r’ as the variable

\[\begin{aligned}
\text { Arc length }&=\frac{\theta}{360} \times 2 \times \boldsymbol{\pi} \times r \\
62&=\frac{x}{360} \times 2 \times \boldsymbol{\pi} \times 18.5 \\
62&=\frac{x}{360} \times 37 \times \boldsymbol{\pi} \\
\frac{62}{37}&=\frac{x}{360} \times \boldsymbol{\pi} \\
0.533384 \ldots&=\frac{x}{360} \\
192.018 \ldots&=x
\end{aligned}\]

**Clearly state your answer**.

The question asks you to give your answer to 2 decimal places:

\[\begin{aligned}
&x=192.018…\\
&=192.02 (2d.p.)
\end{aligned}\]

**Finding the length of the circumference not the length of the arc**

Remember to find the fraction of the circle that makes the arc not just the circumference of the whole circle.

E.g.

Use

\frac{\theta}{360} \times \pi\times d

Or

\frac{\theta}{360} \times 2\times\pi \times r

Not

\pi\times d

Nor

2\times\pi \times r**Incorrect use of the cosine rule**

Many mistakes are made when applying other rules within an arc question (e.g. the cosine rule). Take your time and regularly ask if your answer makes sense within the context of the question.

Have a look at our cosine rule lesson for more practice.

**Incorrect Units**

Remember the arc is a length and therefore the units will not be squared.

1. The circumference of a circle is 24cm . A sector within the same circle creates an arc of 6cm . What is the angle of the sector?

90^{\circ}

180^{\circ}

270^{\circ}

360^{\circ}

\begin {aligned}
\frac{arc length}{circumference}=\frac{6cm}{24cm} \\=\frac{1}{4}
\end{aligned}

\frac{1}{4} of the circumference

Therefore, it is a quarter of the circle, so the angle is 90^{\circ}

2. Is the arc in question 1 a minor or major arc?

Minor arc

Major arc

The arc length is less than half the circumference. Therefore, it is a minor arc.

3. Calculate the arc length of this sector, in terms of pi:

5\pi cm

10\pi cm

5\pi cm^{2}

25\pi cm^{2}

\begin{aligned}
&\text {Arc length} = \frac{\theta}{360} \times 2\times\pi \times r\\
&=\frac{90}{360} \times 2\times\pi \times 10\\
&=5\pi
\end{aligned}

4. Calculate the arc length of this semi circle in terms of pi:

31.4 cm

10\pi cm

10\pi cm^{2}

20\pi cm^{2}

\begin{aligned}
&\text {Arc length} = \frac{\theta}{360} \times 2\times\pi \times r\\
&=\frac{180}{360} \times\pi \times 20\\
&=10\pi
\end{aligned}

5. Calculate the arc length of this sector in terms of pi:

75.4 cm

48\pi cm^{2}

24\pi cm

32\pi cm

\begin{aligned}
&\text {Arc length} = \frac{\theta}{360} \times 2\times\pi \times r\\
&=\frac{270}{360} \times 2\times\pi \times 16\\
&=24\pi
\end{aligned}

6. Calculate the arc length of this sector in terms of pi:

22.0 cm

8\pi cm

7\pi cm^{2}

7\pi cm

\begin{aligned}
&\text {Arc length} = \frac{\theta}{360} \times 2\times\pi \times r\\
&=\frac{315}{360} \times 2\times\pi \times 4\\
&=7\pi
\end{aligned}

1. The diagram shows a sector of a circle with centre O .

The radius of the circle is 13cm .

The angle of the sector is 150^{\circ}

Calculate the arc length, give your answer correct to 3 significant figures.

**(3 marks)**

Show answer

\frac{150}{360} \times 2\times\pi \times 13

**(1)**

34.0339

**(1)**

34.0

**(1)**

2. The diagram shows a sector of a circle with centre O .

The radius of the circle is 6.5cm .

The acute angle AOB is 70^{\circ} .

Calculate the arc length sector, give your answer correct to 3 significant figures.

**(3 marks)**

Show answer

\frac{290}{360} \times 2\times\pi \times 6.5

**(1)**

32.899

**(1)**

32.9

**(1)**

3. The diagram shows a sector of a circle with centre O .

The radius of the circle is 4.9cm .

The acute angle AOB is 60^{\circ} .

Calculate the arc length sector, give your answer correct to 2 decimal places.

Show answer

\frac{60}{360} \times 2\times\pi \times 4.9

**(1)**

5.1312…

**(1)**

5.13

**(1)**

4. Below is a sector of a circle with an arc length of 6\pi cm and a radius of 10cm . Find the size of the angle labelled x .

**(3 marks)**

Show answer

Correct attempt to form an equation for the arc length

6\pi=\frac{x}{360} \times 2 \times {\pi} \times 10

**(1)**

Attempt to solve equation for x , with one step completed correctly

\begin{aligned}
6&=\frac{x}{360} \times 20 \\
0.3&=\frac{x}{360}
\end{aligned}

**(1)**

108

**(1)**

5. The sector below has an arc length of 30cm .

Calculate the length of x .

Give you answer to 2 decimal places.

**(4 marks)**

Show answer

Correct attempt to form an equation for the arc length

30=\frac{135}{360} \times 2 \times {\pi} \times x

**(1)**

Attempt to solve equation for x , with one step completed correctly

\begin{aligned}
80&=2 \times \pi \times x \\
40&=\pi \times x
\end{aligned}

**(1)**

12.732…

**(1)**

12.73

**(1)**

You have now learned how to:

- Identify and apply circle definitions and properties, including: centre, radius, chord, diameter, circumference
- Identify and apply circle definitions and properties, including tangent, arc, sector and segment
- Calculate the length of an arc
- Calculate a property of a circle given the length of an arc

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