One to one maths interventions built for KS4 success

Weekly online one to one GCSE maths revision lessons now available

In order to access this I need to be confident with:

Multiplying fractions Substitution Perimeter Area RoundingThis topic is relevant for:

Here we will learn about the volume of a cone, including how to calculate the volume of a cone given its radius and perpendicular height and how to calculate a missing length within a cone, given its volume.

There are also cone worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

The **volume of a cone** is the amount of space inside a cone.

The volume of a cone is **one third** of the volume of a cylinder.

The volume of a cone can be calculated using a formula.

To do this, we substitute two of the dimensions of the cone into the volume formula and evaluate the result.

The **volume formula** for any cone is

\text{Volume}=\frac{1}{3} \pi r^2 h

where r ** **is the** radius **of the** base of the cone** and h is the** perpendicular height of the cone**.

Find the volume of this cone where the radius of the base of the cone is 5cm and the perpendicular height of the cone is 8cm .

We need to find the area of the base of a cone using A=\pi r^{2} (the area of a circle).

We then multiply it by the vertical height h , and find one third of the answer.

\[\text{Volume}=\frac{1}{3} \pi r^2 h\\
= \frac{1}{3} \times \pi \times 5^2 \times 8\\
=\frac{200}{3}\pi\\
=209.4 \ cm^3 \ \text{(1 dp)}\]

A **cone **is a three dimensional object with a circular base that tapers to a point (a vertex). This vertex is also known as the **apex**.

If the apex is directly above the centre of the base, the cone is referred to as a **right circular cone**. If the apex is not above the centre of the base, this is referred to as an **oblique cone**.

Note: The **slant height** of the cone *l** *is not needed to calculate the volume of a cone, but it is used to calculate the **surface area** of a cone.

**Step-by-step guide:** __Surface area of a cone __(coming soon)

The volume of a cone stays the same if the apex moves parallel to the base but the surface area of the cone changes. This is because the slant heights are not equal for an oblique cone.

In order to calculate the volume of a cone:

**Write down the formula,**\text{volume}=\frac{1}{3} \pi r^2 h .**Substitute the given values.****Work out the calculation.****Write the final answer, including the units.**

Get your free volume of a cone worksheet of 20+ questions and answers. Includes reasoning and applied questions.

COMING SOONGet your free volume of a cone worksheet of 20+ questions and answers. Includes reasoning and applied questions.

COMING SOONFind the volume of the cone with radius 4cm and perpendicular height 7cm .

Give your answer to 3 significant figures.

**Write down the formula,**\text{volume}=\frac{1}{3} \pi r^2 h .

The formula for the volume of a cone is V=\frac{1}{3} \pi r^2 h .

2**Substitute the given values.**

We need to substitute the value of the radius r and the perpendicular height h into the formula.

V= \frac{1}{3}\times\pi\times{4^2}\times{7}3**Work out the calculation.**

Use a calculator to work out the volume.

V=\frac{112}{3}\pi = 117.286…4**Write the final answer, including the units.**

Check what form the final answer needs to be. Here we are asked to give the answer to 3 significant figures.

V=117.286…=117 cm^3 (3sf)The volume of the cone is 117cm^3 (3sf) .

Find the volume of the cone with radius 2.1cm and perpendicular height 4.3cm .

Give your answer to 3 significant figures.

**Write down the formula, \text{volume}=\frac{1}{3} \pi r^2 h .**

The volume formula of a cone is V=\frac{1}{3} \pi r^2 h .

**Substitute the given values.**

We need to substitute the value of the radius r and the perpendicular height h into the formula.

V= \frac{1}{3} \times \pi \times 2.1^2 \times 4.3**Work out the calculation.**

Use a calculator to work out the volume.

V= 19.8580…**Write the final answer, including the units.**

Check what form the final answer needs to be. Here we are asked to give the answer to 3 significant figures.

V=19.8580…=19.9 cm^3 (3sf)The volume of the cone is 19.9 cm^3 (3sf) .

Calculate the volume of a cone with radius 3cm and perpendicular height 5cm .

Write your answer in terms of \pi .

**Write down the formula, \text{volume}=\frac{1}{3} \pi r^2 h .**

The formula for the volume of a cone is V=\frac{1}{3} \pi r^2 h .

**Substitute the given values.**

We need to substitute the value of the radius r and the perpendicular height h into the formula.

V= \frac{1}{3} \times \pi \times 3^2 \times 5**Work out the calculation.**

As we can change the order of a multiplication and the solution stays the same, we have V=\frac{1}{3}\times\pi\times{3^{2}}\times{5}=\frac{1}{3}\times{3^{2}}\times{5}\times{\pi} .

Simplifying this, we get V=15\pi .

**Write the final answer, including the units.**

Check what form the final answer needs to be. Here we need to leave the answer in terms of \pi .

V=15\pi\text{cm}^3The volume of the cone is 15\pi cm^3 .

Find the volume of the cone with the diameter of 4cm and perpendicular height 6cm .

Write your answer in terms of \pi .

**Write down the formula, \text{volume}=\frac{1}{3} \pi r^2 h .**

The formula for the volume of a cone is V=\frac{1}{3} \pi r^2 h .

**Substitute the given values.**

As the diameter is twice the length of the radius, the radius is equal to 4\div2=2cm .

Now we can substitute the values of r and h into the formula to get V= \frac{1}{3} \times \pi \times 2^2 \times 6\ .

**Work out the calculation.**

As we can change the order of a multiplication and the solution stays the same, we have V=\frac{1}{3}\times\pi\times{2^{2}}\times{6}=\frac{1}{3}\times{2^{2}}\times{6}\times{\pi} .

Simplifying this, we get V= 8\pi .

**Write the final answer, including the units.**

Check what form the final answer needs to be. Here we are asked to leave the answer in terms of \pi .

V=8\pi\text{cm}^3The volume of the cone is 8\pi cm^3 .

A cone has a volume of 500cm^3 and a radius of 5cm . Calculate the perpendicular height of the cone, correct to 1 decimal place.

**Write down the formula, \text{volume}=\frac{1}{3} \pi r^2 h .**

The volume formula of a cone is V=\frac{1}{3} \pi r^2 h .

**Substitute the given values.**

We are given the volume and the radius, so we can substitute these into the formula.

500=\frac{1}{3} \times \pi \times 5^2 \times hAs 5^2=25 , we have 500=\frac{1}{3} \times \pi \times{25}\times h .

**Work out the calculation.**

We need to solve the equation for h ,

**Write the final answer, including the units.**

Check what form the final answer needs to be. Here we are asked to give the answer to 1 decimal place.

h = \frac{60}{\pi} = 19.1\text{cm\quad(1dp)}The perpendicular height of the cone is 19.1 cm (1dp).

A cone has a volume of 800cm^3 and a perpendicular height of 15cm . Calculate the radius of the cone. Give your answer to 2 decimal places.

**Write down the formula, \text{volume}=\frac{1}{3} \pi r^2 h .**

The question involves the volume of a cone, so we need the formula for the volume of a cone.

V=\frac{1}{3} \pi r^2 h**Substitute the given values.**

We are given the volume and the perpendicular height, so we can substitute these into the formula.

800=\frac{1}{3} \times \pi \times r^2 \times 15**Work out the calculation.**

As \frac{1}{3} \times15=5 , we can simplify the right hand side of the equation, before we find the value of r .

We now have r^2={\frac{160}{\pi}} . To find the value of r , we must square root both sides of the equation. By doing this we get r=\sqrt{\frac{160}{\pi}}=7.136…

**Write the final answer, including the units.**

Check what form the final answer needs to be. Here we are asked to give the answer to 2 decimal places.

r=7.136…=7.14 cm (2dp)The radius of the cone is 7.14cm (2dp) .

**Using the correct formula**

There are several formulas that can be used, so we need to match the correct formula to the correct context.

**Rounding**

It is important to not round the answer until the end of the calculation. This will mean your final answer is accurate.

**Using the radius or the diameter**

It is a common error to mix up radius and diameter. Remember the radius is half of the diameter.

**Make sure you have the correct units**- For area we use square units such as cm^2 .
- For volume we use cube units such as cm^3 .

1. Find the volume of a cone of radius 7.3cm and perpendicular height 9.7cm . Give your answer to 3 significant figures.

541 cm^3

542 cm^3

719 cm^3

718 cm^3

Substitute the values of r and h into the formula.

V=\frac{1}{3}\pi r^2 h

V=\frac{1}{3}\times \pi \times 7.3^2\times 9.7

V=541.310…

V=541 \ cm^3 \ \text{(3sf)}

2. Find the volume of a cone of radius 8.6cm and perpendicular height 7.9cm . Write your answer to 3 significant figures.

562 cm^3

563 cm^3

611 cm^3

612 cm^3

Substitute the values of r and h into the formula.

V=\frac{1}{3}\pi r^2 h

V=\frac{1}{3}\times \pi \times 8.6^2 \times 7.9

V=611.860…

V=612 \ cm^3 \ \text{(3sf)}

3. Calculate the volume of a cone with the radius 6cm and the perpendicular height 7cm . Write your answer in terms of \pi .

42\pi cm^3

84\pi cm^3

126\pi cm^3

252\pi cm^3

We are finding the volume of a cone so we substitute the values of r and h into the formula.

V=\frac{1}{3}\pi r^2 h\\

V=\frac{1}{3}\times \pi \times 6^2 \times 7\\

V=84\pi\\

V=84\pi \ cm^{3}

4. A cone has a diameter of 8cm and a perpendicular height of 6cm . Calculate the volume of the cone in terms of \pi .

12\pi cm^3

32\pi cm^3

48\pi cm^3

96\pi cm^3

Calculate the value of the radius by dividing the diameter by 2 , then substitute the values of r and h into the formula and solve.

r=8 \div 2= 4cm

V=\frac{1}{3} \pi r^2 h

V=\frac{1}{3}\times \pi \times 4^2 \times 6

V=32\pi

V=32\pi \ cm^3

5. A cone has a volume of 400cm^3 . The radius of the base is equal to 6cm . Calculate the perpendicular height of the cone to 1 decimal place.

3.5 cm

8.2 cm

10.6 cm

11.1 cm

Substitute the volume and the radius into the volume formula and then rearrange to find the perpendicular height, h .

V=\frac{1}{3} \pi r^2 h

400=\frac{1}{3}\times \pi \times 6^2 \times h

1200=\pi \times 36 \times h

\frac{1200}{\pi \times 36}=h

h=10.610…

h=10.6 \ cm \ \text{(1dp)}

6. The volume of a cone is 700 cm^3 . The perpendicular height of the cone is 8cm . Calculate the radius of the cone to 2 decimal places.

5.40 cm

5.72 cm

9.14 cm

9.28 cm

Substitute the values of the volume and the perpendicular height into the formula, and rearrange to find the radius r .

V=\frac{1}{3} \pi r^2 h

700=\frac{1}{3}\times \pi \times r^2 \times 8

2100=\pi \times r^2 \times 8

\frac{1200}{\pi \times 8}=r^2

r=\sqrt{\frac{2100}{\pi \times 8}}

r=9.1409…

r=9.14 \ cm \ \text{(to 2 dp)}

\text{Volume of a cone}=\frac{1}{3} \pi r^2 h

1. Below is a cone with radius 4.1 cm and perpendicular height 5.8 cm .

Calculate the volume of the cone.

Give your answer to 3 significant figures.

**(2 marks)**

Show answer

V=\frac{1}{3} \times \pi \times 4.1^2 \times 5.8

**(1)**

**(1)**

2. Use the information in the diagram below to calculate the volume of the 3D shape.

Write your answer in terms of \pi .

**(2 marks)**

Show answer

V=\frac{1}{3} \times \pi \times 8^2 \times 12

**(1)**

**(1)**

3. A container is a cone of radius 30 cm and perpendicular height 50 cm .

Water fills the container at a rate of 3000 cm^3 per minute.

How long does it take to fill the container?

Give your answer to the nearest minute.

**(4 marks)**

Show answer

\frac{1}{3} \times \pi \times 30^2 \times 50

**(1)**

**(1)**

**(1)**

15.707… = 16 minutes

**(1)**

You have now learned how to:

- Calculate the volume of a cone

Prepare your KS4 students for maths GCSEs success with Third Space Learning. Weekly online one to one GCSE maths revision lessons delivered by expert maths tutors.

Find out more about our GCSE maths revision programme.

x
#### FREE GCSE maths practice papers (Edexcel, AQA & OCR)

Download free

8 sets of free exam practice papers written by maths teachers and examiners for Edexcel, AQA and OCR.

Each set of exam papers contains the three papers that your students will expect to find in their GCSE mathematics exam.