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Angles in polygons Types of quadrilaterals Parallel linesThis topic is relevant for:
Here we will learn about polygons, including regular polygons, angles in polygons, and complex polygons.
There are also polygons worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if youβre still stuck.
An irregular polygon is a 2D shape that has straight sides that are not equal to each other and angles that are not equal to each other. You need to be able to classify geometric shapes based on their properties and sizes and find unknown angles in any polygon. To do this, we need to look closely at the properties of these shapes.
E.g.
Trapezium | Irregular Pentagon | Irregular dodecagon |
To do this, we need to look closely at the properties of these shapes.
Polygon | Number of sides | Image (irregular polygon) |
Scalene triangle | 3 | |
Irregular quadrilateral | 4 | |
Irregular pentagon | 5 | |
Irregular hexagon | 6 | |
Irregular heptagon | 7 | |
Irregular octagon | 8 | |
Irregular nonagon | 9 | |
Irregular decagon | 10 | |
Irregular hendecagon | 11 | |
Irregular dodecagon | 12 |
Sum of interior angles = (n-2) Γ 180^{\circ}
where n represents the number of sides.
As the size of each angle is not equal, we can determine the size of each angle by adding together the interior angles that we know and putting it equal to the sum of the interior angles, then solving the equation.
Sum of exterior angles of a polygon = 360Β°
We can use this property to find either the interior angle, or exterior angle at a vertex.
As the size of each angle is not equal, we can determine the size of an exterior angle by adding together the exterior angles that we know and subtracting it from 360Β° .
A convex polygon is a polygon with all the interior angles less than 180Β° . A concave polygon has at least one angle that is greater than 180Β° (or a reflex angle).
E.g.
Convex hexagon | Concave hexagon |
All interior angles are either acute or obtuse. | At least one angle is greater than 180Β° |
In order to classify an irregular polygon:
Get your free Irregular polygons worksheet of 20+ questions and answers. Includes reasoning and applied questions.
DOWNLOAD FREEGet your free Irregular polygons worksheet of 20+ questions and answers. Includes reasoning and applied questions.
DOWNLOAD FREEIrregular polygon is part of our series of lessons to support revision on polygons. You may find it helpful to start with the main polygons lesson for a summary of what to expect, or use the step by step guides below for further detail on individual topics. Other lessons in this series include:
Given that ABC is an isosceles triangle and BCD is a straight line, classify the polygon ABD .
ABC has 3 sides and so it is a triangle.
2Determine the size of the angles and/or side lengths within the polygon.
As BCA = 116Β° , angle ACD = 180 - 116 = 64Β° .
As ABC is an isosceles triangle, ABC = BAC = (180 - 116)\div 2 = 32Β° .
As angles in a triangle total 180Β° , angle CAD = 180 - (74 + 64) =Β 42Β° .
Angle BAD = 42 + 32 = 74Β° .
3Recognise the other properties of the polygon.
As the three angles in the triangle ABC are 74Β°, 74Β° and 32Β° . The triangle ABD has two equal angles and so it is isosceles.
The polygon is an isosceles triangle, which is an irregular polygon.
Classify the following polygon:
State/calculate the number of sides of the polygon.
The polygon has 4 sides so this is a type of quadrilateral.
Determine the size of the angles and/or side lengths within the polygon.
Angle ACD is alternate to angle BAC and so angle ACD = 48Β° .
The angle COD = 180 - (41 + 48) = 91Β° .
Recognise the other properties of the polygon.
As the angle at the centre is not equal to 90 degrees and the four sides are two pairs of parallel lines, the polygon ABCD is a parallelogram, which is an irregular quadrilateral.
The polygon below is a quadrilateral. By using angle properties, determine the type of quadrilateral.
State/calculate the number of sides of the polygon.
It is stated in the question that we have a quadrilateral.
Determine the size of the angles and/or side lengths within the polygon.
We do not have any angles to use to classify this polygon. This in turn discounts many quadrilaterals that have specific angle properties. We can however use the information provided to find the length of AD .
As the vertical height is perpendicular to the base, we can use Pythagorasβ Theorem to calculate the length of AD .
3^{2}+4^{2}=AD^{2}
9+16=AD^{2}
AD^{2}=25
AD=5cm
Recognise the other properties of the polygon.
As AD does not equal BC but AB and CD are parallel, the quadrilateral is a trapezium (which is an irregular polygon).
A pentagon is constructed by joining an isosceles triangle with a rectangle. The line AM is a line of symmetry. Show that the polygon is irregular.
State/calculate the number of sides of the polygon.
The pentagon has 5 sides.
Determine the size of the angles and/or side lengths within the polygon.
As angles in a triangle total 180Β° , angle AEB = 180 - (90+53) = 37Β° .
As BCDE is a rectangle, angle BED = 90Β° and so angle AED = 90 + 37 = 127Β° .
As the polygon is symmetrical, angle BAE = 53 Γ 2 = 106Β° .
Recognise the other properties of the polygon.
The interior angles of the polygon are equal to 106Β°, 120Β°, 90Β°, 106Β° and 120Β° so, as the angles are not the same, the pentagon is irregular.
Below is a description of a polygon. From the description, determine the classification of the polygon.
The polygon has 10 edges.
The polygon has a rotational symmetry of order 5 .
The interior angles are equal to 42Β° or 246Β° .
The polygon can be constructed from 5 congruent kites.
State/calculate the number of sides of the polygon.
As the polygon has 10 edges, this polygon is a type of decagon.
Determine the size of the angles and/or side lengths within the polygon.
As the polygon can be constructed from 5 congruent kites, each side length of the decagon is the same. As the polygon has a rotational symmetry of order 5 and the interior angles are 42Β° or 246Β° , the polygon looks like a five pointed star.
Recognise the other properties of the polygon.
As the angles in the polygon are not equal, the shape is an irregular decagon.
The interior angles of a polygon are: 4x+16, 6x+8 and 2x+12 . Classify the polygon.
State/calculate the number of sides of the polygon.
As there are 3 interior angles, the polygon is a type of triangle.
Determine the size of the angles and/or side lengths within the polygon.
As the sum of angles in a triangle total 180Β°
4x+16+6x+8+2x+12=180
12x+36=180
12x=144
x=12
As x=12
4x+15=4\times 12+16=64Β°
6x+8=6\times 12+8=80Β°
2x+12=2\times 12+12=36Β°
Recognise the other properties of the polygon.
As all the angels in the polygon are different, the triangle is a scalene triangle (an irregular polygon).
Make sure you know your angle properties. Getting these confused causes quite a few misconceptions.
There are many quadrilaterals and it is common to confuse the properties, especially for a rhombus, parallelogram, or trapezium.
As well as this, stating that the polygon is a quadrilateral is not enough information for a classification.
Assuming a triangle is isosceles or equilateral can have an impact on the size of angles within the rest of the polygon, so make sure you can explain why you have chosen a specific type of triangle.
As well as this, stating that the polygon is a triangle is not enough information for a classification. You must state whether it is isosceles/ equilateral etc.
1. BD is parallel to AE in the triangle ACE . Classify the polygon BCD
Equilateral triangle
Right Angle triangle
Isosceles triangle
Scalene triangle
The angle BDC = 180 – 127 = 53^{\circ} (angles on a straight line total 180^{\circ} ).
Angle CBD = 180 – (65 + 53) = 62^{\circ} (angles in a triangle total 180^{\circ} ).
All angles of BCD are different.
2. A quadrilateral is inscribed in a circle with centre O . The diagonals meet perpendicularly at the point E where AC = 2AE . Use circle theorems to determine the classification of the quadrilateral ABCD .
Diamond
Arrowhead
Isosceles triangle
Kite
As AC = 2AE , and BD is perpendicular to AC , triangles ABC and ADC are isosceles triangles. This means that the two angles at A and C are equal and the side lengths AB and BC , and AD and CD are equal. This is a kite.
3. The polygon below has an order of rotational symmetry of 4 . Classify the polygon.
Octagon
Quadrilateral
Regular octagon
Regular pentagon
As the order of rotational symmetry is 4 , the angles at A, C, E and G are all equal to 40^{\circ} , and the angles at B, D, F, and H are equal to 360 – 130 = 230^{\circ} . The polygon has 8 sides but the interior angles are not equal.
4. 6 congruent triangles are joined together to form a 6 sided polygon. Each line segment within the polygon is the same length. The new polygon has two acute angles, 3 obtuse angles and one reflex angle. The polygon has one line of symmetry and no rotational symmetry. Classify the polygon.
Arrowhead
Regular hexagon
Hexagon
Parallelogram
As the polygon has 6 sides and different interior angles, the polygon is a hexagon.
5. The polygon below is incomplete. Given that the polygon is made up of 10 congruent kites, classify the polygon.
Regular decagon
Regular dodecagon
Regular icosagon
Regular octagon
As the polygon is made of 10 congruent kites, each side length is the same and the interior angles are also equal due to the kite also being symmetrical.
6. The interior angles of a polygon are: 12x-30, 8x+40, 7x+30, 8x, and 5x+20 . The sum of the angles is equal to 540^{\circ} . Classify the polygon.
Pentagon
Hexagon
Regular pentagon
Regular hexagon
As x=12\\ 12x-30=12\times12-30=114^{\circ}\\ 8x+40=8\times12+40=136^{\circ}\\ 7x+30=7\times12+30=114^{\circ}\\ 8x=8\times12=96^{\circ}\\ 5x+20=5\times12+20=80^{\circ}
The internal angles are not equal and so the polygon is a pentagon.
1. (a) An isosceles trapezium is made when you join two triangles together along an edge with the same length. ABC is an isosceles triangle. Work out the size of the angle ACD .
(b) What type of triangle is ACD ?
(5 marks)
(a)
BCA = (180 – 116)\div2 = 32^{\circ}
(1)
CAD = 116 – 32 = 84^{\circ}(1)
ADC = 180 – 116 = 64^{\circ}(1)
ACD = 180 – (84+64) = 32^{\circ}(1)
(b)
Scalene
(1)
2. (a) Show that the triangle is a right angle triangle.
(b)The area of both polygons are equal. Calculate the length x .
(5 marks)
(a)
5^{2}+12^{2}=25+144=169
(1)
\sqrt{169}=13(1)
The sum of the square of the two shorter sides is equal to the square of the hypotenuse so the triangle contains a right angle
(1)
(b)
Triangle area = 5\times12\div2=30cm^{2}
(1)
30\div6=x\\ x=5cm(1)
3. (a) The polygon ABC is half of a kite where AC is the longest length of the kite. Write an expression for the area of the kite.
(b) Given that the area of the smaller triangle ABO = 40cm^{2} , calculate the area of the kite.
(c) Calculate the size of angle OAB .
(5 marks)
(a)
8x^{2}
(1)
(b)
x^{2}=40
(1)
8x^{2}=320cm^{2}(1)
(c)
OAB=tan^{-1}(\frac{2x}{x})
(1)
OAB = 63.4^{\circ}(1)
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