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Lines of symmetry Rotational symmetry Types of angles Angles on a straight line Angles in a triangle How to work out perimeterThis topic is relevant for:

Here we will learn about triangles, including what a triangle is and how to solve problems involving their sides and their angles.

There are also triangles worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

**Triangles **are 2D shapes with three straight sides and three vertices. These are the only two key properties of triangles.

To solve problems involving triangles, we need to be able to gather information about its side lengths and/or its interior angles and apply these to the problem.

The **sum of interior angles of a triangle is ** \bf{180°}.

For example,

29^{\circ}+68^{\circ}+83^{\circ}=180^{\circ}.If a triangle’s angles are all acute angles (less than 90^{\circ} ), it is sometimes known as an **acute triangle.**

If a given triangle has one **obtuse angle** it is sometimes known as an **obtuse triangle**.

**Step-by-step guide:** Angles in a triangle

There are different types of triangles that have different properties.

Being able to recognise different types of triangles is known as **classifying triangles**.

**Step-by-step guide:** Types of triangles

An **equilateral triangle** has the following properties,

- All sides are equal length.
- All angles are equal size (60^{\circ}) .

An equilateral triangle has 3 **lines of symmetry**. The lines go from one vertex to the middle of the opposite side.

The lines of symmetry are angle **bisectors of the vertices** and are also **perpendicular bisectors of the sides** of the equilateral triangle.

**Step-by-step guide:** Equilateral triangles (coming soon)

An **isosceles triangle** has the following properties,

- Two sides are equal length.
- Two equal angles.

The two equal angles are called **base angles** and they are opposite the sides of equal length. The unequal side is known as the **base** and is opposite the unequal angle.

**Step-by-step guide:** Isosceles triangles (coming soon)

A **scalene triangle** has the following properties,

- No equal sides.
- No equal angles.

**Step-by-step guide:** Scalene triangles (coming soon)

A **right-angled triangle** has the following property,

- One right angle.

The longest side of a right-angled triangle is opposite the right-angle. It is called the **hypotenuse**.

The **Pythagorean theorem** is used to determine missing side lengths of a right-angled triangle. If a question involves both the sides of the triangle and one of the angles, we could use **trigonometry**.

A special case of a right-angled triangle is a right-angled triangle which also has two equal sides. It can be known as an **isosceles right triangle** or an **isosceles right-angled triangle**. The two equal angles will both be 45^{\circ}.

**Step-by-step guide:** Right-angled triangles (coming soon)

The area of a triangle can be found by using the formula,

A=\frac{1}{2}bh ,

where b is the **base length** and h is the **perpendicular height** of the triangle.

Sometimes these values need to be calculated.

The area of a triangle is given in **square units**.

**Step-by-step guide:** Area of a triangle

It is impossible for a triangle to contain more than one obtuse angle as the sum of angles in a triangle is 180^{\circ}.

For example,

- A triangle contains the three angles 98^{\circ}, \ 91^{\circ} and 5^{\circ}.

This gives us the angle sum of 98+91+5=194^{\circ} and so as angles in a triangle always total 180^{\circ}. This is an impossible triangle.

- A triangle contains two right angles, and a third angle x^{\circ}.

The sum of angles in the triangle is therefore 90+90+x=(180+x)^{\circ}.

The value of x must equal 0 for the angles to add to 180^{\circ} and so this is another impossible triangle.

In order to solve problems involving triangles:

**Locate known angles and calculate any necessary unknown angles.****Locate known sides and calculate any necessary unknown side lengths.****Solve the problem using any necessary values.**

Get your free triangles worksheet of 20+ questions and answers. Includes reasoning and applied questions.

COMING SOONGet your free triangles worksheet of 20+ questions and answers. Includes reasoning and applied questions.

COMING SOONFind angle x.

**Locate known angles and calculate any necessary unknown angles.**

This problem involves the internal angles of a triangle. The sum of interior angles of a triangle is 180^{\circ}. One angle is given.

As two sides have a dash through them indicating they are the same length, the triangle is isosceles and so the triangle contains the two base angles 63^{\circ} and 63^{\circ}.

2**Locate known sides and calculate any necessary unknown side lengths.**

As we need to determine the size of angle x and we have information about the other two angles, we can use these to find the missing angle. We do not need to calculate any length of the triangle.

3**Solve the problem using any necessary values.**

Using the two known angles and the angle fact that the sum of angles in a triangle is 180^{\circ},

180-(2\times 63)=54.Therefore angle x=54^{\circ}.

Determine the size of angle x.

**Locate known angles and calculate any necessary unknown angles.**

This problem involves the interior and exterior angles of a triangle. The sum of interior angles of a triangle is 180^{\circ}. One of the angles in the triangle is a right-angle which is 90^{\circ}.

As the sum of angles on a straight line total 180^{\circ}, we can find the third angle in the triangle,

180-156=24^{\circ}.

Labelling this onto the diagram, we now have,

The three interior angles of the triangle are 90^{\circ}, 24^{\circ} and x^{\circ}.

**Locate known sides and calculate any necessary unknown side lengths**.

This step is not needed for this question as we know two of the three angles within the triangle and we are finding the value of the missing angle x.

**Solve the problem using any necessary values.**

We use the angle fact that interior angles of a triangle sum to 180^{\circ} to work out the third angle.

180-(90+24)=66^{\circ}

Therefore angle x=66^{\circ}.

Calculate the missing angle x.

**Locate known angles and calculate any necessary unknown angles.**

One of the angles in the triangle is a right-angle which is 90^{\circ}. As there are two sides of the triangle with a dash through them, these lines are equal in length and so we have a right-angled isosceles triangle.

This means that the remaining two angles are the same, and the three angles must total 180^{\circ}. The two remaining angles are therefore

(180-90)\div{2}=90\div{2}=45^{\circ}.

**Locate known sides and calculate any necessary unknown side lengths**.

We know that two sides are of equal length but we do not need to determine the length of any side of the triangle and so we can move on to step 3.

**Solve the problem using any necessary values.**

As adjacent angles on a straight line sum to 180^{\circ}, we can use this to find the angle x as it is on a straight line with the angle 45^{\circ}.

180-45=135^{\circ}

Therefore angle x=135^{\circ}.

The sides of a triangle are 13 \ cm, 16 \ cm and 21 \ cm. What is the perimeter of the triangle?

**Locate known angles and calculate any necessary unknown angles.**

The angles are not involved in this question as we want to find the perimeter which is a length, and we do not know any angles in the triangle.

**Locate known sides and calculate any necessary unknown side lengths**.

The three sides of the triangle are given and so we have the information needed to answer the question.

**Note**: The sides are different lengths and so it is a scalene triangle.

**Solve the problem using any necessary values.**

The perimeter can be found by finding the total of the 3 sides. We therefore add together the side lengths to get the perimeter.

13+16+21=50\text{ cm}

The perimeter of the triangle is 50 \ cm.

Here is a triangle.

Two of these triangles are joined on their shortest sides to make a parallelogram. Calculate the perimeter of the parallelogram.

**Locate known angles and calculate any necessary unknown angles.**

There is a right angle in the triangle, denoted using a square and so it is a right-angled triangle. As we want to find the perimeter of the parallelogram it produces, which is a length, we do not need to find the size of any other angle in the triangle.

**Locate known sides and calculate any necessary unknown side lengths**.

The three side lengths are known (3 \ cm, 4 \ cm, and 5 \ cm) and so we can move on to step 3.

**Solve the problem using any necessary values.**

The question states that “two of these triangles are joined on their shortest sides to make a parallelogram”.

The shortest side of the right-angled triangle is the perpendicular height, 3 \ cm, and so we need to join two of these triangles together at this side to form a parallelogram. It is useful to label each side length here.

The perimeter can be found by finding the total of the sides. Remember that the 3 \ cm length is the perpendicular height of the parallelogram now and so it does **not** form part of the outside of the shape.

The perimeter is therefore the sum of the four side lengths, 4 \ cm, 5 \ cm, 4 \ cm, and 5 \ cm.

4+5+4+5=18\text{ cm}

The perimeter of the parallelogram is 18\text{ cm}.

The perimeter of a triangle is 119 \ cm.

The ratio of the sides of the triangle is 5:4:8.

Determine the length of each side of the triangle.

**Locate known angles and calculate any necessary unknown angles.**

The angles of the triangle are not involved in this question as we are calculating the side lengths of the triangle and have no information about the angles within the triangle.

**Locate known sides and calculate any necessary unknown side lengths**.

The three sides of the triangle are not given. But we have been given the ratio of the sides. Drawing a sketch of what the triangle may look like (although not essential), we have

**Solve the problem using any necessary values.**

Currently we have a triangle with a perimeter of 4+5+8=17 \ cm. As we want a similar triangle with a perimeter of 119 \ cm, we need to find the scale factor of enlargement. We do this by dividing the desired perimeter, by the scaled perimeter.

119\div{17}=7

We therefore know that each side length must be 7 times greater than our scaled triangle. We therefore need to multiply each side length by 7.

5\times 7=35

4\times 7=28

8\times 7=56

This gives us the three side lengths, 35 \ cm, 28 \ cm, and 56 \ cm.

**Note: **This is exactly the same approach as if we were to divide a quantity into a ratio, as explained below.

We need to divide the perimeter by the total of the parts of the perimeter.

119\div (5+4+8)=7

We then multiply the ratio parts by 7.

5\times 7=35

4\times 7=28

8\times 7=56

The lengths of the sides of the triangle are 35 \ cm, 28 \ cm, and 56 \ cm.

**Angles in polygons**

Make sure you know your angle properties as getting these confused causes quite a few misconceptions.

◌ Angles in a triangle total 180^{\circ} .

◌ Angles in a quadrilateral total 360^{\circ} .

**Angle facts**

Make sure you know your angle properties.

◌ Adjacent angles on a straight line add up to 180^{\circ} .

◌ Vertically opposite angles are equal.

◌ Alternate angles are equal.

◌ Corresponding angles are equal.

1. Which of these shapes show an equilateral triangle?

An equilateral triangle has all equal sides and all equal angles.

2. The sides of a triangle are 4.3 \ cm, 4.7 \ cm, and 43 \ mm. What kind of triangle is it?

Scalene

Equilateral

Isosceles

Right-angled

43 \ mm is the same as 4.3 \ cm. Since two sides are the same, it is an isosceles triangle.

3. Find angle x.

84^{\circ}

63^{\circ}

42^{\circ}

96^{\circ}

The triangle has two equal side lengths and so it is an isosceles triangle. This means that the base angles will be equal. The interior angles of a triangle sum to 180^{\circ}. Angle x is therefore equal to

(180-96)\div 2=42^{\circ}.

Angle x=42^{\circ}

4. Determine the size of the angle x in the diagram below.

142^{\circ}

81^{\circ}

38^{\circ}

61^{\circ}

As the sum of adjacent angles is 180^{\circ}, the angle next to 142^{\circ} is equal to 180-142=38^{\circ}.

As the sum of angles in a triangle is 180^{\circ}, the unknown value of x is equal to 180-(81+38)=61^{\circ} and so x=61^{\circ}.

5. Here is a triangle. Two of these triangles are joined on the longest sides to make a quadrilateral. Find its perimeter.

12 \ cm

24 \ cm

19 \ cm

14 \ cm

The two congruent triangles will make a rectangle when they are joined on their longest side (the hypotenuse).

The perimeter of the rectangle will be

2\times (3+4)=14.

6. The perimeter of an isosceles triangle is 45 \ cm. The unequal side is half the size of one of the equal sides. Find the length of the unequal side of the isosceles triangle.

9 \ cm

15 \ cm

18 \ cm

12 \ cm

The ratio of the sides of the isosceles triangle would be 1:2:2.

The unequal side is the shortest side and can be found by

45\div (1+2+2)=45\div 5=9.

The sides of the triangles will be 9 \ cm, 18 \ cm, and 18 \ cm. The shortest side will be 9 \ cm.

1. Here is a triangle.

Draw the line(s) of symmetry of the shape.

**(2 marks)**

Show answer

For one line of symmetry.

**(1)**

For three lines of symmetry.

**(1)**

2. Below is a diagram showing the triangle ABC. The point D lies on the line AC such that BD = CD.

(a) Determine the size of angle x.

(b) Find angle y.

**(4 marks)**

Show answer

(a)

180-(90+70)

**(1)**

**(1)**

(b)

(180-90)\div{2}

**(1)**

**(1)**

3. (a) Write down the coordinates of point B.

(b) Plot the point (1,3) and label it C.

(c) The points A, B and C make a triangle.

Find the area of the triangle.

**(4 marks)**

Show answer

(a) (6,9)

**(1)**

(b)

**(1)**

(c)

(6\times 5)\div 2

**(1)**

**(1)**

4. The perimeter of a triangle ABC is 60 \ cm.

The ratio of the sides of the triangle are 2:3:3.

(a) What type of triangle is ABC ?

(b) Find the smallest side of the triangle ABC.

(c) Heron’s formula can be used to find the area of a triangle.

Heron’s formula is

\text{Area}=\sqrt{s(s-a)(s-b)(s-c)}where s is half the perimeter and a, b and c are the three side lengths.

Use Heron’s formula along with your solution to part b) to find the area of the triangle ABC.

Give your answer to 3 significant figures.

State the units for your answer.

**(8 marks)**

Show answer

(a) Isosceles

**(1)**

(b)

60\div (2+3+3)=60\div 8 \ (=7.5)**(1)**

**(1)**

(c)

s=60\div 2 (=30)**(1)**

The second and third sides are 22.5 \ cm.

**(1)**

**(1)**

**(1)**

**(1)**

You have now learned how to:

- Recognise different types of triangles
- Solve problems involving the angles of a triangle
- Solve problems involving the perimeter of a triangle

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