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Here we will learn about finding the area of a trapezium, including compound area questions, questions with missing side lengths and questions involving unit conversion.

There are also area of a trapeziumworksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

The **area of a trapezium** is the amount of space inside the trapezium. It is measured in units squared ( cm^{2}, m^{2}, mm^{2} etc.)

A trapezium (also known as a trapezoid) is a **quadrilateral **with exactly one pair of **parallel **sides. The parallel sides are indicated using small arrows.

The plural of trapezium is trapezia or trapeziums.

An **isosceles trapezium** is a trapezium where the base angles are equal and therefore the left and right side lengths are also equal.

The area of a trapezium is calculated by:

**Adding the parallel sides****Dividing by 2****Multiplying by the height.**

This can also be summarised with the following formula:

\text { Area }_{\text {Trapezium }}=\frac{a+b}{2} \times h

Where a and b are the parallel sides

Where h is the perpendicular height of the trapezium

In order to find the area of a trapezium

**Find the sum of the parallel sides.****Divide by 2 .****Multiply by the perpendicular height of the trapezium.****Write down your final answer with units squared.**

Another way of calculating the area is by using the formula below:

\text { Area }_{\text {Trapezium }}=\frac{a+b}{2} \times h

Where a and b are the parallel sides

Where h is equal to the perpendicular height of the trapezium

Get your free Area of a trapezium worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free Area of a trapezium worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREE**Area of a trapezium** is part of our series of lessons to support revision on **area**. You may find it helpful to start with the main area lesson for a summary of what to expect, or use the step by step guides below for further detail on individual topics. Other lessons in this series include:

Find the area of the trapezium below:

**Find the sum of the parallel sides.**

4+6=10

2**Divide by 2.**

10\div2=5

3**Multiply by the perpendicular height of the trapezium.**

In this case the perpendicular height is 3 .

5\times3=15

4**Write your final answer with units squared.**

\text { Area }=15 \mathrm{~m}^{2}

Find the area of the trapezium below:

**Find the sum of the parallel sides.**

We have two different units for the parallel sides so we must change the measures to a common unit.

In this case it is easier to convert to metres since the height is also in metres.

There are 100cm in a metre, so if we divide the top side of the trapezium by 100 we get 9.5m

So now if we add the sides:

9.5+14=23.5

**Divide by 2.**

23.5\div2=11.75

**Multiply by the perpendicular height of the trapezium.**

In this case the perpendicular height is 8 .

11.75\times8=94

**Write your final answer with units squared.**

\text { Area }=94 m^{2}

Sarah is looking to design the flower bed below at the front of her house. She would like to cover the entire flower bed with rose bushes. Each bush needs 1.5m^{2} to allow the roots to spread out evenly. What is the maximum number of rose bushes she can plant on her flower bed?

**Find the sum of the parallel sides.**

4.5+1.5=6

**Divide by 2.**

6\div2=3

**Multiply by the perpendicular height of the trapezium.**

In this case the perpendicular height is 3 .

3\times3=9

**Write your final answer with units squared.**

\text { Area }=9 m^{2}

Now to answer the actual question, since each rose bush needs 1.5 square metres to grow, we need to divide 1.5 into the total area which is 9 .

9\div1.5 = 6

Sarah can plant a maximum of 6 rose bushes in her garden.

Find the area of the shaded region below:

**Find the sum of the parallel sides.**

Before we can do this step we need to split the compound shape into individual shapes we can calculate the area of. In this case we can split the hexagonal shape at the top into two trapeziums and have a rectangle at the bottom as shown:

Now if we take one trapezium, we know one length is 8m , the length of the other parallel side is 6m because that is the length of the rectangle and which is connected to the side.

8+6=14

*We calculated the height as 4.5m because the height of both trapeziums combined is 9m so to get the height of one trapezium we divide 9 by 2 to get 4.5 .

**Divide by 2.**

14\div2=7

**Multiply by the perpendicular height of the trapezium.**

In this case the perpendicular height is 4.5 .

7\times4.5=31.5

**Write your final answer with units squared.**

\text { Area }_{\text {Trapezium }}=31.5 \mathrm{~cm}^{2}

We have to now double this area as there are 2 trapeziums and then add the area of rectangle.

\[\begin{aligned}
\text { Area }_{\text {Rectangle }} &=l \times w \\
\text { Area }_{\text {Rectangle }} &=6 \times 3 \\
\text { Area }_{\text {Rectangle }} &=18 \mathrm{~cm}^{2}
\end{aligned}\]

\[\begin{aligned}
\text { Area }_{\text {Compound Shape }} &=31.5+18 \\
&=81 \mathrm{~cm}^{2}
\end{aligned}\]

The area of the trapezium below is 128cm^{2} . Calculate the value of h in the trapezium below:

**Rearrange the area of a trapezium formula**

To find the height of the trapezium let us start with the formula for the area of a trapezium and rearrange it to solve for height (h).

\text { Area }_{\text {Trapezium }}=\frac{a+b}{2} \times h

First we need to move the 2 to the other side of the equal sign. Division changes to multiplication.

2 A=(a+b) \times h

Next we need to move the a+b to the other side of the equal sign. Multiplication changes to division.

\frac{2 A}{(a+b)}=h

The new formula for the height of the trapezium is:

h=\frac{2 A}{(a+b)}

**Substitute in the known values**

We can then substitute our known values:

\[\begin{aligned}
h &=\frac{2(128)}{(12+4)} \\
h &=16 \mathrm{~cm}
\end{aligned}\]

The area of a trapezium is 322 square milimetres and its height is 14mm . If the length of one of the parallel sides is 27mm , what is the length of the other parallel side?

Let’s start out by sketching out a trapezium using what is given in the question:

**Rearrange the area of a trapezium formula **

To find the length of the other parallel side ‘a’ let us start with the formula for the area of a trapezium and rearrange it to solve for a .

\text { Area }_{\text {Trapezium }}=\frac{a+b}{2} \times h

First we need to multiply both sides of the formula by 2 .

2 A=(a+b) \times h

Next we need to divide both sides of the formula by ‘h’ .

\frac{2 A}{h}=a+b

Then we can then subtract ‘b’ from both sides of the formula.

\frac{2 A}{h}-b=a

The new formula for a is:

a=\frac{2 A}{h}-b

**Substitute in the known values**

We can then substitute our known values:

\[\begin{aligned}
&a=\frac{2(322)}{14}-27 \\
&a=19 \mathrm{~mm}
\end{aligned}\]

**Using incorrect units for the answer**

A common error is to forget to include squared units when asked to calculate area.

**Forgetting to convert measures to a common unit**

Before calculating the area of a trapezium, pupils must look at the units given in the question. If different units are given e.g. length = 4m and width = 3cm pupils must convert them either both to cm or both to m .

**Using length of the non-parallel sides when calculating area and not the height**

Sometimes in a question we are given additional lengths which are not needed in our calculations. Sometimes we are given the length of the non-parallel sides of the trapezium. We must be careful to not mistake these measurements for height.

1. Find the area of the trapezium below:

20.5m^{2}

36m^{2}

67.5m^{2}

47.5m^{2}

Add the parallel sides 9 and 7 together. Divide the sum by 2 . Times by the perpendicular height of 4.5 .

2. Find the area of the trapezium below:

5085cm^{2}

5085m^{2}

2055.6cm^{2}

2055.6m^{2}

Convert 0.68m into cm . Add the 45cm and 68cm together. Divide by 2 . Multiply by 90 .

3. Sally is looking to design the garden below at the back of her house. She would like to cover the entire garden with grass. An individual carpet of grass covers an area of 4 square metres. How many rolls of grass will be needed to cover the entire garden?

42.5

10

11

165

Add the parallel sides 11 and 6 together. Divide the sum by 2 . Times by the perpendicular height of 5 . Divide by 4 .

4. Find the area of the shaded region below:

224m^{2}

84.5m^{2}

44m^{2}

55m^{2}

Find the area of the rectangle by multiplying its length times width. (5 x 11) . Split the hexagon in half and find the area of each trapezium. To do this add the parallel sides ( 11 and 15 ), divide by 2 , and multiply by the perpendicular height which in this case is 6.5 . As there are two congruent trapeziums, multiply the area of the trapezium by 2 and add on the area of the rectangle to get the compound area.

5. The area of the trapezium below is 68m^{2} . Calculate the value of h in the trapezium below:

8.5m^{2}

60m^{2}

16m

8.5m

Start with the area of a trapezium formula \text { Area }_{\text {Trapezium }}=\frac{a+b}{2} \times h and rearrange to get the formula h=\frac{2 A}{(a+b)} . Substitute the values of the area and the parallel sides and solve for the height.

6. Calculate the value of a in the trapezium below:

55mm

13mm

45mm

14mm

Start with the area of a trapezium formula \text { Area }_{\text {Trapezium }}=\frac{a+b}{2} \times h and rearrange to get the formula a=\frac{2 A}{h}-b . Make sure to isolate a by moving the other variables to the other side of the equal sign and changing to the opposite sign. Substitute the known values and solve for the length of the parallel side.

1. Find the area of the trapezium below.

**(3 marks)**

Show answer

Finding sum of parallel sides (12+18=30)

**(1)**

Dividing by 2 or multiplying by height

**(1)**

75m^{2} (cao with units)

**(1)**

2. (a) Calculate the value of x in the trapezium below.

(b) The above trapezium is enlarged by a scale factor of 2 . What is the area of the new trapezium?

**(7 marks)**

Show answer

(a)

Evidence of adding the parallel sides 11+17 = 28

**(1)**

Dividing by 2

**(1)**

70\div14 seen

**(1)**

5m seen (cao including units)

**(1)**

(b)

2^{2} oe seen

**(1)**

70\times4 seen

**(1)**

**(1)**

3. A painter is looking to paint his deck. Below is a blueprint of the deck. A can of paint costs £5.50 and covers an area of 1.5cm^{2} . How much would it cost to paint the entire deck?

**(5 marks)**

Show answer

Adding parallel sides of trapezium and dividing by 2 or multiplying by height

**(1)**

50cm^{2} seen as area of trapezium

**(1)**

\frac{1}{2}bh seen or correct values substituted or 24cm^{2} seen with some calculations

**(1)**

Evidence of adding areas or dividing total are by 1.5 or multiplying by £5.50

**(1)**

**(1)**

You have now learned how to:

- Calculate and compare the area of trapeziums including using standard units
- Calculate the area of trapeziums and related composite shapes

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#### GCSE Maths Papers - November 2022 Topics

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Practice paper packs based on the November advanced information for Edexcel 2022 Foundation and Higher exams.

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