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In order to access this I need to be confident with:

Parts of a circle Angles in polygons Angles on a straight lineAngles at a point

Angles in parallel linesProperties of triangles

This topic is relevant for:

Here we will learn about the circle theorem: angles in the same segment, including its application, proof, and using it to solve more difficult problems.

There are also circle theorem worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

Angles in the same segment are equal

In the diagram above, BD is a chord that divides the circle into the major and minor segments. The two points A and C on the circumference are joined to two other points on the circumference B and D . The angle DAB is the same as angle DCB . This is the same for any point that is placed on the major arc and so **angles in the same segment are equal**.

If the point is placed on the minor arc in the other segment, it would be a different angle, but all angles on the minor arc would be the same. Here, x=180-θ for any value of θ.

Below is a diagram showing the key parts of a circle for this theorem:

- A
**chord**is a straight line that meets the circumference in two places. The longest chord in a circle is the**diameter**. - The
**major segment**is the larger segment of a circle when it is enclosed by a chord and the**major arc**. - The
**minor segment**is the smaller part of a circle when it is cut by a chord and the**minor arc**. - An
**arc**is a part of the circumference. The major arc is longer than the minor arc.

**Subtended angles**

An angle within a circle is created by two chords meeting at a point on the circumference of a circle. The diagrams below show the angle subtended by arc AC from point B for two different circles.

To be able to prove the theorem, you need to know the following circle theorems:

- The
**angle at the centre is twice the angle at the circumference**

**We start by labelling the two angles at the circumference a and b**

2**Plot the centre of a circle and draw two radii from the centre to the circumference (here these are dashed lines). Label the angle between the two radii c . **

3**Let us inspect the angles a and c .**

4**We know that the angle at the centre is twice the angle at the circumference. This means that if the angle at the centre is equal to 2x, the angle at the circumference (which was our angle a)is now equal to half of 2x, or just x.**

5**Let us now inspect angles b and c .**

6**Again, we know that the angle at the centre is twice the angle at the circumference and so if we say that the angle c is equal to 2x, the angle b is equal to x.**

7**We now have the current situation where a and b are equal to x and the angle c is equal to 2x .**

8**This means that the two angles at the circumference are the same size and therefore we can state angles in the same segment are equal.**

In order to use the fact that angles in the same segment are equal:

**Locate the key parts of the circle for the theorem****Use other angle facts to determine an angle at the circumference in the same segment****Use the angle in the same segment theorem to state the other missing angle**

Get your free angles in the same segment worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free angles in the same segment worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEBelow is a circle with centre O . AC and BD are chords. Calculate the size of angle CAD .

**Locate the key parts of the circle for the theorem**.

Here we have:

- The angle CBD = 47°
- AC and BD are chords
- The angle CAD = θ

2**Use other angle facts to determine an angle at the circumference in the same segment**.

We already know that DBC = 47° so we do not need to use any other angle fact to determine this angle for this example.

3**Use the angle in the same segment theorem to state the other missing angle**.

The angle CAD is in the same segment as the angle CBD and so we can state the angle of CAD

CAD = CBD = 47°

A, B, C, and D are points on a circle with centre O . Calculate the size of the angle CBD .

**Locate the key parts of the circle for the theorem**.

Here we have:

- The angle BDA = 65°
- AC, AD, BC, and BD are chords
- The angle CED = 88°
- The angle CBD = θ

**Use other angle facts to determine an angle at the circumference in the same segment**.

**Angles on a straight line total 180° ** so angle BEC = 180-88 = 92° .

**Use the angle in the same segment theorem to state the other missing angle**.

The angle BCA is in the same segment as the angle BDA and so they are equal angles. This means angle BCA = 65° .

As **angles in a triangle total 180° **, angle CBD can now be calculated:

CBD = 180 - (92+65)

CBD = 23°

The circle with centre O has four points on the circumference. The two chords AC and BD intersect at the point E . Calculate the size of angle ABE .

**Locate the key parts of the circle for the theorem**.

Here we have:

- The angle CDB = 44°
- BD is a diameter
- AB, AC, and CD are chords
- The angle CED = 79°
- The angle ABE = θ

**Use other angle facts to determine an angle at the circumference in the same segment**.

**Vertically opposite angles are equal** and so the angle BEA = 70° .

**Use the angle in the same segment theorem to state the other missing angle**.

Angle CDB is in the same segment as the angle CAB and so they are equal. This means we can calculate the size of angle ABE as **angles in a triangle total 180° :**

ABE = 180 - (79+44)

ABE = 57°

A, B, C, and D are points on the circumference of the circle with centre O . Calculate the size of angle ABD .

**Locate the key parts of the circle for the theorem**.

Here we have:

- The angle AOD = 74°
- OA = OD = Radii
- BD is a diameter
- AB, AC and CD are chords
- The angle ABD = θ

**Use other angle facts to determine an angle at the circumference in the same segment**.

The **angle at the centre is twice the angle at the circumference** and so the angle ACD is equal to:

ACD=74\div2

ACD=37°

**Use the angle in the same segment theorem to state the other missing angle**.

Angle ABD is in the same segment as angle ACD and so ABD = 37° .

ABCD are vertices of a cyclic quadrilateral. The circle has centre O . The chords AC and BD intersect at the point E . Calculate the size of the angle ABE .

**Locate the key parts of the circle for the theorem**.

Here we have:

- The angle ADC = 94°
- The angle CAD = 21°
- The angle BEC = 88°
- A, B, C and D are all connected by chords
- The angle ABD = θ

**Use other angle facts to determine an angle at the circumference in the same segment**.

Here, angle properties are very important. **Angles on a straight line total 180° **, angle CED = 180 - 88 = 92° . **Vertically opposite angles are the same** and so angle AED = 88° . **Angles in a triangle total 180° **, and so angle ADE = 180 - (88+21) = 71° . This means that angle CDE = 94 - 71 = 23° . Placing all this information into the diagram, we have:

The angle DCE can now be calculated as it is the third angle in the triangle. This means that:

DCE = 180 - (92+23)

DCE = 65°

**Use the angle in the same segment theorem to state the other missing angle**.

Angle ACD is in the same segment as angle ABD and so they are equal. This means that angle ABD = 65° .

A, B, C, D, and E are points on a circle with centre O . The lines AB > and CD are parallel. Calculate the value of angle BDC .

**Locate the key parts of the circle for the theorem**.

Here we have:

- The angle AGE = 84°
- The angle EBD = 8°
- AC and BD are diameters
- BE, CE and CD are chords
- The angle BDC = θ

**Use other angle facts to determine an angle at the circumference in the same segment**.

**Vertically opposite angles are the same **so angle BGO = 84° . The missing angle in the triangle AOB = 180-(84+8) = 88° . **Angles on a straight line total 180° **, so angle BOC = 180 - 88 = 92° .

The **angle at the centre is twice the angle at the circumference **and so angle BEC = 922 = 46°

**Use the angle in the same segment theorem to state the other missing angle**.

As angle BEC is in the same segment as the angle BDC we can say that angle BEC = angle BDC or BDC=46 .

**Angle is double or half the original**

The other angle in the same segment at the circumference is doubled or halved instead of it being the same.

**Angles add up to 90° or 180°**

The two angles that are in the same segment at the circumference total 90° (or 180° if one angle is obtuse).

1. A circle with centre O has four points on the circumference, A, B, C, and D . Angle CAD = 11^{\circ} . Calculate the size of the angle CBD .

10^{\circ}

79^{\circ}

22^{\circ}

11^{\circ}

CBD = CAD = 11^{\circ} (angles in the same segment are equal)

2. A, B, C, and D are points on the circle with centre O . The chords BD and AC intersect at the point E . Calculate the size of angle CBE .

49^{\circ}

47^{\circ}

43^{\circ}

50^{\circ}

- BEC = 84^{\circ} (angles on a straight line)
- BCE = 47^{\circ} (angles in the same segment are equal)
- CBE = 180 – (84+47) = 49^{\circ} (angles in a triangle)

3. A, B, C, and D are points on the circle with centre O . BD and AC intersect at the point E . BD is **not** the diameter of the circle. Calculate the size of angle ABE .

38^{\circ}

51^{\circ}

52^{\circ}

44.5^{\circ}

- CED = 89^{\circ} (angles on a straight line)
- DCE = 180 – (91+38) = 51^{\circ} (angles in a triangle)
- ABE = 51^{\circ} (angles in the same segment are equal)

4. A circle with centre O has four points on the circumference, A, B, C, and D . The reflex angle AOD = 306^{\circ} . Calculate the size of angle ABD .

54^{\circ}

27^{\circ}

108^{\circ}

44^{\circ}

- AOD = 360 – 306 = 54^{\circ} (angles at a point)
- ACD = 54 ÷ 2=27^{\circ} (angle at the centre is twice the angle at the circumference)
- ABD = ACD = 27^{\circ} (angles in the same segment are equal).

5. A circle with centre O has four points on the circumference, A, B, C, and D . AC and BD intersect at the point E . Angle BCD = 84^{\circ} . Calculate the size of angle ABE .

84^{\circ}

52^{\circ}

56^{\circ}

42^{\circ}

- BAD = 180 – 84 = 96^{\circ} (opposite angles in a cyclic quadrilateral total 180^{\circ} )
- BAE = 96 – 52 = 44^{\circ}
- ABE = 180 – (80+44) = 56^{\circ} (angles in a triangle)

6. A circle with centre O has points A, B, C, D, and E on the circumference. Angle BAF = 58^{\circ} . Calculate the size of the angle BCD .

122^{\circ}

64^{\circ}

174^{\circ}

116^{\circ}

- BCD = 180 – 58 = 122^{\circ} (angles in opposing segments total 180^{\circ} / cyclic quadrilateral).

1. Use the information in the diagram below to calculate the size of angle ACB. Explain your answer.

**(4 marks)**

Show answer

ADB = 180 – (78 + 65) = 37∘

**(1)**

Angles in a triangle total 180∘

**(1)**

**(1)**

Angles in the same segment are equal

**(1)**

2. A, B, C, D are points on the circle with centre O. The chords AC and BD intersect at the point E. The tangent FG goes through the point B. Terry says that angle ACD = 11∘. Is he correct?

Explain your answer.

**(5 marks)**

Show answer

ABE = 90 – 75 = 15∘

**(1)**

The tangent meets the radius at a right angle

**(1)**

**(1)**

Angles in the same segment are equal

**(1)**

No, Terry is wrong

**(1)**

3 (a). The circle with centre O has 4 points on the circumference, ]A, B, C, and D. Calculate the size of angle ADB.

(b). Hence state the size of angle AED in the diagram below.

**(6 marks)**

Show answer

**(a)** BAC = 68 2 = 34∘

**(1)**

Angle at the centre is twice the angle at the circumference

**(1)**

**(1)**

Angles in a triangle total 180∘

**(1)**

**(b)** AED = 42∘

**(1)**

Angles in the same segment are equal

**(1)**

You have now learned how to:

- Apply and prove the standard circle theorems concerning angles, radii, tangents and chords, and use them to prove related results

- Angle at the centre
- Cyclic quadrilaterals
- Angles in a semicircle
- The alternate segment theorem
- Tangents of a circle
- Chord of a circle

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#### FREE GCSE Maths Practice Papers - 2022 Topics

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Practice paper packs based on the advanced information for the Summer 2022 exam series from Edexcel, AQA and OCR.

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