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Here we will learn about the nth term of a quadratic sequence, including generating a quadratic sequence, finding the nth term of a quadratic sequence and applying this to real life problems.

There are also quadratic nth term worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

A **quadratic nth term** is a rule used to generate a sequence based on the square numbers and has the general form an^{2}+bn+c where a, b, and c are constants (a constant is a number that does not change).

This looks very similar to a quadratic expression (ax^{2}+bx+c) however by substituting in values for n we generate a sequence where the common difference between two terms is not the same for any two terms.

E.g.

Given the n^{th} term n^{2}+2n , generate the first 5 terms in the sequence.

n | n^{2} | 2n | n^{2}+2n |

1 | 1 | 2 | 3 |

2 | 4 | 4 | 8 |

3 | 9 | 6 | 15 |

4 | 16 | 8 | 24 |

5 | 25 | 10 | 35 |

So the first 5 terms in the sequence with the nth term rule n^{2}+2n are: 3, 8, 15, 24, 35.

Let us inspect the sequence of n^{2} .

If we write the first 5 terms of the sequence of n^{2}, we get the numbers: 1, 4, 9, 16, 25 . This is because when you substitute the values of 1, 2, 3, 4, and 5 into the nth term, we get the first 5 square numbers.

Let’s look at the term to term difference.

Here, the first term to term difference is +3, +5, +7, +9 , etc and so the sequence n^{2} increases by another sequence. We can therefore use this sequence as a framework when trying to find the nth term of a quadratic sequence.

What if we had the sequence 2n^{2} ?

The first 5 terms of the sequence 2n^{2} are 2, 8, 18, 32, 50 . This is calculated by multiplying the terms for the sequence n^{2} by 2 .

Notice that the term to term difference is still not the same:

The term to term differences for 2n^{2} are now twice as large as the term to term difference for n^{2} .

This means that when you see a sequence that has a difference based on the numbers +3, +5, +7, +9 , this means that the sequence is based on the square numbers, and so your sequence will be a quadratic sequence of the form an^{2}+bn+c .

Let us now reverse the question previously and use the first 5 terms in the sequence 3, 8, 15, 24, 35 to find the nth term of the sequence.

So we have the sequence: 3, 8, 15, 24, 35 .

If we look at the term to term difference between these numbers, we have:

Notice that there is** no common difference** from one term to the next so this sequence is based on the sequence n^{2} .

We have a small problem though as even though this sequence increases by +5, +7, +9, +11, etc, we do not know what the coefficient of n^{2} is (the value of a for an^{2} ).

To work this out, we need to halve the second difference.

The second difference is the term to term rule between the first difference. For our sequence above we have:

The second difference for this sequence is +2 , and so as the coefficient of n^{2} is half of this number, we can now state that our sequence is based on the sequence 1n^{2} or just n^{2}=1, 4, 9, 16, 25.

So how do we get from the numbers: 1, 4, 9, 16, 25 to the terms in the sequence 3, 8, 14, 24, 35 ?

We start by finding the remainder between each term:

Term in original sequence | 3 | 8 | 15 | 24 | 35 |

n^{2} | 1 | 4 | 9 | 16 | 25 |

Term – n^{2} | 2 | 4 | 6 | 8 | 10 |

So now we have a new sequence of numbers: 2, 4, 6, 8, 10.

We can use our knowledge of finding the nth term of an arithmetic sequence to work out the nth term to be 2n .

So nth term of our quadratic sequence is n^{2}+2n .

In order to find the nth term of a quadratic sequence:

**Calculate the second difference.****Subtract**\bf{an^{2}}**from the original sequence**.**Find the**\textbf{nth}**term of the arithmetic sequence**.

Get your free quadratic sequences worksheet of 20+ questions and answers on quadratic nth term and more. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free quadratic sequences worksheet of 20+ questions and answers on quadratic nth term and more. Includes reasoning and applied questions.

DOWNLOAD FREE**Quadratic nth term** is part of our series of lessons to support revision on **sequences**. You may find it helpful to start with the main sequences lesson for a summary of what to expect, or use the step by step guides below for further detail on individual topics. Other lessons in this series include:

Calculate the nth term for the following sequence: 4, 16, 36, 64, 100

**Calculate the second difference**.

The second difference is +8 . By halving the second difference, the sequence is based on 4n^{2} .

**2Subtract an^{2} from the original sequence**.

Term in original sequence | 4 | 16 | 36 | 64 | 100 |

4n^{2} | 4 | 16 | 36 | 64 | 100 |

Term – 4n^{2} | 0 | 0 | 0 | 0 | 0 |

**3Find the nth term of the arithmetic sequence**.

As the remainder is 0 for each term, there is no arithmetic sequence to find the nth term of and so the nth term of the sequence 4, 16, 36, 64, 100 is:

4n^{2} .

Calculate the nth term for the following sequence: −5, −20, −45, −80, −125 .

**Calculate the second difference**.

The second difference is −10 . By halving the second difference, the sequence is based on −5n^{2} .

**Subtract an^{2} from the original sequence**.

Term in original sequence | -5 | -20 | -45 | -80 | -125 |

−5n^{2} | -5 | -20 | -45 | -80 | -125 |

Term -5n^{2} | 0 | 0 | 0 | 0 | 0 |

**Find the nth term of the arithmetic sequence**.

As the remainder is 0 for each term, there is no arithmetic sequence to find the nth term of and so the nth term of the sequence −5 , −20 , −45 , −80 , −125 is:

−5n^{2} .

Calculate the nth term for the following sequence: 7, 20, 39, 64, 95 .

**Calculate the second difference**.

The second difference is +6 . By halving the second difference, the sequence is based on 3n^{2} .

**Subtract an^{2} from the original sequence**.

Term in original sequence | 7 | 20 | 39 | 64 | 95 |

3n^{2} | 3 | 12 | 27 | 48 | 75 |

Term – 3n^{2} | 4 | 8 | 12 | 16 | 20 |

We now have the remaining arithmetic sequence 4, 8, 12, 16, 20.

**Find the nth term of the arithmetic sequence**.

The nth term of the sequence 4, 8, 12, 16, 20 is 4n , so the nth term of this quadratic sequence 7, 20, 39, 64, 95 is:

3n^{2}+4n.

Calculate the nth term for the following sequence: 1, −5, −15, −29, −47

**Calculate the second difference**.

The second difference is −4 . By halving the second difference, the sequence is based on −2n^{2} .

**Subtract an^{2} from the original sequence**.

Term in original sequence | 1 | -5 | -15 | -29 | -47 |

−2n^{2} | -2 | -8 | -18 | -32 | -50 |

Term – 2n^{2} | 3 | 3 | 3 | 3 | 3 |

The remainder is a constant and so there is no arithmetic sequence to calculate the nth term of. We just add 3 to the value of −2n^{2} .

**Find the nth term of the arithmetic sequence**.

The nth term of the sequence 1, -5, -15, -29, -47 is:

-2n^{2}+3 .

Calculate the nth term for the following sequence: 7, 14, 23, 34, 47

**Calculate the second difference**.

The second difference is +2 . By halving the second difference, the sequence is based on n^{2} .

**Subtract an^{2} from the original sequence**.

Term in original sequence | 7 | 14 | 23 | 34 | 47 |

n^{2} | 1 | 4 | 9 | 16 | 25 |

Term – n^{2} | 6 | 10 | 14 | 18 | 22 |

The remainder is an arithmetic sequence 6, 10, 14, 18, 22.

**Find the nth term of the arithmetic sequence**.

The nth term of the arithmetic sequence is 4n+2 . This means that the nth term of our quadratic sequence is:

n^{2}+4n+2 .

Calculate the nth term for the following sequence: −5, −1, 9, 25, 47

**Calculate the second difference**.

The second difference is +3 . By halving the second difference, the sequence is based on 3n^{2} .

**Subtract an^{2} from the original sequence**.

Term in original sequence | -5 | -1 | 9 | 25 | 47 |

3n^{2} | 3 | 12 | 27 | 48 | 75 |

Term – 3n^{2} | -8 | -13 | -18 | -23 | -28 |

The remainder is an arithmetic sequence −8, −13, −18, −23, −28

**Find the nth term of the arithmetic sequence**.

The nth term of the arithmetic sequence −8, −13, −18, −23, −28 is −5n−3 so the nth term of our quadratic sequence is:

3n^{2}−5n−3 .

**Second difference**

A common error is to forget to half the second difference before using it as the coefficient of n^{2} .

E.g.

For the quadratic sequence n^{2}=1, 4, 9, 16, 25 , …the second difference is equal to 2 and so the nth term could incorrectly written as 2n^{2} .

**Confusing a quadratic sequence with an arithmetic sequence**

A quadratic sequence will have a common second difference.

**Positive and negative second differences**

When the sequence is decreasing into negative terms, the second difference can be written incorrectly as a positive number.

E.g.

The sequence −n^{2} = −1, −4, −9, −16, … has a second difference of −2 but is incorrectly written as 2 .

**Values of n**

The value for n cannot be negative.** **n represents the term (position) numbers and therefore it can only be positive integers starting from 1 and should also not include 0, n=1, 2, 3, 4, 5, ….

This is important when finding the term in the sequence given its value as a zero or negative solution for n can be calculated.

1. Calculate the nth term of the quadratic sequence: 2,8,18,32,50

6n−4

6n^2

4n^2

2n^2

Second difference +4

2n^2=2, 8, 18, 32, 50

2. Calculate the nth term of the quadratic sequence: −3, −12, −27, −48, −75

−3n

(−3n)^2

−3n^2

−4.5n^2

Second difference −6

−3n^2= −3, −12, −27, −48, −75

3. Calculate the nth term of the quadratic sequence: 7, 24, 51, 88, 135

5n+2

5n^2+2n

5n^2−2n

10n^2−3

Second difference +10

Original | 7 | 24 | 51 | 88 | 135 |

5n^{2} |
5 | 20 | 45 | 80 | 125 |

Original – 5n^{2} |
2 | 4 | 6 | 8 | 10 |

So nth term = 5n^2+2n

4. Calculate the nth term of the quadratic sequence: −10, −22, −42, −70, −106

−4n−6

−4n^2+6

−8n^2−2

−4n^2−6

Second difference −8

−4n^2= −4, −16, −36, −64, −100

Original | -10 | -22 | -42 | -70 | -106 |

4n^{2} |
-4 | -16 | -36 | -64 | -100 |

Original – 4n^{2} |
-6 | -6 | -6 | -6 | -6 |

So nth term = 4n^2 – 6

5. Calculate the nth term of the quadratic sequence: 3, 11, 23, 39, 59

2n+1

2n^2+1

2n^2+2n-1

4n^2-1

Second difference +4

2n^2 = 2, 8, 18, 32, 50

Original | 3 | 11 | 23 | 39 | 59 |

2n^{2} |
2 | 8 | 18 | 32 | 50 |

Original – 2n^{2} |
1 | 3 | 5 | 7 | 9 |

So nth term = 2n^2 + 2n – 1

6. Calculate the nth term of the quadratic sequence: 6, 15, 32, 57, 90

4n+2

4n^2-3n+5

4n^2+3n-5

8n^2-2

Second difference +8

4n^2=4, 16, 36, 64, 100

Original | 6 | 15 | 32 | 57 | 90 |

4n^{2} |
4 | 16 | 36 | 64 | 100 |

Original – 4n^{2} |
2 | -1 | -4 | -7 | -10 |

So nth term = 4n^2 – 3n + 5

1. Given that the nth term of the sequence 2, 8, 18, 32, 50 is 2n^2 , state the nth term of the sequence 3, 10, 21, 36, 55 .

**(2 marks)**

Show answer

Remainder: 1, 2, 3, 4, 5

**(1)**

nth term: 2n^2+n

**(1)**

2. (a) Given the first three terms in the sequence are 2, 18, 48 , state the next two terms in the sequence.

(b) Calculate the nth term of the sequence

**(5 marks)**

Show answer

92

**(1)**

**(1)**

**(1)**

**(1)**

nth term = 7n^2-5n

**(1)**

3. Is the value 52 a term in the sequence n^2+3n+2 ?

**(4 marks)**

Show answer

n^2+3n+2=52 so n^2+3n-50=0

**(1)**

Factor pairs of 50 : 1×50, 2×25, 5×10

**(1)**

Does not factorise

**(1)**

No

**(1)**

You have now learned how to:

- Deduce expressions to calculate the nth term of quadratic sequences

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