One to one maths interventions built for KS4 success

Weekly online one to one GCSE maths revision lessons now available

In order to access this I need to be confident with:

Coordinates

Negative numbers Equation of a line Gradient of a line Substitution Linear equationsThis topic is relevant for:

Here we will learn about how to find the y intercept and the x intercept from a straight line graph, including straight lines in the form y=mx+c and ax+by=c.

There are also y intercept worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

Finding the y intercept and the x intercept of a straight line is an important skill used to solve algebraic and real-life problems involving straight line graphs.

The **intercept **of a graph is where it **crosses the coordinate axes**.

You can find the y and x intercepts of graphs of all types of functions including straight lines, quadratic functions, cubic functions and others. The x intercepts of a quadratic equation are also known as its roots. In A Level Mathematics we look at finding intercepts of more complicated functions.

To find the intercepts,

Substitute x=0 into the equation of the function to find the y intercept.

Substitute y=0 into the equation of the function to find the x intercept.

Let’s look at some examples,

A straight line has the equation 4x-3y=18. Find the y and x intercepts of the line.

- To find the y intercept, substitute x=0 into the equation.

Now solve the equation to find the corresponding y value.

\begin{aligned} -3y&=18\\\\ y&=-6 \end{aligned}The y intercept is -6 and has coordinate (0,-6).

- To find the x intercept, substitute y=0 into the equation.

Now solve the equation to find the x value.

\begin{aligned} 4x&=18\\\\ x&=4.5 \end{aligned}The x intercept is 4.5 and has coordinate (4.5, \ 0).

For many graphs, if the function is of the form y=[ function of x] \ + constant, the constant is the y intercept. These functions are mainly what we call polynomials, and involve integer powers of x.

For example,

However, this is not the case for more complicated functions such as reciprocals, exponentials or some trigonometric functions.

In order to find the y intercept and the x intercept:

**Substitute**x=0**into the equation of the line.****Solve the equation to find the**\bf{y}**intercept.****Substitute**y=0**into the equation of the line.****Solve the equation to find the**\bf{x}**intercept**.

Get your free y intercept worksheet of 20+ straight line graph questions and answers. Includes reasoning and applied questions.

COMING SOONGet your free y intercept worksheet of 20+ straight line graph questions and answers. Includes reasoning and applied questions.

COMING SOONFind the y intercept and x intercept of the line y=2x-5.

**Substitute**x=0**into the equation of the line.**

2**Solve the equation to find the ** \bf{y} ** intercept.**

This equation gives y=-5.

The y intercept is -5.

It has coordinates (0,-5).

You might have noticed that this is the special case where the equation is in the form y=[ function of x] \ + \ c. In this case c=-5 so the y intercept is (0, -5).

3**Substitute ** y=0 ** into the equation of the line.**

4**Solve the equation to find the ** \bf{x} ** intercept**.

The x intercept is 2.5.

It has coordinates (2.5, \ 0).

Find the y intercept and x intercept of the line y=\frac{1}{2}x+3.

**Substitute ** x=0 ** into the equation of the line.**

y=\frac{1}{2}(0)+3

** Solve the equation to find the** \bf{y}

This equation gives y=3.

The y intercept is 3 .

It has coordinates (0, \ 3).

**Substitute ** y=0 ** into the equation of the line.**

0=\frac{1}{2}x+3

**Solve the equation to find the ** \bf{x} ** intercept**.

\begin{aligned} 0&=\frac{1}{2}x+3\\\\ \frac{1}{2}x&=-3\\\\ x&=-6 \end{aligned}

The x intercept is -6.

It has coordinates (-6, \ 0).

Find the y intercept and x intercept of the line 2x+5y=20.

**Substitute ** x=0 ** into the equation of the line.**

2(0)+5y=20

** Solve the equation to find the ** \bf{y}

\begin{aligned}
5y&=20\\\\
y&=4
\end{aligned}

The y intercept is 4 .

It has coordinates (0, \ 4).

**Substitute ** y=0 ** into the equation of the line.**

2x+5(0)=20

**Solve the equation to find the ** \bf{x} ** intercept**.

\begin{aligned}
2x&=20\\\\
x&=10
\end{aligned}

The x intercept is 10.

It has coordinates (10, \ 0).

Find the y intercept and x intercept of the line 3x-4y=24.

**Substitute ** x=0 ** into the equation of the line.**

3(0)-4y=24

** Solve the equation to find the ** \bf{y}

\begin{aligned}
-4y&=24\\\\
y&=-6
\end{aligned}

The y intercept is -6 .

It has coordinates (0, \ -6).

**Substitute ** y=0 ** into the equation of the line.**

3x-4(0)=24

**Solve the equation to find the ** \bf{x} ** intercept**.

\begin{aligned}
3x&=24\\\\
x&=8
\end{aligned}

The x intercept is 8.

It has coordinates (8, \ 0).

James is measuring the height of an ice sculpture as it melts.

He thinks the height, h \ cm, can be modelled using the equation h=50-2t, where t is the number of hours after the sculpture was made.

Find the initial height of the sculpture and the time taken for it to melt completely according to James’ equation.

**Substitute ** t=0 ** into the equation of the line.**

In this problem x is represented by t and y by h.

The initial height is the height at the start of the experiment. At the start of the experiment, no time has passed so t=0.

The initial height of the sculpture is the h intercept when t = 0.

h=50-2(0)

** Solve the equation to find the ** \bf{h}

h=50

The h intercept is 50.

The initial height of the sculpture is 50 \ cm.

**Substitute ** h=0 ** into the equation of the line.**

When the sculpture has melted completely, the height of the sculpture would be 0.

The time taken for the sculpture to melt completely is the t intercept when h = 0.

0=50-2t

**Solve the equation to find the ** \bf{t} ** intercept**.

\begin{aligned}
2t&=50\\\\
t&=25
\end{aligned}

The t intercept is 25.

It takes 25 hours for the sculpture to melt completely.

**Substituting the wrong value for zero**

A common error is to think that the y intercept is when y = 0.

It is important to remember that when y = 0, the line will be crossing the x axis and therefore will give the x intercept.

**Forgetting to state the coordinates when asked**

If an exam question asks for the y intercept or x intercept, just the value where the line crosses the axes is appropriate. However, sometimes the question will ask for the coordinates of the y intercept. In this case the answer must be given in the form (0, \ c), or (a, \ 0) for the coordinates of the x intercept. ** **

**Confusing the intercept with the gradient**

When the line is in the form y=mx+c, a common error is to confuse the y intercept, c with the gradient or slope of a line, m. The y intercept will have coordinates (0, \ c) and the x intercept will have coordinates (-\frac{c}{m}, \ 0).

1. State the coordinate of the y intercept of the line y=3x-2.

(-2,0)

(0,-2)

(3,0)

(0,3)

The coordinate of the y intercept of a line in the form y=mx+c will be (0,c).

2. Find the coordinate of the x intercept of the line y=3x-6.

(2,0)

(0,2)

(-2,0)

(-6,0)

Substitute y=0 to give

\begin{aligned} 0&=3x-6\\\\ 3x&=6 \\\\ x&=2 \end{aligned}

3. The equation of a line is given as y=8-3x.

Find the y intercept and x intercept of the line.

y intercept = \frac{8}{3}, \ x intercept = 8

y intercept = 8, \ x intercept = -3

y intercept = 8, \ x intercept = -\frac{8}{3}

y intercept = 8, \ x intercept = \frac{8}{3}

When x=0, \ y=8-3(0)=8

When y=0,

\begin{aligned} 0&=8-3x\\\\ 3x&=8 \\\\ x&=\frac{8}{3} \end{aligned}

4. The equation of a line is given as x-3y=9.

Find the y intercept and x intercept of the line.

y intercept = -3, \ x intercept = 9

y intercept = 9, \ x intercept = -3

y intercept = -\frac{1}{3}, \ x intercept = 9

y intercept = 9, \ x intercept = -\frac{1}{3}

When x=0,

\begin{aligned} -3y&=9\\\\ y&=-3 \end{aligned}

When y=0,

\begin{aligned} x-3(0)&=9\\\\ x&=9 \end{aligned}

5. The equation of a line is given as 5x-4y=10.

Find the y intercept and x intercept of the line.

y intercept = 2, \ x intercept = -2.5

y intercept = -2.5, \ x intercept = 2

y intercept = -\frac{2}{5}, \ x intercept = \frac{1}{2}

y intercept = \frac{1}{2}, \ x intercept = -\frac{2}{5}

When x=0,

\begin{aligned} 5(0)-4y&=10\\\\ -4y&=10\\\\ y&=-2.5 \end{aligned}

When y=0,

\begin{aligned} 5x-4(0)&=10\\\\ 5x&=10\\\\ x&=2 \end{aligned}

6. An object is projected vertically upwards and its velocity, v, is modelled by the equation v=14-10t, where t is the time in seconds after its initial projection.

Find the time when the object reaches its maximum height.

1.4 seconds

14 seconds

10 seconds

0.71 seconds

Maximum height occurs when v = 0, which is the t intercept of the line equation.

\begin{aligned} 0&=14-10t\\\\ 10t&=14\\\\ t&=1.4 \end{aligned}

1. The cost £C of hiring a taxi for a journey of m miles is given by the formula,

C=0.6m+5.The cost is plotted on the following set of axes.

(a) State the y intercept of the line.

(b) Give an interpretation of the y intercept.

**(2 marks)**

Show answer

(a) 5

**(1)**

(b) The price of hiring the taxi before it has travelled any distance / a fixed cost added to the price of each journey.

**(1)**

2. A line has the equation 6x-3y=12.

(a) Find the y intercept of the line.

(b) Find the x intercept of the line.

**(4 marks)**

Show answer

(a)

Substituting x=0.

**(1)**

Solving to give y = – 4.

**(1)**

(b)

Substituting y=0.

**(1)**

Solving to give 2.

**(1)**

3. The line L passes through the point (3,5) and has gradient 2.

The line crosses the x axis at point A.

Write down the coordinates of point A.

**(4 marks)**

Show answer

Method using the point (3,5) and gradient of 2 to find the equation.

**(1)**

Equation of y=2x-1 found.

**(1)**

Substituting y=0.

**(1)**

Solving to give x=\frac{1}{2} \ \text{or} \ (\frac{1}{2},0).

**(1)**

You have now learned how to:

- Find the y intercept and x intercept of straight line graphs

Prepare your KS4 students for maths GCSEs success with Third Space Learning. Weekly online one to one GCSE maths revision lessons delivered by expert maths tutors.

Find out more about our GCSE maths revision programme.