One to one maths interventions built for KS4 success

Weekly online one to one GCSE maths revision lessons now available

In order to access this I need to be confident with:

Prime factors Index notation Factor trees Highest common factorFactors and multiples

Venn diagrams

This topic is relevant for:

Here we will learn about the **lowest common multiple** including how to calculate the lowest common multiple, use the lowest common multiple, and recognise when to calculate the lowest common multiple to answer complex worded problems.

Their are also lowest common multiple worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

The **lowest common multiple** or least common multiple (LCM) is the smallest integer (whole number) that belongs to the multiplication table of two or more composite numbers.

**Lowest **meaning smallest number

**Common **meaning shared between two or more numbers

**Multiple **meaning the product of two numbers (times tables)

E.g.

Find the LCM of 4 and 6.

Let’s start by writing the multiples of 4 and 6

We can see that the smallest positive integer that occurs in each list is 12,

hence the **lowest common multiple** of 4 and 6 is **12**.

NOTE: 24 occurs in both lists so is a common multiple, but not the lowest common multiple.

Calculating the** lowest common multiple **becomes more complicated for larger numbers as listing the multiples of each number is very time consuming.

To make it easier we utilise the **prime factors** of the number.

The fundamental theorem of arithmetic states that each number greater than 1 is either a prime number or can be written by a product of primes.

This means that **every number has a unique set of prime factors**.

We can use **prime factors** and a **Venn diagram** to calculate the **lowest common multiple.**

To do this we need to write out the prime factorisation of each number fully (without any powers) and then put the numbers into the Venn diagram by looking for pairs.

Here, we have the prime factors of 12 and 30.

- In the left circle are the prime factors of 12 (2, 2, and 3).
- In the right circle, we have the prime factors of 30 (2, 3, and 5).
- The dark orange section represents the prime factors of 12 that are not prime factors of 30 (which is just the prime factor of 2).
- The light orange section represents the prime factors of 30 that are not prime factors of 12 (which is just the prime factor of 5).
- The intersection represents the prime factors of 12 and 30 (2 and 3).
- The highest common factor for 12 and 30 is 2 × 3 = 6.

The **lowest common multiple** of **12** and **30** is equal to the **product of all the factors viewed in the Venn diagram**.

The **lowest common multiple** to be 2 × 2 × 3 × 5 =** 60**.

In order to calculate the lowest common multiple for two or more numbers:

**State the product of prime factors of each number, not in index form****Write all the prime factors into the Venn diagram for each number****Multiply each prime factor in the Venn diagram to find the LCM**

Get your free lowest common multiple worksheet of 20+ multiples questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free lowest common multiple worksheet of 20+ multiples questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREE

Calculate the lowest common multiple of 18 and 24.

**State the product of prime factors of each number, not in index form**

Using prime factorization we can write 18 and 24 as a product of prime factors.

18 = 2 × 3 × 3

24 = 2 × 2 × 2 × 3

2**Write all the prime factors into the Venn diagram for each number**

3**Multiply each prime factor in the Venn diagram to find the LCM**

LCM = 3 × 2 × 3 × 2 × 2 = 72

Calculate the lowest common multiple of 14 and 56.

**State the product of prime factors of each number, not in index form**

14 = 2 × 7

56 = 2 × 2 × 2 × 7

**Write all the prime factors into the Venn diagram for each number**

**Multiply each prime factor in the Venn diagram to find the LCM**

LCM = 2 × 7 × 2 × 2 = 56

Given that 90 = 2 × 3^{2} × 5 in exponent form, work out the lowest common multiple of 54 and 90.

**State the product of prime factors of each number, not in index form**

To state the product of prime factors of 54, we can use a factor tree:

54 = 2 × 3 × 3 × 3

90 = 2 × 3 × 3 × 5

**Write all the prime factors into the Venn diagram for each number**

**Multiply each prime factor in the Venn diagram to find the LCM**

LCM = 3 × 2 × 3 × 3 × 5 = 270

Calculate the lowest common multiple of 12, 20, and 32.

**State the product of prime factors of each number, not in index form**

12 = 2 × 2 × 3

20 = 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

**Write all the prime factors into the Venn diagram for each number**

**Multiply each prime factor in the Venn diagram to find the LCM**

LCM = 2 × 2 × 2 × 2 × 2 × 3 × 5 = 480

Calculate the lowest common multiple of 35 and 72.

**State the product of prime factors of each number, not in index form**

35 = 5 × 7

72 = 2 × 2 × 2 × 3 × 3

**Write all the prime factors into the Venn diagram for each number**

**Multiply each prime factor in the Venn diagram to find the LCM**

LCM = 5 × 7 × 2 × 2 × 2 × 3 × 3 = 35 × 72 = 2520

Two buses leave the depot at 10am. Bus A takes 36 minutes to return back to the depot, Bus B takes 42 minutes to return back to the depot. How long is it before both buses are back at the depot at the same time?

**State the product of prime factors of each number, not in index form**

36 = 2 × 2 × 3 × 3

42 = 2 × 3 × 7

**Write all the prime factors into the Venn diagram for each number**

**Multiply each prime factor in the Venn diagram to find the LCM**

LCM = 2 × 3 × 2 × 3 × 7 = 252 minutes

To answer the question:

252 minutes = 4 hours and 12 minutes

10am + 4 hours 12 minutes = 2:12pm

**Calculating the highest common factor instead**

A very common misconception is mixing up the lowest common multiple with the highest common factor. It is therefore important that you are confident with the definition of factors and multiples.

**Calculating a × b**

Multiplying the two numbers ‘a’ and ‘b’ given in the question will achieve a common factor as each number is a factor of the total. However, this may not be the lowest common multiple.

To check this, you can calculate the highest common factor of the two numbers (see the lesson on the highest common factor) then divide the value for ‘**ab**‘ by the highest common factor. If the highest common factor is 1, then this will return the same number for your lowest common multiple.

**Not multiplying the factors in the intersection**

The factors in the intersection of the Venn diagram are used to find the highest common factor. This leaves the other factors “unused” and therefore the misconception arises that these numbers generate the lowest common multiple.

Take example 6. The lowest common multiple will be incorrectly calculated as LCM = 2 × 3 × 7 = 42

1. Calculate the lowest common multiple of 42 and 70.

2940

210

14

420

42 = 2 × 3 × 7
70 = 2 × 5 × 7

LCM = 2 × 3 × 5 × 7 = 210

2. Calculate the lowest common multiple of 38 and 76.

38

2888

76

19

38 = 2 × 19
76 = 2 × 2 × 19

LCM = 2 × 2 × 19 = 76

3. Given that 68 = 2^{2} × 17, calculate the lowest common multiple of 24 and 68.

408

1632

4

816

24 = 2 × 2 × 2 × 3

LCM = 2 × 2 × 2 × 3 × 17 = 408

4. Calculate the lowest common multiple of 10, 25, and 45.

11250

5

450

2250

10 = 2 × 5
25 = 5 × 5
45 = 3 × 3 × 5

LCM = 2 × 3 × 3 × 5 × 5 = 450

5. Calculate the lowest common multiple of 16 and 45.

144

1440

1

720

16 = 2 × 2 × 2 × 2
45 = 3 × 3 × 5

LCM = 2 × 2 × 2 × 2 × 3 × 3 × 5 = 720

6. Two buckets of water are leaking. Bucket A drips water every 16 seconds, whilst bucket B drips water every 18 seconds. If they both start dripping water at the same time, what is the amount of time that will go by before they both drip water again at the same time?

144 mins

2 secs

1 min 12 secs

2 mins 24 secs

16 = 2 × 2 × 2 × 2
18 = 2 × 3 × 3

LCM = 2 × 2 × 2 × 2 × 3 × 3 = 144

144 seconds = 2 mins 24 secs

1. Doug is making cheese burgers for a party. Bread rolls are sold in packs of 6 , burgers are sold in packs of 8 , and cheese slices are sold in packs of 10 . Doug wants to buy the minimum number of each item so he can make each cheese burger the same, with no leftovers. How many of each item should he buy?

**(5 marks)**

Show answer

6 = 2 \times 3, 8 = 2 \times 2 \times 2 and 10 = 2 \times 5

**(1)**

LCM (6, 8, 10) = 3 \times 2 \times 2 \times 2 \times 5 = 120

**(1)**

120 \div 6 = 20 packs of bread rolls

**(1)**

120 \div 8 = 15 packs of burgers

**(1)**

120 \div 10 = 12 packs of cheese

**(1)**

2. The machinery in a factory produces a lot of noise. A heavy metal hammer pounds every 12 seconds, an alarm repeats every 18 seconds and a belt clicks every 32 seconds. If they all make a synchronised sound, how many minutes will have passed before they all make a sound together again?

**(4 marks)**

Show answer

At least two of:

Prime factors of 12 = 2 \times 2 \times 3 ,

Prime factors of 18 = 2 \times 3 \times 3 ,

Prime factors of 32 = 2 \times 2 \times 2 \times 2 \times 2

**(1)**

**(1)**

LCM = 288 seconds

**(1)**

288 \div 60 = 4.8 minutes (or 4 minutes, 48 seconds)

**(1)**

3. Two numbers have a LCM of 175 and a HCF of 5. What are the two numbers?

**(4 marks)**

Show answer

**(1)**

175\div 5 = 35 For

**(1)**

35 = 5 \times 7, therefore:

**(1)**

5 \times 5 = 25 and 5 \times 7 = 35

… 25 and 35

**(1)**

You have now learned how to:

- Use the concepts and vocabulary of prime numbers, factors (or divisors), multiples, common factors, common multiples, highest common factor, lowest common multiple, prime factorisation, including using product notation and the unique factorisation property

- Venn diagrams
- Powers and roots
- Highest common factor

Prepare your KS4 students for maths GCSEs success with Third Space Learning. Weekly online one to one GCSE maths revision lessons delivered by expert maths tutors.

Find out more about our GCSE maths revision programme.

x
#### FREE GCSE Maths Scheme of Work Guide

Download free

An essential guide for all SLT and subject leaders looking to plan and build a new scheme of work, including how to decide what to teach and for how long

Explores tried and tested approaches and includes examples and templates you can use immediately in your school.