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Here we will learn about angles in a pentagon, including finding the sum of the interior angles and solving problems involving interior angles and exterior angles.

There are also angles in a pentagon* *worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

**Angles in a pentagon** are the angles in a **five**–**sided** **polygon** (2D shape).

**Regular****pentagons**have five equal (congruent) sides, five vertices and five equal**interior angles**. We can refer to this as a convex pentagon because all of the angles are less than 180^{\circ}.

- An
**irregular****pentagon**has 5 sides that are not all equal, and 5 interior angles that are not all equal.

**Sum of interior angles** of a **pentagon **is \bf{540^{\circ}}.

**Sum of exterior angles** of a** pentagon **is \bf{360^{\circ}}.

We need to be able to solve problems involving angles in a **pentagon**.

To do this we need to work with the **interior** and **exterior** angles of a **pentagon**.

A pair of **interior** and **exterior** angles of all polygons add to 180^{\circ} because they form a straight line. They are supplementary angles.

**Interior angles**of a**pentagon**are the angles inside the 2D shape, formed when two sides of the shape meet.

We can find the**sum of the interior angles**of a pentagon, hexagon or any**polygon**using the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

A pentagon has 5 sides, so n=5 .

\begin{aligned} \text{Sum of interior angles of a pentagon} & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

To find**one interior angle**of a**regular pentagon**we can divide the**sum of the interior angles**by the number of sides, in this case, 5.

**Step-by-step guide:** Interior angles of a polygon

**Exterior angles**of a**pentagon**are the angles between the**pentagon**and the extended line from the next side.

The**sum of the exterior angles**of any**polygon**is always 360^{\circ}.

To find each of the**exterior angles**of a**regular****pentagon**we can use the formula,

\text{Exterior angle of a regular polygon}=\frac{360}{n}, where n is the number of sides.

Alternatively, if we know the size of the**exterior**angle of a regular polygon, we can use a rearrangement of the above formula to identify the number of sides the regular polygon has.

\text{number of sides}=\frac{360}{\text { exterior angle }}

**Step-by-step guide:** Exterior angles of a polygon

In order to solve problems involving angles in a pentagon:

**Identify if the pentagon is regular or irregular.****Identify what the question is asking for.****Solve the problem using the information you have gathered**.

Get your free angles in a pentagon worksheet of 20+ angles in polygons questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free angles in a pentagon worksheet of 20+ angles in polygons questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREE**Angles in a pentagon** is part of our series of lessons to support revision on **angles in polygons**. You may find it helpful to start with the main angles in polygons lesson for a summary of what to expect, or use the step by step guides below for further detail on individual topics. Other lessons in this series include:

Below is a regular pentagon. Find the angle marked x.

**Identify if the pentagon is regular or irregular.**

The question tells us that this is a regular pentagon. This means the sides of the pentagon are equal and the interior angles are equal.

2**Identify what the question is asking for.**

The question wants us to find the angle x, which is one of the five exterior angles of this pentagon.

3**Solve the problem using the information you have gathered.**

To find the size of the exterior angles of a regular pentagon we can use the formula,

\text{Exterior angle of a regular polygon}=\frac{360}{n}, where n is the number of sides.

So, the missing angle can be calculated as

x=\frac{360}{5}=72^{\circ} .

So, the exterior angle of a pentagon equals 72^{\circ}.

What is the sum of the interior angles of a pentagon?

**Identify if the pentagon is regular or irregular.**

The question does not clarify whether the pentagon is regular or irregular, however, this doesn’t matter in the context of the question. The sum of the interior angles of a pentagon will be the same whether it is regular or irregular.

**Identify what the question is asking for.**

The question asks us to calculate the sum of the internal angles of a pentagon.

**Solve the problem using the information you have gathered.**

To calculate the sum of the interior angles of a pentagon, octagon or any polygon we can use the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the interior angle of a pentagon can be calculate as,

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

Below is a regular pentagon. Find the angle marked x.

**Identify if the pentagon is regular or irregular.**

The question tells us that this is a regular pentagon.

**Identify what the question is asking for.**

The question wants us to find the angle x, which is one of the five interior angles of this pentagon.

**Solve the problem using the information you have gathered.**

To find the size of an interior angle of any pentagon we need to first calculate the sum of the interior angles.

To calculate the sum of the interior angles of any polygon we can use the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the interior angle of a pentagon can be calculate as,

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

Now that we know the angles inside a pentagon sum to 540^{\circ}, we can divide this by the number of sides, in this case 5, to find the size of one interior angle.

So, the missing angle can be calculated as

x=\frac{540}{5}=108^{\circ} .

Hence, the missing angle measures 108^{\circ}.

Below is a polygon. Find the size of the missing angle x.

**Identify if the pentagon is regular or irregular.**

The question does not state whether the polygon is regular or irregular, however, the interior angles of the pentagon are not equal, so it must be irregular.

**Identify what the question is asking for.**

The question asks us to find the missing interior angle.

**Solve the problem using the information you have gathered.**

To find the size of an interior angle of any pentagon we need to first calculate the sum of the interior angles.

To calculate the sum of the interior angles of any polygon we can use the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the interior angle of a pentagon can be calculate as,

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

Now that we know the angles inside a pentagon sum to 540^{\circ}, we can subtract the interior angles we know, to find the missing value.

x=540-(112+94+89+98)=147^{\circ}

Below is an irregular polygon. Find the size of the missing angle x.

**Identify if the pentagon is regular or irregular.**

The question states that the polygon is irregular.

**Identify what the question is asking for.**

The question asks us to find the missing exterior angle.

**Solve the problem using the information you have gathered.**

To find the size of the exterior angle, x, we need to find the missing interior angle that corresponds to it, labelled y on the diagram below.

To find the size of an interior angle of any pentagon we need to first calculate the sum of the interior angles.

To calculate the sum of the interior angles of any polygon we can use the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the interior angle of a pentagon can be calculate as,

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

Now that we know the angles inside a pentagon sum to 540^{\circ}, we can subtract the interior angles we know, to find the missing value.

y=540-(92+94+125+118)=111^{\circ}

Now that we know the value of the interior angle corresponding to x, we can use the fact that the **interior** and **exterior **angles of all polygons add to 180^{\circ} because they form a straight line, to calculate the exterior angle.

So, x=180-111=69^{\circ}.

The diagram shows a shape formed by two regular polygons.

Find the size of the angle labelled x.

**Identify if the pentagon is regular or irregular.**

The question states that both polygons in the diagram are regular polygons.

**Identify what the question is asking for.**

The questions asks us to find the size of the angle x, which is formed on the exterior of the two regular pentagons.

**Solve the problem using the information you have gathered.**

To find the size of the angle, x, we need to find the missing interior angles that meet at the point.

To find the size of an interior angle of any pentagon we need to first calculate the sum of the interior angles.

To calculate the sum of the interior angles of any polygon we can use the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the interior angle of a pentagon can be calculate as,

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

Now that we know the angles inside a pentagon sum to 540^{\circ}, we can divide this by the number of sides, in this case 5, to find the size of one of the interior angles.

So, the interior angles are \frac{540}{5}=108^{\circ}.

Now that we know that the two interior angles are 108^{\circ} each, we can use the angle fact ‘angles around a point sum to 360^{\circ} ’ to find the angle x.

So, x=360-(108+108)=144^{\circ}.

**Regular and irregular polygons**

It is important to correctly identify whether a polygon is regular or irregular, using the information given in the question or on the diagram. Do not assume one or the other.

**Using the formulae incorrectly**

Whether a polygon is regular or irregular will determine how the formulae for working with interior and exterior angles can be used. For example, the formula

\text{Exterior angle of a regular polygon}=\frac{360}{n}, where n is the number of sides.

Can only be used to find the size of exterior angles of regular polygons, where all exterior angles are equal.

1. Calculate the exterior angle of a regular pentagon.

72^{\circ}

108^{\circ}

540^{\circ}

180^{\circ}

We can find the size of an exterior angle of any regular polygon using the formula,

\text{Exterior angle of a regular polygon}=\frac{360}{n}, where n is the number of sides.

So, the size of exterior angles of a regular pentagon can be calculated as \frac{360}{5}=72^{\circ}.

2. Calculate the sum of the interior angles of a 5 sided polygon.

72^{\circ}

108^{\circ}

540^{\circ}

900^{\circ}

We can find the sum of the interior angles of any polygon using the formula

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the sum of the interior angles of a pentagon can be calculated as

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

3. The diagram shows a pentagon. Calculate the missing angle x.

108^{\circ}

72^{\circ}

483^{\circ}

123^{\circ}

To find the value of one interior angle of an irregular polygon, we first need to calculate the sum of the interior angles of the polygon.

We can find the sum of the interior angles of any polygon using the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the sum of the interior angles of a pentagon can be calculated as,

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

Now that we know the angles inside the pentagon sum to 540^{\circ}, we can subtract the interior angles we know, to find the missing value.

x=540-(54+92+135+136)=123^{\circ}

4. The diagram shows a pentagon. Calculate the missing angle x.

540^{\circ}

108^{\circ}

72^{\circ}

116^{\circ}

The interior and exterior angles of any polygon sum to 180, so,

x=180-64=116^{\circ}.

5. The diagram shows a pentagon. Calculate the missing angle x.

108^{\circ}

72^{\circ}

57^{\circ}

540^{\circ}

To find the size of the exterior angle, x, we need to find the missing interior angle that corresponds to it. To find the size of an interior angle of any pentagon we need to first calculate the sum of the interior angles.

To calculate the sum of the interior angles of any polygon we can use the formula

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the interior angle of a pentagon can be calculate as,

\begin{aligned} & =(n-2) \times 180 \\\\ & =(5-2) \times 180 \\\\ & =3 \times 180 \\\\ & =540^{\circ} \end{aligned}

Now that we know the angles inside a pentagon sum to 540^{\circ}, we can subtract the interior angles we know, to find the missing value.

y=540-(92+54+135+136)=123^{\circ}

Now that we know the value of the interior angle corresponding to x, we can use the fact that the interior and exterior angles of all polygons add to 180^{\circ} because they form a straight line, to calculate the exterior angle.

So, x=180-123=57^{\circ}.

6. The diagram below is formed by three regular polygons. Find the size of the missing value x.

36^{\circ}

108^{\circ}

72^{\circ}

144^{\circ}

To find the size of the angle, x, we need to find the missing interior angles that meet it at the point.

To find the size of an interior angle of any pentagon we need to first calculate the sum of the interior angles.

To calculate the sum of the interior angles of any polygon we can use the formula,

\text{Sum of interior angles}=(n-2) \times 180, where n is the number of sides.

So, the interior angle of a pentagon can be calculate as,

Now that we know the angles inside a pentagon sum to 540^{\circ}, we can divide this by the number of sides, in this case 5, to find the size of one of the interior angles.

So, the interior angles are

\frac{540}{5}=108^{\circ}.

Now that we know that the three interior angles are 180^{\circ} each, we can use the angle fact ‘angles around a point sum to 360^{\circ} ’ to find the angle x.

So, x=360-(108+108+108)=36^{\circ}.

1. Here is a regular polygon with 5 sides. Calculate the size of the interior angles of this shape.

**(2 marks)**

Show answer

(5-2)\times 180 \div 5

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2. The diagram shows a pentagon. Find the missing angle x.

**(3 marks)**

Show answer

(5-2)\times 180=540

**(1)**

**(1)**

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3. The exterior angle of a regular polygon is 72^{\circ}. Find the number of sides the polygon has, hence, name the shape.

**(2 marks)**

Show answer

\frac{360}{72}=5

**(1)**

Pentagon

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You have now learned how to:

- Find the exterior angle of a pentagon
- Find the the sum of the interior angles of a pentagon
- Find the value of an interior angle of a pentagon
- Solve problems involving angles in pentagons

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