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Here we will learn about ratio, including simplifying ratios, dividing a ratio into a quantity, ratios to fractions, and problem solving with ratios.

There are also ratio worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

**Ratio** is a **relationship between two or more quantities** showing the number of times one is contained within the other(s).

Ratios are written in the form a:b , which is said “ a \ to \ b ” where a and b are normally integers, fractions or decimals.

They can also be represented in the form \frac{a}{b} (a fraction).

The **order** of the quantities in the ratio is important.

E.g.

If there are 10 boys in a class and 15 girls, we can say that the **ratio of boys to girls** is 10:15 which we say as “ 10 to 15 ”.

Ratios are used in **real life** very frequently.

We use ratios to bake cakes, convert currencies when you go on holiday, determine the shutter speed on a camera, draw scale models of buildings, calculate the speed of a car, determine the aspect ratio of television screens, read maps and many many more!

In the GCSE mathematics curriculum, topics that use ratios include the above as well as trigonometry, calculating the gradient of a line, measuring density or pressure of an object, calculating best value for money, speed calculations, and even within sampling techniques.

**See also:** 15 Ratio questions

We can use a variety of methods when interpreting ratios:

A ratio can be written as a part to part and a part to whole.

We explore how to write a relationship as a ratio, manipulate ratios and real life ratio problems

E.g.

30 people attend a fitness class. 23 are female and the rest are male.

Write the part to part ratio of males to females.

Solution 7:23

**Step-by-step guide:** How to work out ratio

Writing a ratio in its simplest form allows us to carry out calculations with ratios that are easier mathematically as the numbers we use are smaller.

We explore how to simplify a ratio, equivalent ratios and more real life ratio problems.

E.g.

Simplify fully the ratio 14:21:35 .

Solution 2:3:5

**Step-by-step guide:** Simplifying ratios

Dividing a quantity into a ratio can help us find how much the value of one or each part of a ratio is worth.

We explore how to divide a quantity into a ratio and use this to solve real life problems.

E.g.

Divide £50 into the ratio of 2:3 .

Solution £20:£30

**Step-by-step guide:** Dividing ratios

When we express a ratio as a fraction, we need to know either the value of each part of the ratio or the total amount and the value of all but one part of the ratio (of which we need to find).

We explore using ratios to find fractions, and using fractions to find ratios.

E.g.

The ratio of red to blue counters is 3:4 . What fraction of the counters are blue?

Solution \frac{4}{7}

**Step-by-step guide:** Ratio to fraction

Writing a ratio as fractions can be extended to then writing it as percentages.

E.g.

The ratio of green counters to yellow counters is 1:3. What percentage of the counters are yellow?

Solution: \frac{3}{4}=75%. 75% of the counters are yellow.

**Step-by-step guide:** Ratio to percentage

Comprehension and a wide range of subject knowledge is required to solve problems involving ratios.

We explore how to set up and solve problems involving ratios.

E.g.

Jenny is x years old and Suzie is four times as old as Jenny. If the difference between their ages is 15 , how old is each person? Write your answer as a ratio of Jenny’s age to Suzie’s age.

Solution 5:20

**Step-by-step guide:** Ratio problem solving

E.g.

Square A has an area of 9cm^2 . Square B has a perimeter of 20cm . Write the ratio of their side lengths in the form 1:n

Solution 1:\frac{5}{3}

**Step-by-step guide:** Ratio scale

Get your free ratio worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free ratio worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEQuestions may ask you to write a situation as a ratio.

For example, a class has 12 boys and 17 girls, write the number of boys and the number of girls as a ratio. The answer would be 12:17.

You may be given a ratio and asked to use the ratio to solve problems.

For example, a purple paint in made by mixing red and blue paint in the ratio 2:3. Use the ratio to work out how many litres of red and blue paint are needed to make 40 litres of purple paint.

Red:Blue=2:3 which has 5 parts in total. The total is the amount of purple paint.

We need to scale up the ratio so that there are 40 litres of purple paint by multiplying each part by 8.

Therefore there will be 16 litres of red paint and 24 litres of blue paint needed to make 40 litres of purple paint.

You may be asked to express a ratio in the form “n:1” or “1:n”. This would involve scaling the ratio so that one of the parts is 1.

For example,

Express the ratio 12:4 is the ratio of n:1. This would mean we have to scale the four so that it becomes 1. We can do this by dividing both parts of the ratio by 4 to become 3:1, with n= 3.

Some ratio problems involve points on a straight line and the ratios of the lengths of the different sections.

For example,The points A, B, C and D lie in order on a straight line.

AB:BD=2:5 and AC:CD=3:2

Then we add the ratio parts.

The total for the ratio parts needs to be the same, so we scale up using the lowest common multiple.

If we write the new ratios onto the line, we can then see what the different sections of the line are.

The sections BC will be 21-10=11.

Or alternatively BC can be calculated by 25-14=11.

The final answer is

AB:BC:CD=10:11:14

Ratio problems may also involve coordinates.

For example,

Points A and B have the coordinates (1,1) and (11,6) respectively.

Point C lies on the line AB such that AC:CB=3:2

Find point C.

The ratio 3:2 has 5 parts. We need to split the line AB into 5 equal parts. AC will be \frac{3}{5} of the line and CB will be \frac{2}{5} of the line.

We can do this by looking at the x-coordinates and the y-coordinates separately.

The distance in the x direction is 11 - 1 = 10

So the x-coordinate will be 1 + \frac{3}{5} ✕ 10 = 7

The distance in the y direction is 6 - 1 = 5

So the x-coordinate will be 1 + \frac{3}{5} ✕ 5 = 4

So point C is at (7,4).

The ratio of people who prefer skiing holidays to beach holidays is expressed as a bar model. State the ratio of people who prefer skiing holidays to the total number of people.

**State the number of shares in the required part of the ratio.**

The Beach has 3 parts.

2**State the number of shares in the other part(s) as required.**

The total number of parts is 1+3=4

3**Write the ratio using a colon : (and simplify when necessary).**

Use a bar model to simplify the ratio 12:6

**Calculate the highest common factor of the parts of the ratio.**

Representing the ratio 12:6 as a bar model, we have

Where purple represents 12 shares, and yellow represents 6 shares.

HCF(12,6)=6

**Divide each part of the ratio by the highest common factor.**

As the highest common factor is 6 , we divide the bar above into six bars containing the same amount of purple shares, and yellow shares.

Each bar is the ratio 2:1 .

**Solution**: 2:1

Shirley wants to make shortbread for a party. The recipe requires flour, butter and sugar in the ratio 3:2:1 .

Shirley has 610g of flour, 450g of butter, and 750g of sugar.

Does she have enough of each ingredient to make 1.2kg of shortbread?

The weight of each ingredient in a shortbread is shown as a bar model below.

**Add the parts of the ratio together.**

Adding up the number of shares in the bar we have 3+2+1=6

**Divide the quantity by the sum of the parts.**

1.2kg is equal to 1200g (multiply by 1000 ).

1200 \div 6=200g per share.

**Multiply the share value by each part in the ratio.**

Looking at each ingredient, we have

Flour = 200 \times 3=600g

Butter = 200 \times 2=400g

Sugar = 200 \times 1=200g

**Answer**: Yes she has enough of each ingredient.

The diagram below shows the days of the month that were above or below 20^{\circ}C on average.

Complete the bar model to show the fraction of days in the month at were above 20^{\circ}C

**Add the parts of the ratio for the denominator.**

By counting the number of days in the month, there are 31 days.

We therefore need to split the bar into 31 equal shares.

**State the required part of the ratio as the numerator.**

The first number in the ratio represents the number of days above 20^{\circ}C and so we need to colour in 11 of these shares in red, the rest are blue.

This means that 11 out of the 31 days were warmer than 20^{\circ}C and so the fraction is \frac{11}{31} .

**Solution:** \frac{11}{31}

The ratio of a:b=3:2 . The ratio of b:c=3:5 . What is the ratio of a:c ?

**Identify key information within the question.**

The ratio of a:b=3:2 . The ratio of b:c=3:5 . What is the ratio of a:c ?

Drawing these ratios using bar models, we have:

**Know what you are trying to calculate.**

Instinctively, you may think that the ratio of a:c is 3:5 but this would be incorrect. We need to calculate the ratio of a:c when the number of shares of b are the same for each ratio.

We therefore need to calculate the lowest common multiple of the two values of b, find the equivalent ratios of a:b and b:c when b is the same value, then we can state the ratio a:c.

**Use prior knowledge to structure a solution.**

The first five multiples of 2 and 3 are:

Multiples of 2 = 2, 4, {\color{red} 6}, 8, 10

Multiples of 3 = 3, {\color{red} 6}, 9, 12, 15

LCM(2,3) = {\color{red} 6}.

We now find the equivalent ratios.

Multiplying both parts of the ratio of a:b by 3 , we get the ratio 9:6 .

Multiplying both parts of the ratio of b:c by 2 , we get the ratio 6:10

As the value of b is the same for both ratios, the ratio for a:c can be stated by counting the number of shares in each part.

a:c=9:10 .

This ratio is already in its lowest terms and so cannot be simplified further.

A map has the scale of 1cm:2km . The distance between two points on the map is 3.5cm . Calculate the distance between the two points in real life.

**Write down two related quantities from the question / diagram.**

Using a bar model, we can show the ratio of the map to the actual distance as

**Calculate the scale factor / ratio of the two quantities.**

We know that the ratio between the two quantities is 1cm:2km . Remember that these are different units.

**Use the scale factor to determine other scaled values.**

Every 1cm on the map represents 2km in real life and so by multiplying the number of shares by 3.5 , we will calculate the actual distance

Here, 3.5cm on the map is equal to 7km in real life.

**Ratio written in the wrong order**

A common error is to write the parts of the ratio in the wrong order.

E.g.

The number of dogs to cats is given as the ratio 12:13 but the solution is incorrectly written as 13:12 .

**Ratios and fractions confusion**

E.g.

The ratio 2:3 is incorrectly expressed as the fraction \frac{2}{3} and rather than the correct answer of \frac{2}{5} .

This is a misunderstanding of the sum of the parts of the ratio. The sum of all of the parts of the ratio gives us the denominator of the fraction.

**Incorrect value for the numerator**

A common error is to incorrectly state the numerator from the ratio.

E.g.

The number of mugs to glasses in a kitchen is written as the ratio 8:11 respectively. Write the fraction of mugs in the kitchen.

The solution could be incorrectly written as \frac{11}{19} taking the value for the numerator as the number of glasses, not the number of mugs.

The correct answer is \frac{8}{19} .

**Not fully simplified**

A common error is to not write a ratio in its simplest form by not finding the highest common factor.

E.g.

Simplify the ratio 12:18

Dividing both numbers by 2 will leave a ratio of 6:9 . This can be simplified further by dividing by 3 to get the ratio 2:3 , which is the correct answer.

**Not simplifying all parts of the ratio**

When simplifying a ratio with more than two parts, not all of the parts are simplified. For example, “Simplify the ratio 12:6:15 ” is incorrectly written as 2:6:3 as the middle part is not cancelled down.

**Dividing the ratio by each part**

A common error is to divide a value by each part of the ratio.

E.g.

Divide £120 into the ratio 2:3

The incorrect answer if produced by dividing £120 by 2 , and then dividing £120 by 3 to get £60:£40 .

This does not make sense as the ratio is not equivalent to the original.

The correct answers requires that the amount is divided by the sum of the parts in the ratio

120 \div (2+3)=120 \div 5=£24,

then this value multiplied by each part in the ratio

24 \times 2=£48 ,

24 \times 3=£72

**Mixing units**

Make sure that all the units in the ratio are the same.

For example, in example 6 , all the units in the ratio were in millilitres. We did not mix ml and l in the ratio.

**Simplifying the answer**

When sharing a quantity into the ratio, you are finding an equivalent ratio so you do not need to simplify the answer.

1. A musical requires 200 costumes. 140 costumes are allocated to the background dancers whilst the rest are for the starring roles. Write the ratio of the costumes for starring roles to backing dancers in the simplest form.

7:3

7:10

3:7

10:7

200-140=60 starring role costumes

The ratio is therefore 60:140.

The highest common factor of 60 and 140 is 20:

There are 3 shares for starring roles, and 7 shares for background dancers, hence the ratio 3:7.

2. 50 people were asked about their use of social media; everyone participated. 24 boys were asked. Write the ratio of boys to girls who participated in the study in its simplest form.

Use the bar model below to help you.

240:260

12:25

12:13

26:50

Colouring in 24 out of the 50 shares we have

This leaves us with 26 shares that are left white.

The highest common factor of 24 and 26 is 2 .

We can therefore halve the number of shares on each side of the ratio to get

Counting the shares, we now have the ratio of 12:13.

3. A soap “Duo” is made by combining lavender soap with lemon soap. Each bar of soap weighs 330g . If the ratio of lavender to lemon is 4:7 , how many grams of lemon soap are in each bar?

110g

120g

188.6g

210g

As there are 7+4=11 shares within the ratio

330 \div 11=30g per share

The amount of Lemon in the soap is equal to 7 \times 30=210g

4. The fraction of bananas in a bowl is \frac{13}{20} . Calculate the ratio of bananas to other pieces of fruit in the bowl.

13:20

13:7

13:33

7:20

The total number of pieces of fruit is 20 . The number of bananas is 13 . As a bar model, this looks like

The number of other pieces of fruit is therefore 7 (this is calculated by 20-13=7 or counting the number of purple bars above).

The ratio of bananas to other pieces of fruit is therefore 13:7.

5. Mel, Nicole and Orla use a bar model to show their ages.

Orla is 12 years older than Nicole. How old is Mel?

15 \ years

18 \ years

5 \ years

10 \ years

We currently have the ratio 5:6:10.

If Orla is 12 years older than Nicole, and this is 4 shares of the ratio, we have 4 shares equal to 12 years.

1 share is equal to 3 years.

As Mel has 5 shares, 5 \times 3=15 years old.

6. A model soldier is scaled down using a ratio of 5cm:1cm . Given that the height of the soldier in real life is 182cm , calculate the height of the model.

30.33cm \ (2dp)

36.4cm

45.5cm

151.67cm \ (2dp)

Using a bar model, we have the ratio 5:1 drawn as

If the soldier is 182cm in real life, the value of one share within the bar model is equal to 182 \div 5=36.4cm.

This means the height of the model is 36.4cm.

1. An orchestra has 100 musicians. 60\% of them play a string instrument. The ratio of violin players to the other string instruments is 4:11 .

How many musicians play the violin in the orchestra?

**(4 marks)**

Show answer

100 \times 0.60=60

**(1)**

60 \div (4+11)=4

**(1)**

4 \times 4=16

**(1)**

16 violin players

**(1)**

2. A florist sells 3 sizes of rose bouquets: regular, large, and extra large. The regular bouquet contains 5 roses, the large bouquet contains 8 roses, and the extra large bouquet contains 12 roses.

In one February, she sells 16 regular bouquets, 16 large bouquets and 18 extra large bouquets.

(a) How many roses are required for these orders?

(b) The ratio of roses that were used to not used in the bouquets was 8:3. What fraction of the roses were not used in the bouquets?

(c) How many roses were bought in total?

**(5 marks)**

Show answer

(a)

(5 \times 16)+(8 \times 16)+(12 \times 18)

**(1)**

424 roses

**(1)**

(b)

\frac{3}{8+3}=\frac{3}{11}

**(1)**

(c)

424 \div 8 \times 11

**(1)**

583

**(1)**

3. During one weekend, 256 planes depart from an airport to go to France and Spain in the ratio of 3:5 . On a bank holiday weekend, the number of flights increases by 68, giving the new ratio of 4:5.

How many more flights went to France on the bank holiday weekend?

**(6 marks)**

Show answer

256 \div (3+5)=32

**(1)**

32 \times 3=9

**(1)**

256+68=324

**(1)**

324 \div (4+5)=36

**(1)
**

36 \times 4=144

**(1)**

144-96=48

**(1)**

You have now learned how to:

- Use ratio notation, including reduction to simplest form
- Divide a given quantity into 2 parts in a given part: part or part: whole ratio; express the division of a quantity into 2 parts as a ratio
- Understand that a multiplicative relationship between 2 quantities can be expressed as a ratio or a fraction

- Proportion
- Compound measures
- Best buy maths

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#### FREE GCSE maths practice papers (Edexcel, AQA & OCR)

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8 sets of free exam practice papers written by maths teachers and examiners for Edexcel, AQA and OCR.

Each set of exam papers contains the three papers that your students will expect to find in their GCSE mathematics exam.