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Mean, median and mode Grouped frequency table Addition and subtraction Multiplication and divisionHere you will learn about the mean from a frequency table, including what it is and how to calculate it. You will also learn how to find an estimate for the mean from a grouped frequency table.
Students will first learn about mean from a frequency table as part of statistics and probability in 6 th grade.
Mean from a frequency table is when you find the mean average from a data set which has been organized into a frequency table. The frequency is the number of times a number or item is recorded in a data set.
To calculate the mean, find the total of the values and divide the total by the number of values. The number of values is the total frequency. This can be abbreviated to n.
You can use an extra column to help.
Mean is a measure of central tendency. It is a value that can be used to represent a set of data.
For example,
The frequency table shows the number of people living in 16 apartments.
There are 5 apartments with 1 person living there, so calculate 1 \times 5=5
There are 6 apartments with 2 people living there, so calculate 2 \times 6=12
There are 3 apartments with 3 people living there, so calculate 3 \times 3=9
There are 2 apartments with 4 people living there, so calculate 2 \times 4=8
The number of values (n) is the total frequency, here n=16.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{(1\times 5)+(2\times 6)+(3\times 3)+(4\times 2)}{16}=\cfrac{34}{16}=2.125
The mean is 2.125 people.
Use this worksheet to check your grade 6 to 8 studentsβ understanding of mean from a frequency table. 15 questions with answers to identify areas of strength and support!
DOWNLOAD FREEUse this worksheet to check your grade 6 to 8 studentsβ understanding of mean from a frequency table. 15 questions with answers to identify areas of strength and support!
DOWNLOAD FREEWhen the data has been grouped together and put into a grouped frequency table, you cannot find the actual mean because you only have a range of possible values.
Instead you can find an estimate for the mean using the midpoints of each group. You can add more columns to the grouped frequency table to help.
For example,
The frequency table shows the number of correct answers earned on a test by 20 students.
There were 3 people who answered between 0 \text{-}9 questions correctly. As you donβt know the exact number of questions that each of these people got correct, you will use the midpoint of 4.5 questions correct.
You can find the midpoint by adding the smallest value and the largest value together and dividing by 2.
\text{Estimated Mean}=\cfrac{\text{total}}{n}=\cfrac{420}{20}=21
The estimated mean is 21 questions correct.
How does this relate to 6 th grade math?
In order to calculate the mean from a frequency table, you need to:
The frequency table shows the number of goals scored in 10 soccer games. Find the mean number of goals.
You can add an extra column next to the frequency column to help find the subtotals.
2Find the totals.
Find the total of the frequency column, n. Add up the subtotals to find the total.
3Divide the total by \textbf{n}.
The last step is to divide the total by n.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{11}{10}=1.1
The mean is 1.1 goals.
The frequency table shows the number of people on 20 buses. Find the mean number of people.
Multiply the number values by the frequencies.
You can add an extra column next to the frequency column to help find the subtotals.
Find the totals.
Find the total of the frequency column, n. Add up the subtotals to find the total.
Divide the total by \textbf{n}.
The last step is to divide the total by n.
\text{mean}=\cfrac{\text{total}}{n}=\cfrac{191}{20}=9.55
The mean is 9.55 people.
The frequency table shows the ages, in years, of 25 children in a math club. Find the mean age.
Multiply the number values by the frequencies.
You can add an extra column next to the frequency column to help find the subtotals.
Find the totals.
Find the total of the frequency column, n. Add up the subtotals to find the total.
Divide the total by \textbf{n}.
The last step is to divide the total by n.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{123}{25}=4.92
The mean is 4.92 years.
In order to estimate the mean from a grouped frequency table, you need to:
The grouped frequency table shows the number of people in 10 train carriages.
Estimate the mean number of people.
Find the midpoints of the groups.
You do not know the actual number of people in the groups, so use the midpoint.
Find the midpoint by adding the smallest value and the largest value together and dividing by 2. Add a column for the midpoints.
Multiply midpoints by the frequencies.
You can add an extra column next to the frequency column to help find the subtotals.
Find the totals.
Find the total of the frequency column, n. Add up the subtotals to find the total.
Divide the total by \textbf{n}.
The last step is to divide the total by n.
\text{mean}=\cfrac{\text{total}}{n}=\cfrac{110}{10}=11
But remember that this is an estimate for the mean.
The estimated mean is 11 people.
The grouped frequency table shows the ages of 25 people in a department store.
Estimate the mean age.
Find the midpoints of the groups.
You do not know the actual ages in the groups, so use the midpoint.
Find the midpoint by adding the smallest value and the largest value together and dividing by 2. Add a column for the midpoints.
Multiply midpoints by the frequencies.
You can add an extra column next to the frequency column to help find the subtotals.
Find the totals.
Find the total of the frequency column, n. Add up the subtotals to find the total.
Divide the total by \textbf{n}.
The last step is to divide the total by n.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{542.5}{25}=21.7
But remember that this is an estimate for the mean.
The estimated mean is 21.7 marks.
The grouped frequency table shows the weight in grams of 30 potatoes.
Estimate the mean weight. Round your answer to the nearest tenths.
Find the midpoints of the groups.
You do not know the actual weights in the groups, so use the midpoint.
Find the midpoint by adding the smallest value and the largest value together and dividing by 2. Add a column for the midpoints.
Multiply midpoints by the frequencies.
You can add an extra column next to the frequency column to help find the subtotals.
Find the totals.
Find the total of the frequency column, n. Add up the subtotals to find the total.
Divide the total by \textbf{n}.
The last step is to divide the total by n.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{1300}{30}=43.333β¦ = 43.3 \ \text{(to the nearest tenth)}
But remember that this is an estimate for the mean.
The estimated mean is 43.3 \, g.
1. The frequency table shows the number of pets of 15 students. Find the mean number of pets. Give your answer to the nearest hundredth.
You need to multiply the numbers by the frequencies and find the total. Then divide the total by n, the frequency total,
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{19}{15}=1.2666β¦ = 1.27 \ \text{(to nearest hundredth)}
2. The frequency table shows the number of puppies in 21 litters. Find the mean number of puppies. Give your answer to the nearest hundredth.
You need to multiply the numbers by the frequencies and find the total. Then divide the total by n, the frequency total.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{141}{21}=6.714β¦ = 6.71 \ \text{(to nearest hundredth)}
3. The frequency table shows the price of a can of biscuits in 16 different grocery stores. Find the mean price. Give your answer to the nearest tenth.
You need to multiply the numbers by the frequencies and find the total. Then divide the total by n, the frequency total.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{957}{16}=59.81β¦ = 59.8 \ \text{(to nearest tenth)}
4. The grouped frequency table shows the number of children in 17 families. Estimate the mean number of children. Give your answer to the nearest hundredth.
You need to use midpoints. Multiply the midpoints by the frequencies and find the total. Then divide the total by n, the frequency total.
\text{mean}=\cfrac{\text{total}}{n}=\cfrac{53}{17}=3.117β¦ = 3.12 \ \text{(to nearest hundredth)}
5. The grouped frequency table shows numbers of cars at midday in a parking lot over 14 days. Estimate the mean number of cars. Give your answer to the nearest tenth.
You need to use midpoints. Multiply the midpoints by the frequencies and find the total. Then divide the total by n, the frequency total.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{717}{14}=51.214β¦ = 51.2 \ \text{(to nearest tenth)}
6. The grouped frequency table shows weights of 21 newborn babies. Estimate the mean weight of newborn babies. Give your answer to the nearest hundredth.
3.5 toΒ 4
You need to use midpoints. Multiply the midpoints by the frequencies and find the total. Then divide the total by n, the frequency total.
\text{Mean}=\cfrac{\text{total}}{n}=\cfrac{71.75}{21}=3.4166β¦ = 3.42 \ \text{(to nearest hundredth)}
While a frequency table is not a type of graph, the data that is recorded within a frequency table can be used to create graphs, including box plots, histograms, stem-and-leaf plots, dot plots, and many more.
Grouped data is when the data is given in the form of class intervals, such as 0 \text{-}5, 6 \text{-}10, etc. Ungrouped data refers to when the data is given as individual data points or values.
Class intervals are the organized groups of the numerical data. They can have the same or different class widths, but must not overlap.
The standard deviation is a value that summarizes the variation around the mean. It is another measure that can be calculated from the data in frequency tables.
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