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Here we will learn about **alternate angles** including how to recognise when angles are alternate and apply this understanding to solve problems.

There are also angles in parallel lines worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

**Alternate angles** are angles that occur on opposite sides of the transversal line and have the **same size**.

**Alternate angles are equal**:

We can often spot interior alternate angles by drawing a Z shape:

There are **two different types **of alternate angles, **alternate interior angles **and **alternate exterior angles**.

Below are diagrams showing these two variations.

**Alternate interior angles**:

Here, the two angles of

**Alternate exterior angles**:

Here, the two angles of

It is important to notice that the transversal on each diagram is at a different angle but the two angles in each diagram are the same size. As is the case with all diagrams for angles in parallel lines, never use a protractor to find an angle as all the diagrams, unless stated otherwise, are not to scale.

In order to calculate with alternate angles:

**Highlight the angle(s) that you already know.****State the alternate angle, co-interior angle or corresponding angle fact to find a missing angle in the diagram.****Use a basic angle fact to calculate the missing angle.**

Get your free Alternate Angles worksheet of 20+ questions and answers. Includes reasoning and applied questions.

COMING SOONGet your free Alternate Angles worksheet of 20+ questions and answers. Includes reasoning and applied questions.

COMING SOONCalculate the size of the missing angle θ. Justify your answer.

**Highlight the angle(s) that you already know**.

2**State the alternate angle, co-interior angle or corresponding angle fact to find a missing angle in the diagram.**

Here we can label the alternate angle on the diagram as

3**Use a basic angle fact to calculate the missing angle.**

Here as θ is on a straight line with

\[\begin{aligned}
\theta&=180^{\circ}-50^{\circ} \\
\theta&=130^{\circ}
\end{aligned}\]

Calculate the size of the missing angle θ. Justify your answer.

**Highlight the angle(s) that you already know**.

**State the alternate angle, co-interior angle or corresponding angle fact to find a missing angle in the diagram.**

Here we can state the angle

**Use a basic angle fact to calculate the missing angle.**

The angle θ is the alternate angle to the sum of

\[\begin{aligned}
\theta&=56^{\circ}+62^{\circ} \\
\theta&=118^{\circ}
\end{aligned}\]

By working out the value for

**Highlight the angle(s) that you already know**.

Here we know most of the angles so highlight the angles that are going to help you find the value of

Here,

\[\begin{aligned}
3x&=30^{\circ} \\
x&=10^{\circ}
\end{aligned}\]

**Use a basic angle fact to calculate the missing angle.**

Here we can use the sum of angles in a triangle to help us calculate the value for θ. The value for

\[\begin{aligned}
\theta&=180^{\circ}-(100^{\circ}+30^{\circ}) \\
\theta&=50^{\circ}
\end{aligned}\]

**Mixing up angle facts**

There are a lot of angle facts and it is easy to mistake alternate angles with corresponding angles. To prevent this from occurring, think about the alternate angles being on the alternate sides of the line.

**Using a protractor to measure an angle.**

Using a protractor to measure an angle. Most diagrams are not to scale and so using a protractor will not result in a correct answer unless it is a coincidence.

1. Calculate the size of angle \theta .

\theta=76^{\circ}

\theta=256^{\circ}

\theta=84^{\circ}

\theta=104^{\circ}

104^{\circ} and \theta are alternate angles so \theta = 104^{\circ}.

2. Calculate the size of angle \theta.

\theta=103^{\circ}

\theta=38.5^{\circ}

\theta=77^{\circ}

\theta=13^{\circ}

Using alternate angles and angles on a straight line: \theta=180-103=77^{\circ}

3. Find the value of \theta

\theta=63^{\circ}

\theta=117^{\circ}

\theta=79^{\circ}

\theta=101^{\circ}

Using alternate angles, we can see that the angle in the bottom right vertex of the triangle is 38^{\circ} . We can then use angles in a triangle: \theta = 180-(79+38)=63^{\circ}

4. Work of the value of \theta

\theta=22^{\circ}

\theta=158^{\circ}

\theta=79^{\circ}

\theta=68^{\circ}

Using alternate angles, we can see the angle \theta=22^{\circ} . We can then use the fact that this is an isosceles triangle and the other two angles in the triangle are the same.

180-22=158

\begin{aligned} 158 \div 2 &= 79^{\circ}\\ \theta &= 79^{\circ} \end{aligned}

5. Calculate the size of angle \theta

\theta=110^{\circ}

\theta=68^{\circ}

\theta=70^{\circ}

\theta=40^{\circ}

Using alternate angles, we can see the angle 110^{\circ} . Then \theta=110-42=68^{\circ}

6. By calculating the value for x , work out the value of each angle labelled.

22^{\circ} \text{ and } 34^{\circ}

34^{\circ} \text{ and } 34^{\circ}

50^{\circ} \text{ and }130^{\circ}

50^{\circ} \text{ and } 50^{\circ}

Alternate angles are equal so 7x-20=4x+10

When x=10 :

7x-20=710-20=50^{\circ}

4x+10=410+10=50^{\circ}

1. Find the size of angle a . Give reasons for your answer.

**(3 marks)**

Show answer

180 – 70 = 110 since angles in a triangle add up to 180^{\circ}.

**(1)**

Isosceles triangle so two angles equal 110 \div 2 = 55.

**(1)**

Alternate angles are equal so a=55^{\circ}.

**(1)**

2. Find the size of angle y .

**(3 marks)**

Show answer

Angle ACD =72^{\circ}

**(1)**

Angle ACB = 180 - \left (90+48 \right ) = 42^{\circ}

**(1)**

**(1)**

3. Show that the lines AB and CD are parallel.

**(4 marks)**

Show answer

**(1)**

**(1)**

**(1)**

Alternate angles are equal therefore the lines are parallel.

**(1)**

You have now learned how to:

- Apply the properties of angles at a point, angles at a point on a straight line, vertically opposite angles
- Understand and use the relationship between parallel lines and alternate and corresponding angles

- Angles in parallel lines
- Corresponding angles
- Co-interior angles
- Interior angles of a polygon
- Exterior angles of a polygon
- Pythagoras' theorem

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