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Area of a circle

Right triangle Right angle HypotenuseHere you will learn about the surface area of a cone, including how to find the surface area given the radius of a cone and the slant height.

Students will first learn about the surface area of a cone as a part of geometry in 8 th grade.

The** surface area of a cone** is the area which covers the outer surface of the cone.

For any cone, r is the **radius** of the **base of the cone**, l is the **slant height** of the cone, and h is the **perpendicular height** of the cone.

In order to calculate the total surface area of a cone (*tsa*), find the area of the two parts of the surface of the cone and add them together.

There is a **curved surface area (CSA)** and a **circular base.** The curved surface area of a cone is sometimes referred to as the lateral surface area of a cone (*lsa*).

The surface area of a cone is the area of the two parts added together:

\text{Surface area of a cone}=\pi{r}{l}+\pi{r^{2}}

The **perpendicular height** of a cone h is not required to calculate the surface area of a cone, although it is used to calculate the volume of the cone.

**Step by step guide:** Volume of a cone

Note: You **cannot** use the formula for the surface area of a cone written above for an oblique cone. This is because the curved surface area does not have a constant slant height l from the **apex** (a **vertex**) to the circular base.

**Example**

Calculate the surface area of the cone below to 1 decimal place.

Add these together to find the total surface area of the cone:

\text { Surface area of the cone }=48 \pi+36 \pi=84 \pi=263.9 \mathrm{~cm}^2 \, (1 d p)How does this relate to 8 th grade math?

**Grade 8: Geometry (8.G.C.9)**Know the formulas for the volumes of cones, cylinders, and spheres and use them to solve real-world and mathematical problems.

Use this quiz to check your grade 6 students’ understanding of surface area. 10+ questions with answers covering a range of 6th grade surface area topics to identify areas of strength and support!

DOWNLOAD FREEUse this quiz to check your grade 6 students’ understanding of surface area. 10+ questions with answers covering a range of 6th grade surface area topics to identify areas of strength and support!

DOWNLOAD FREEIn order to calculate the surface area of a cone:

**Find the area of each face.****Add the areas together.****Write the answer, including the units.**

Find the curved surface area of the cone below. The radius of the cone is 3 \mathrm{~cm} and the slant height is 7 \mathrm{~cm}. Write your answer to 1 decimal place.

**Find the area of each face.**

You will only calculate the area of the curved surface for this question.

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 3 \times 7 \\\\ &=21\pi \end{aligned}2**Add the areas together.**

Because you are calculating the area of the curved surface, you can move on to step 3.

3**Write the answer, including the units.**

Round the answer to 1 decimal place and include the units.

21 \pi=66.0 \, (1 d p)The curved surface area of the cone is 66.0 \mathrm{~cm}^2 \, (1 d p).

Note: If the question asks for 1 decimal place, the answer must have 1 decimal place, even if the digit is 0.

Find the total surface area of the cone below to 1 decimal place.

**Find the area of each face.**

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 6.8 \times 9.1 \\\\ &=\cfrac{1547}{25}\pi \end{aligned}

**Add the areas together.**

The sum of the areas is:

\cfrac{1547}{25}\pi+\cfrac{1156}{25}\pi=\cfrac{2703}{25}\pi

**Write the answer, including the units.**

Write the answer to 1 decimal place and with square units.

\cfrac{2703}{25}\pi=339.7 \, (1 d p)

The total surface area of the cone is 339.7 \mathrm{~cm}^2 \, (1 d p).

A chip shop sells mushy peas in a conical pot. The lid has a radius of 7 \mathrm{~cm}, and the pot has a slant height of 10 \mathrm{~cm}. Calculate the outside surface area of the closed pot, including the lid. Write your answer in terms of \pi.

**Find the area of each face.**

\begin{aligned}\text{Curved surface area (the pot)}&=\pi rl \\\\ &=\pi \times 7 \times 10 \\\\ &=70 \pi \end{aligned}

**Add the areas together.**

The sum of the areas is 70\pi+49\pi =119\pi

**Write the answer, including the units.**

Write the answer in terms of \pi, and state the units.

The total surface area of the cone is: 119 \pi \mathrm{~cm}^2

The roof of a tower is a solid cone. The radius of the circular base is 4.5 \mathrm{~m}, and the roof has a slope length of 8.3 \mathrm{~m}. Calculate the surface area of the roof. Write your answer in the form \cfrac{a}{b}\pi where a and b are integers with no common factors.

**Find the area of each face.**

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 4.5 \times 8.3 \\\\ &=\cfrac{747}{20}\pi \end{aligned}

**Add the areas together.**

The sum of the areas is equal to:

\cfrac{747}{20}\pi+\cfrac{81}{4}\pi=\cfrac{747}{20}\pi+\cfrac{405}{20}\pi=\cfrac{1152}{20}\pi

**Write the answer, including the units.**

The answer needs to be written in the form \cfrac{a}{b}\pi where a and b are integers with no common factors. By simplifying the fraction fully, you get \cfrac{1152}{20}\pi=\cfrac{288}{5}\pi.

The surface area of the solid cone is \cfrac{288}{5}\pi \text{ m}^{2}.

Calculate the surface area of a cone with a base diameter of 4 \mathrm{~cm} and a slant height of 6 \mathrm{~cm}. Give your answer to 3 significant figures.

**Find the area of each face.**

Calculate the radius of the circular base first. As the diameter is twice the radius of a circle, divide the diameter of the circle by 2.

4 \div 2=2 \mathrm{~cm}

You are left with r=2 \mathrm{~cm}.

**Add the areas together.**

Add the two areas together.

12 \pi+4 \pi=16 \pi

**Write the answer, including the units.**

Write the answer to 3 significant figures, and state the units.

16\pi=50.3 \, (3sf)

The surface area of the cone is 50.3 \mathrm{~cm}^2 \, (3sf).

A cone has a perpendicular height of 4 \mathrm{~cm}, and a circular base with a radius of 3 \mathrm{~cm}. The apex of the cone is directly above the center of the circular base. Calculate the area of the curved surface in terms of \pi.

**Find the area of each face.**

Find the slant height of the cone. Sketching a diagram of the cone with the dimensions given:

To find the slant height of a cone, l, use Pythagoras’ theorem:

a^2+b^2=c^2.

Given that a=4 \mathrm{~cm}, b=3 \mathrm{~cm}, and c=l, you have:

With the value for the slant height, you can find the curved surface area.

**Add the areas together.**

Because you are calculating the area of the curved surface, you can move on to step 3.

**Write the answer, including the units.**

Leave the answer in terms of \pi and include the units.

The curved surface area of the cone is 15 \pi \mathrm{~cm}^2.

- Link finding the surface area of cones to finding the area and surface area of other geometric shapes students may be familiar with. The formula for finding the area of the circle of the lateral surface area of a cylinder have parallels with the formula for surface area.

- Provide multiple opportunities for students to practice finding the surface area of a cone, including worksheets, games or the use of interactive online tools. Allow students to work with small groups and provide frequent feedback to help improve understanding.

- Use of a problem solving strategy can help students tackle word problems. Model and prompt students to identify and label important information within the word problem before attempting to use the formula.

**Forgetting to add the base**

Make sure to include the area of the base when calculating the total surface area. The formula includes the curved surface and the area of the base.

**Forgetting to simplify radicals**

The formula for the curved surface (lateral surface area of the cone) often involves square roots. Keep an eye out for when you need to do this so you don’t leave the answers unsimplified.

**Mixing up the slant height with the height**

The slant height is the distance from the tip of the cone to any point on the circumference of the base and the height is the perpendicular distance from the base to the tip. Make sure to use the correct height value when calculating the total surface area of the cone.

1. Find the curved surface area of a cone of radius 10 \mathrm{~cm} and slant height 12 \mathrm{~cm}. Give your answer to 3 significant figures.

120 \mathrm{~cm}^2

376.991 \mathrm{~cm}^2

377 \mathrm{~cm}^2

3770 \mathrm{~cm}^2

To find the curved surface area of a cone, substitute the value of r and l into the formula.

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 12\times 10 \\\\ &=120\pi \\\\ &=376.9911184…\\\\ &=377 \ cm^2 \, \text{(3sf)} \end{aligned}

2. A cone has a radius of 7.8 \mathrm{~mm} and a slant height of 9.6 \mathrm{~mm}. Calculate the curved surface area of the cone, to 3 significant figures.

74.9 \mathrm{~mm}^2

117 \mathrm{~mm}^2

235 \mathrm{~mm}^2

235.242 \mathrm{~mm}^2

To find the curved surface area of a cone, substitute the value of r and l into the formula.

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 7.8\times 9.6 \\\\ &=235.2424579… \\\\ &=235 \, \text{cm}^2 \, \text{(3sf)} \end{aligned}

3. A candle is made in the shape of a cone. The radius of the base is 4 \mathrm{~cm}, and the slant height is 7 \mathrm{~cm}. Calculate the surface area of the candle to 1 decimal place.

138.2 \mathrm{~cm}^2

88.0 \mathrm{~cm}^2

117.3 \mathrm{~cm}^2

113.1 \mathrm{~cm}^2

To find the total surface area of a cone, find the curved surface area and add on the area of the circular base.

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 4 \times 7 \\\\ &= 28 \pi \end{aligned}

\begin{aligned}\text{Area of circular base }&=\pi r^2 \\\\ &=\pi \times 4^2 \\\\ &=16 \pi \end{aligned}

Total surface area: 28\pi +16\pi =44\pi

44\pi=138.2\text{ cm}^{2} \, (1 d p)

4. Find the total surface area of a cone of radius 6.5 \mathrm{~cm} and slant height 9.3 \mathrm{~cm}. Write your answer as a fraction in the form \cfrac{a}{b} \pi where a and b are integers. State the units in your answer.

\cfrac{1027}{10}\pi\text{ cm}^{2}

\cfrac{5239}{40}\pi\text{ cm}^{2}

\cfrac{17407}{40}\pi\text{ cm}^{2}

\cfrac{1469}{20}\pi\text{ cm}^{2}

To find the total surface area of a cone, find the curved surface area and add on the area of the circular base.

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 6.5\times 9.3 \\\\ &=\cfrac{1209}{20}\pi \end{aligned}

\begin{aligned}\text{Area of circular base }&=\pi r^2 \\\\ &=\pi \times 6.5^2 \\\\ &=\cfrac{169}{4}\pi \end{aligned}

Total surface area:

\cfrac{1209}{20}\pi+\cfrac{169}{4}\pi=\cfrac{1207}{10}\pi

Surface area is equal to \cfrac{1207}{10} \pi \mathrm{~cm}^2.

5. A conical party hat has a diameter of 16 \mathrm{~cm}, and a slant height of 11 \mathrm{~cm}. An image is being placed on the entire outside surface of the party hat. What is the area of the image? Write your answer in terms of \pi.

88 \pi \mathrm{~cm}^2

176 \pi \mathrm{~cm}^2

276 \pi \mathrm{~cm}^2

\cfrac{704}{3}\pi \mathrm{~cm}^2

The diameter is twice the length of the radius and so r=16 \div 2=8 \mathrm{~cm}.

Substituting the values for r and l into the formula for the curved surface area you get,

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 8\times 11 \\\\ &=88\pi \\\\ &=88\pi \mathrm{~cm}^2 \end{aligned}

6. A cone has a radius of 5 \mathrm{~cm} and a perpendicular height of 12 \mathrm{~cm}. The apex of the cone is directly above the center of the circular base. Calculate the surface area of the cone to 3 significant figures.

94.2 \mathrm{~cm}^2

283 \mathrm{~cm}^2

188 \mathrm{~cm}^2

314 \mathrm{~cm}^2

Use Pythagoras’ theorem to calculate the slant height of the cone, then determine the surface area.

Pythagoras’ theorem: a^{2}+b^{2}=c^{2}

\begin{aligned}a^{2}+b^{2}&=c^{2} \\\\ 5^{2}+12^{2}&=l^{2} \\\\ 25+144&=l^{2} \\\\ l^{2}&=169 \\\\ l&=\sqrt{169} \\\\ l&=13\, cm \end{aligned}

The slant height l=13 \, cm.

\begin{aligned}\text{Curved surface area}&=\pi rl \\\\ &=\pi \times 5\times 13 \\\\ &=65\pi \end{aligned}

\begin{aligned}\text{Area of circular base }&=\pi r^2 \\\\ &=\pi \times 5^2 \\\\ &=25\pi \end{aligned}

Total surface area: 65\pi+25\pi=90\pi=283 \, \text{(3sf)}

The total surface area of the cone is 283 \mathrm{~cm}^2 \, \text{(3sf)}

A cone is a 3D geometric shape that tapers from a flat base to a point called the apex. The base of a cone is typically a circle, but not always.

Finding the surface area of a right circular cone is the same as finding the surface area of any cone. You will first find the area of the curved surface using the formula =\pi r l. You will add the answer of the area of the curved surface to the area of the base, using the formula =\pi r^2.

- Pythagorean theorem
- Congruence and similarity
- Transformations

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