Area of a Rectangle - Math Steps, Examples & Questions

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Area of a rectangle

Here you will learn about finding the area of a rectangle, including finding the area of rectilinear figures, finding missing side lengths, solving area problems involving unit conversion, and solving real-world word problems involving the area of a rectangle.

Students will first learn about area of a rectangle as part of measurement and data in 3rd grade.

What is the area of a rectangle?

The area of a rectangle is the amount of space inside the rectangle. It is measured in units squared, or square units. ( $cm^2, m^2, in^2,$ etc.)

In order to find the area, you need to use the area formula:

$\text { Area }=\text { length} \times \text { width}$

Area of Rectangle what is the area of a rectangle image

For example,

$\begin{aligned} \text { Area } & =\text { length } \times \text { width } \\\\ & =7 \times 4 \\\\ & =28 \mathrm{~m}^2 \end{aligned}$

You can also use this area formula:

$\text { Area }=\text { base} \times \text { height}$

Notice it multiplies the same parts of the rectangle as the formula $A=l \times w,$ but uses the terms $base$ and $height$ instead of $length$ and $width.$ Either of these formulas can be used to find the area of a rectangle.

A rectangle is a quadrilateral ( $4$ sided shape) where every angle is a right angle $(90^{\circ}).$ Opposite sides of the rectangle are equal length.

The area of a rectangle is calculated by multiplying the length of the rectangle by the width of the rectangle.

The final answer must be in square units. For example, square centimeters $(cm^2),$ square meters $(m^2),$ square feet $(ft^2),$ square inches $(in^2),$ etc.

What is the area of a rectangle?

Common Core State Standards

How does this relate to 3rd grade math and 4th grade math?

Grade 3 – Measurement and Data (3.MD.7)
Relate area to the operations of multiplication and addition.
a. Find the area of a rectangle with whole-number side lengths by tiling it, and
show that the area is the same as would be found by multiplying the side
lengths.
b. Multiply side lengths to find areas of rectangles with whole number side
lengths in the context of solving real world and mathematical problems,
and represent whole-number products as rectangular areas in mathematical
reasoning.
c. Use tiling to show in a concrete case that the area of a rectangle with whole-
number side lengths $a$ and $b + c$ is the sum of $a \times b$ and $a \times c.$ Use area
models to represent the distributive property in mathematical reasoning.
d. Recognize area as additive. Find areas of rectilinear figures by decomposing
them into non-overlapping rectangles and adding the areas of the non-
overlapping parts, applying this technique to solve real world problems.

Grade 4 – Measurement and Data (4.MD.3)
Apply the area and perimeter formulas for rectangles in real world and mathematical problems. For example, find the width of a rectangular room given the area of the flooring and the length, by viewing the area formula as a multiplication equation with an unknown factor.

How to find the area of a rectangle

In order to find the area of a rectangle:

Identify the length and width of the rectangle.
Write down the formula for the area of a rectangle.
Substitute the given values and calculate.
Write down your final answer with units squared.

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$[FREE] End of Year Math Assessments (Grade 4 & Grade 5)$

[FREE] End of Year Math Assessments (Grade 4 & Grade 5)

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Assess math progress for the end of grade 4 and grade 5 or prepare for state assessments with these mixed topic, multiple choice questions and extended response questions!

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Area of a rectangle examples

Example 1: finding area given the length and width

Find the area of the rectangle below.

Identify the length and width of the rectangle.

$Length = 6 \, m$

$Width = 4 \, m$

2Write down the formula for the area of a rectangle.

$\text { Area }=\text { length } \times \text { width }$

3Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ \text { Area }&=6 \times 4 \\\\ & =24 \end{aligned}$

4Write down your final answer with units squared.

In this case, you are working with meters so your final answer must be in square meters.

$\text { Area }=24 \mathrm{~m}^{2}$

Example 2: finding the area of a rectangle requiring converting units

Find the area of the rectangle below.

Identify the length and width of the rectangle.

$Length = 1 \, m$

$Width = 30 \, cm$

There are two different units for the length and width so you must change them to a common unit.

In this case, it is easier to convert both to centimeters to avoid working with decimals.

There are $100$ centimeters in a meter, so if you multiply the length by $100,$ you get $100$ centimeters.

$Length = 100 \, cm$

$Width = 30 \, cm$

Write down the formula for the area of a rectangle.

$\text { Area }=\text { length } \times \text { width }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { length } \times \text { width }\\\\ \text { Area }&=100 \times 30 \\\\ &=3000 \end{aligned}$

Write down your final answer with units squared.

Since you are working with centimeters, your final answer will be in square centimeters.

$\text { Area }=3000 \mathrm{~cm}^{2}$

Example 3: real-world word problem

Ms. Crawely is tiling her bathroom floor. The dimensions of the floor are $6 \, m$ by $4 \, m.$ Each tile is $50 \, cm$ by $50 \, cm.$ How many tiles will she need to cover the bathroom floor?

Identify the length and width of the rectangle.

For the bathroom floor:

$Length = 6 \, m$

$Width = 4 \, m$

As there are two different units in the question, you need to convert everything to meters or centimeters. To avoid working with decimals, convert the bathroom floor dimensions into centimeters.

For the bathroom floor:

Multiply by $100$ because there are $100$ centimeters in a meter.

$\begin{aligned} \text { Length }&=6 \mathrm{~m} \times 100=600 \mathrm{~cm} \\\\ \text { Width }&=4 \mathrm{~m} \times 100=400 \mathrm{~cm} \end{aligned}$

For the tiles:

$Length = 50 \, cm$

$Width = 50 \, cm$

Write down the formula for the area of a rectangle.

$\text { Area }=\text { length } \times \text { width }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ \text { Area }&=600 \times 400 \\\\ \text { Area }&=240000 \\\\ \end{aligned}$

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ \text { Area }&=50 \times 50 \\\\ \text { Area }&=2500 \end{aligned}$

Write down your final answer with units.

$240000 \div 2500=96 \text { tiles }$

Example 4: calculating side length given the area

Find the width of the rectangle below.

Identify the length and width of the rectangle.

$Length = 80 \, m$

$Width = \, ?$

To calculate the width of a rectangle, you need to use the area:

$\text { Area }=320 \mathrm{~m}^2$

Write down the formula for the area of a rectangle.

$\text { Area }=\text { length } \times \text { width }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }& =\text { length } \times \text { width } \\\\ 320& =80 \times w \\\\ \cfrac{320}{80}& =w \\\\ w& =4 \end{aligned}$

Write down your final answer with units.

$\text { width }=4 \, m$

In this case, because the question asks you to calculate width and not area, do not write $m^2.$

Example 5: area of a rectilinear figure

Find the area of the field below:

Identify the length and width of the rectangle.

Before finding the length and width, you need to first decompose the rectilinear figure into individual non-overlapping rectangles. In this case, there are two ways in which you could do this:

Both options will give you the same answer. For the purposes of this question, you will use the decomposed rectilinear figure on the left.

Now you need to find the length and width of each rectangle:

You need to calculate two of the side lengths. Label them $a$ and $b.$ You will also label the rectangles as $A$ and $B.$

To calculate $a,$ you know the full length of the rectilinear figure is $8 \, m.$ You need to subtract $7 \, m$ from it which gives you $1 \, m.$

$a = 1 \, m$

To calculate $b,$ you know the full width of the rectilinear figure is $2 \, m.$ You need to subtract $1 \, m$ which gives you $1 \, m.$

$b = 1 \, m$

For rectangle $A$ :

$Length = 2 \, m$

$Width = 1 \, m$

For rectangle $B$ :

$Length = 7 \, m$

$Width = 1 \, m$

Write down the formula for the area of a rectangle.

$\text { Area }=\text { length } \times \text { width }$

Substitute the given values and calculate.

Rectangle $A$

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ \text { Area }&=2 \times 1 \\\\ &=2 \end{aligned}$

Rectangle $B$

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ \text { Area }&=7 \times 1 \\\\ & =7 \end{aligned}$

You need to now find the sum of the areas of rectangle $A$ and $B.$

$\begin{aligned} \text{ Total Area } &= \text{ Area of Rectangle A } + \text{ Area of Rectangle B } \\\\ \text{ Total Area } &=2+7 \\\\ \text{ Total Area } &=9 \end{aligned}$

Write down your final answer with units squared.

$\text { Area }=9 \mathrm{~m}^2$

Example 6: word problem

Rectangle $ABCD,$ shown below, has a perimeter of $22 \, m$ and a side length of $8 \, m.$ Find the area of the rectangle.

Identify the length and width of the rectangle.

$Length = 8 \, m$

$Width = \, ?$

As the width is unknown, you will have to find it using the perimeter and your knowledge of rectangles.

The perimeter of a rectangle is the total distance around the outside of the rectangle, or the sum of the sides of a rectangle.

Since you know that the opposite sides of a rectangle are the same lengths, that means that, since side $BC$ measures $8 \, m,$ side $AD$ also measures $8 \, m.$

Now you have two side lengths, which equal $16 \, m$ together.

Since the total perimeter is $22 \, m,$ the remaining two sides, side $AB$ and side $CD,$ must equal $6m$ together.

Therefore, side $AB = 3 \, m$ and side $CD = 3 \, m.$

Now you have the length and width in order to find the area of the rectangle.

$Length = 8 \, m$

$Width = 3 \, m$

Write down the formula for the area of a rectangle.

$\text { Area }=\text { length } \times \text { width }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ \text { Area }&=8 \times 3 \\\\ &=24 \end{aligned}$

Write down your final answer with units squared.

In this case, you are working with meters so your final answer must be in square meters.

$\text { Area }=24 \, m^2$

Teaching tips for area of a rectangle

Before learning the area of a rectangle formula, allow students to explore area by tiling with square tiles. These concrete manipulatives act as unit squares and will help students build an understanding of area before they begin calculating it.

Rather than having students practice finding the area of a rectangle on multiple skill worksheets, provide them with a variety of practice problems, activities, and/or projects that have a real-world context. This will deepen their understanding of this skill.

Easy mistakes to make

Using incorrect units for the answer
A common error is to forget to include square units in your answer when finding the area of a rectangle.

Forgetting to convert measures to a common unit
Before using the formula for the area of a rectangle, you need to ensure that the units are the same. If different units are given (for example, $length = 4 \, m$ and $width = 3 \, cm$ ), then you must convert them either both to centimeters or both to meters.

Practice area of a rectangle questions

60 \, mm

17 \, mm^2

60 \, mm^2

17 \, mm

Multiply the length and width together to get the area of the rectangle.

$12 \mathrm{~mm} \times 5 \mathrm{~mm}=60 \mathrm{~mm}^2$

480 \, m^2

480 \, cm^2

$4.8 \, m^2$ or $48 \, 000 \, cm^2$

124 \, m^2

Prior to multiplying the length times the width, convert the length and width to a common unit (both length and width to meters or both to centimeters).

Remember there are $100$ centimeters in $1$ meter.

$35$ tiles

$875$ tiles

$400$ tiles

$11$ tiles

Find the area of the floor by multiplying the length of the rectangle times the width.

Prior to multiplying the length and width for the tile, convert the length and width to a common unit (since you calculated the floor in meters here, you converted tiles to meters).

Remember there are $100$ centimeters in $1$ meter.

Take the area of the tiles and divide it into the area of the floor to get the number of tiles needed to cover the floor.

4 \, m

19600 \, m

19 \, 600 \, m^2

4 \, m^2

Using the formula for the area of a rectangle, substitute your given values.

As you are trying to find the width of the rectangle, you need to rearrange the formula dividing the length into the area.

57 \, m^2

22 \, m^2

45 \, m^2

30 \, m^2

Split the rectilinear figure into $3$ rectangles.

Find the missing side length of rectangle $C$ by subtracting $3$ from the total length which is $5 \, m.$

Add up all the individual areas to get the total area of the rectilinear figure.

Area of a Rectangle image 15 US

Rectangle $A$

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ &=3 \times 2 \\\\ &=6 \\\\ \text { Area }&=6 \, m^2 \end{aligned}$

Rectangle $B$

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ &=3 \times 2 \\\\ &=6 \\\\ \text { Area }&=6 \, m^2 \end{aligned}$

Rectangle $C$

$\begin{aligned} \text { Area }&=\text { length } \times \text { width } \\\\ &=9 \times 2 \\\\ &=18 \\\\ \text { Area }&=18 \, m^2 \end{aligned}$

$\begin{aligned} \text { Total Area }&= 6 \, m^2+6 \, m^2+18 \, m^2 \\\\ & =30 \, m^2 \end{aligned}$

2 \, m

2 \, m^2

22 \, m^2

22 \, m

Since side $XY$ is $11 \, m,$ side $WZ$ is also $11 \, m.$ That means the sum of the remaining side lengths must equal $4 \, m.$

So side $WX$ and side $YZ$ are each $2 \, m.$ Then, you multiply $11 \, m$ by $2 \, m \; (length \times width)$ to find the area.

Area of a rectangle FAQs

How do you find the area of a rectangle?

Multiply the length of a rectangle by the width of a rectangle to find its area.

What is the difference between the area of a rectangle and the perimeter of a rectangle?

The area of a rectangle is the amount of space inside the rectangle. It is measured in square units. The perimeter of a rectangle is the distance around the outside of a rectangle, or the sum of the sides of a rectangle. It is measured in any unit of length.

What is the area of a rectangle formula?

The formula for area of a rectangle is $Area = length \times width.$

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