[FREE] End of Year Math Assessments (Grade 4 and Grade 5)

The assessments cover a range of topics to assess your students' math progress and help prepare them for state assessments.

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Multiplication and division

Multiplying and dividing decimalsProperties of quadrilaterals

Here you will learn about finding the area of a parallelogram, including compound area questions, questions with missing side lengths, and questions involving unit conversion.

Students will first learn about area of a parallelogram as part of geometry in 6th grade.

The **area of a parallelogram** is the amount of space inside the parallelogram. It is measured in units squared, or square units. ( cm^2, m^2, mm^2, etc.) It is calculated by **multiplying **the **base of a parallelogram** by the** perpendicular height**.

In order to find the area, you need to use the area formula:

\begin{gathered} \text { Area }=\text { base } \times \text { perpendicular height } \\\\ \text { Area }=b \times h \end{gathered}

For example,

\begin{aligned} \text { Area } & =\text { base } \times \text { perpendicular height } \\\\ & =8 \times 6 \\\\ & =48 \mathrm{~m}^2 \end{aligned}

A parallelogram is a **quadrilateral **( 4 sided shape) with 2 pairs of parallel lines.

Opposite sides of a parallelogram are parallel. The parallel sides and opposite angles are congruent. The interior angles of the parallelogram add up to 360^{\circ}.

To understand the formula, you cut off the triangle on one end of the parallelogram and attach it to the other end to form a rectangle. The formula for the area of a rectangle is base multiplied by height.

Your final answer must be in square units. For example, square centimeters (cm^2), square meters (m^2), square feet (ft^2) etc.

How does this relate to 6th grade math?

**Grade 6 – Geometry (6.G.1)**Find the area of right triangles, other triangles, special quadrilaterals, and polygons by composing into rectangles or decomposing into triangles and other shapes; apply these techniques in the context of solving real-world and mathematical problems.

In order to find the area of a parallelogram by decomposing the shape:

**Decompose the parallelogram into two triangles and a rectangle.****Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.****Identify the base and height of the rectangle.****Write down the formula for the area of a rectangle.****Substitute the given values and calculate.****Write down your final answer with units squared.**

In order to find the area of a parallelogram using the formula:

**Identify the base and the perpendicular height of the parallelogram.****Write down the formula for the area of a parallelogram.****Substitute the given values and calculate.****Write down your final answer with units squared.**

Assess math progress for the end of grade 4 and grade 5 or prepare for state assessments with these mixed topic, multiple choice questions and extended response questions!

DOWNLOAD FREEAssess math progress for the end of grade 4 and grade 5 or prepare for state assessments with these mixed topic, multiple choice questions and extended response questions!

DOWNLOAD FREEDecompose the parallelogram and rearrange its part so that they form a rectangle. Then find the area.

**Decompose the parallelogram into two triangles and a rectangle.**

2**Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.**

3**Identify the base and height of the rectangle.**

Base = 10 \, m

Height = 6 \, m

4**Write down the formula for the area of a rectangle.**

\text { Area }=\text { Base } \times \text { Height }

5**Substitute the given values and calculate.**

\begin{aligned} \text { Area }&=\text { Base } \times \text { Height } \\\\ &=10 \times 6 \\\\ &=60 \end{aligned}

6**Write down your final answer with units squared.**

\text { Area }=60 \mathrm{~m}^{2}

Find the area of the parallelogram below:

**Decompose the parallelogram into two triangles and a rectangle.**

**Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.**

**Identify the base and height of the rectangle.**

There are three measurements shown on the diagram, so you must be able to determine what represents the base and the height.

The base, shown at the bottom, is 8 \, m.

The 6.3 \, m measurement shown on the diagram represents the length of the parallelogram’s original diagonal side. This measurement is not needed to find the area.

The height is 6m, which is the measurement needed.

Therefore,

Base = 8 \, m

Height = 6 \, m

**Write down the formula for the area of a rectangle.**

\text { Area }=\text { Base } \times \text { Height }

**Substitute the given values and calculate.**

\begin{aligned} \text { Area } & =\text { Base } \times \text { Height } \\\\ & =8 \times 6 \\\\ & =48 \end{aligned}

**Write down your final answer with units squared.**

\text { Area }=48 \mathrm{~m}^2

**Decompose the parallelogram into two triangles and a rectangle.**

**Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.**

**Identify the base and height of the rectangle.**

There are two different units of measurement used in the diagram. In order to solve for the area, the units must be the same.

Therefore, you need to convert meters to centimeters or centimeters to meters.

For this question, you will use meters as the common unit. Since there are 100 centimeters in 1 meter, you can divide 1,000 \, cm by 100 to get the measurement in meters.

1,000 \mathrm{~cm} \div 100=10 \mathrm{~m}

Furthermore, the length of the diagonal of the original parallelogram is not needed.

So,

Base = 10 \, m

Height = 7.5 \, m

**Write down the formula for the area of a rectangle.**

\text { Area }=\text { Base } \times \text { Height }

**Substitute the given values and calculate.**

\begin{aligned} \text { Area }&=\text { Base } \times \text { Height } \\\\ & =10 \times 7.5 \\\\ & =75 \end{aligned}

**Write down your final answer with units squared.**

\text { Area }=75 \mathrm{~m}^2

**Identify the base and the perpendicular height of the parallelogram**.

The length of the diagonal side of the parallelogram is not needed in order to find its area, so it is just additional information.

Base = 8.3 \, ft

Perpendicular \; height = 12 \, ft

**Write down the formula for the area of a parallelogram.**

\text { Area }=\text { Base } \times \text { Perpendicular Height }

**Substitute the given values and calculate.**

\begin{aligned} \text { Area }&=\text { Base } \times \text { Perpendicular Height } \\\\ & =8.3 \times 12 \\\\ & =99.6 \end{aligned}

**Write down your final answer with units squared.**

\text { Area }=99.6 \mathrm{~ft}^2

**Identify the base and the perpendicular height of the parallelogram.**

Before you can identify the perpendicular height and the base, you need to convert one of the measurements so that each measurement has the same unit.

For this question, you will use meters.

To convert km to meters, you need to multiply by 1,000.

0.032 \mathrm{~km} \times 1,000=32 \mathrm{~m}

So,

\begin{aligned}
& \text { Base }=32 \mathrm{~m} \\\\
& \text { Perpendicular height }=49 \mathrm{~m}
\end{aligned}

**Write down the formula for the area of a parallelogram.**

\text { Area }=\text { Base } \times \text { Perpendicular Height }

**Substitute the given values and calculate.**

\begin{aligned} \text { Area }&=\text { Base } \times \text { Perpendicular Height } \\\\ & =32 \times 49 \\\\ & =1,568 \mathrm{~m}^2 \end{aligned}

**Write down your final answer with units squared.**

\text { Area }=1,568 \mathrm{~m}^2

Find the base length of the parallelogram below:

**Identify the base and the perpendicular height of the parallelogram.**

Base = \, ?

Perpendicular \; Height = 11 \, cm

In this question, you are given the area of the parallelogram as 242 \, cm^2, which you can use to calculate the base.

**Write down the formula for the area of a parallelogram.**

\text { Area }=\text { Base } \times \text { Perpendicular Height }

**Substitute the given values and calculate.**

\begin{aligned} \text { Area }&=\text { Base } \times \text { Perpendicular Height } \\\\ 242&=\text { Base } \times 11 \\\\ \text { Base }&=\cfrac{242}{11} \\\\ \text { Base }&=22 \end{aligned}

**Write down your final answer with units.**

Since the answer represents the length of the base and not the area of the parallelogram, the answer will not be in square units.

\text { Base length }=22 \mathrm{~cm}

A painter needs to paint a logo on the side of an office firm. The logo is composed of four identical parallelograms, as shown below. Each can of paint costs \$1.20 and covers an area of 2.5m^2. How much will it cost to paint the logo?

**Identify the base and the perpendicular height of the parallelogram.**

Base = \, 4 \, m

Perpendicular \; Height = 2 \mathrm{~m} ( 8 \div 4 parallelograms)

**Write down the formula for the area of a parallelogram.**

\text { Area }=\text { Base } \times \text { Perpendicular Height }

Since there are 4 identical parallelograms in the logo, you need to multiply the area by 4.

\text { Area }=4 \times(\text { Base } \times \text { Perpendicular Height })

**Substitute the given values and calculate.**

\begin{aligned} \text { Area }&=4 \times(\text { Base } \times \text { Perpendicular Height }) \\\\ & =4 \times(4 \times 2) \\\\ & =32 \end{aligned}

**Write down your final answer with units squared.**

\text { Area }=32 \, m^2

Now that you have calculated the area, you need to find how many cans of paint are needed to paint the logo.

Since each paint can covers an area of 2.5 \, m^2, you need to divide 2.5 into 32.

32 \div 2.5=12.8 \text { cans }

Since you can’t buy 0.8 of a can, you will need to round the number of cans to 13.

Each can costs \$ 1.20, so 13 \times 1.2=\$ 15.60

Therefore, the total cost to paint the logo is \$15.60.

- Provide students with a variety of problems, including word problems with a real-world context. Label parallelograms with the perpendicular height as well as the diagonal length, so that they need to correctly differentiate between the two in order to solve.

- Encourage students to follow the step-by-step process used above for each strategy. Have students write these steps in their math notebooks, or post them in the classroom for students to refer to.

**Using incorrect units for the answer**

A common error is to forget to include square units when asked to find area.

**Forgetting to convert measures to a common unit**

Before using the formula for calculating the area of a parallelogram, students must look at the units given in the question. If different units are given, for example, length = 4 \, m and width = 3 \, cm, students must convert them both to cm or both to m.

**Using length of the diagonal when calculating area and not the perpendicular height of a parallelogram**

Sometimes in a question, additional measurements are given that are not needed in order to find the area. Sometimes the length of one of the diagonal sides of the parallelogram will be given, which must be ignored. Only the base and perpendicular height measurements are needed to find the area.

- Area
- Area of a quadrilateral
- Area of a trapezoid
- Area of a rhombus
- Area of a triangle
- Area of a right triangle
- Area of an isosceles triangle
- Area of an equilateral triangle
- Area of an obtuse triangle
- Area of composite shapes
- Area of a rectangle
- Area of a square
- Area of rectilinear figures

1. Find the area of the parallelogram below:

17.5 \, m

17.5 \, m^2

66 \, m^2

66 \, m

Multiply the b \times h, which is 12 \times 5.5, which equals 66.

Since you are calculating area, the answer must be in square units.

2. Find the area of the parallelogram below:

3150 \, m^2

36.4 \, m^2

14.4 \, m^2

31.5 \, m^2

Convert 450 \, cm into meters by dividing by 100.

Multiply the base length (7 \, m) by the converted perpendicular height (4.5 \, m) to equal 31.5 \, m^2.

Be careful **not** to multiply by the length of the diagonal instead of the perpendicular height.

3. The diagram represents a garden with a square fountain in the middle. Calculate the area of the shaded region of the garden.

29.6 \, m^2

33.6 \, m^2

12.2 \, m^2

10.2 \, m^2

Find the area of the parallelogram by multiplying the base length times the height.

Find the area of the square by multiplying the base times the height.

Subtract the area of the square by the area of the parallelogram.

4. Calculate the length of the base of the parallelogram below:

1994 \, cm^2

24 \, cm

24 \, cm^2

1994 \, cm

Divide the area, 216 \, cm^2, by the perpendicular height of 9 \, cm.

Remember that you are not calculating the area so your final answer should not be in square units.

5. Calculate the area of the shaded region below:

126 \, cm^2

98 \, cm^2

126.98 \, cm^2

224 \, cm^2

Convert all measures to cm.

Find the area of the parallelogram first by multiplying the base times the height.

Add on the area of the rectangle which is calculated by multiplying the length and the width.

6. A landscaper is planning a rectangular garden for a client. The garden will feature a patio and sandpit both in the shape of parallelograms. The remainder of the garden will be covered in grass. Below is a blueprint of the garden. What area of the garden will be covered in grass?

105 \, m^2

78.25 \, m^2

85 \, m^2

131.75 \, m^2

First, find the area of the entire garden by multiplying its length by its width (15 \times 7 = 105).

Then, find the areas of the patio and the sandpit by multiplying base times perpendicular height for each one.

(5 \times 4 = 20, and 1.5 \times 4.5 = 6.75)

Subtract 20 and 6.75 from the total area, 105.

105-20-6.75 = 78.25m^2.

The area of a parallelogram is calculated by multiplying the base of a parallelogram times its perpendicular height.

The formula for area of a parallelogram is

\text{ area } = \text{ base } \times \text{ perpendicular height. }

Yes, if the adjacent sides are right angles, this means the opposite sides are parallel, making the shape a parallelogram or more specifically a rectangle.

- Perimeter
- 3D shapes
- Volume

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