Area of a Parallelogram - Math Steps, Examples & Questions

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Area of a parallelogram

Here you will learn about finding the area of a parallelogram, including compound area questions, questions with missing side lengths, and questions involving unit conversion.

Students will first learn about area of a parallelogram as part of geometry in 6th grade.

What is the area of a parallelogram?

The area of a parallelogram is the amount of space inside the parallelogram. It is measured in units squared, or square units. ( $cm^2, m^2, mm^2,$ etc.) It is calculated by multiplying the base of a parallelogram by the perpendicular height.

In order to find the area, you need to use the area formula:

$\begin{gathered} \text { Area }=\text { base } \times \text { perpendicular height } \\\\ \text { Area }=b \times h \end{gathered}$

For example,

$\begin{aligned} \text { Area } & =\text { base } \times \text { perpendicular height } \\\\ & =8 \times 6 \\\\ & =48 \mathrm{~m}^2 \end{aligned}$

A parallelogram is a quadrilateral ( $4$ sided shape) with $2$ pairs of parallel lines.

Opposite sides of a parallelogram are parallel. The parallel sides and opposite angles are congruent. The interior angles of the parallelogram add up to $360^{\circ}.$

To understand the formula, you cut off the triangle on one end of the parallelogram and attach it to the other end to form a rectangle. The formula for the area of a rectangle is base multiplied by height.

Your final answer must be in square units. For example, square centimeters $(cm^2),$ square meters $(m^2),$ square feet $(ft^2)$ etc.

What is the area of a parallelogram?

Common Core State Standards

How does this relate to 6th grade math?

Grade 6 – Geometry (6.G.1)
Find the area of right triangles, other triangles, special quadrilaterals, and polygons by composing into rectangles or decomposing into triangles and other shapes; apply these techniques in the context of solving real-world and mathematical problems.

How to find the area of a parallelogram

In order to find the area of a parallelogram by decomposing the shape:

Decompose the parallelogram into two triangles and a rectangle.
Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.
Identify the base and height of the rectangle.
Write down the formula for the area of a rectangle.
Substitute the given values and calculate.
Write down your final answer with units squared.

In order to find the area of a parallelogram using the formula:

Identify the base and the perpendicular height of the parallelogram.
Write down the formula for the area of a parallelogram.
Substitute the given values and calculate.
Write down your final answer with units squared.

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$[FREE] End of Year Math Assessments (Grade 4 & Grade 5)$

[FREE] End of Year Math Assessments (Grade 4 & Grade 5)

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Assess math progress for the end of grade 4 and grade 5 or prepare for state assessments with these mixed topic, multiple choice questions and extended response questions!

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Area of a parallelogram examples

Example 1: decompose the parallelogram

Decompose the parallelogram and rearrange its part so that they form a rectangle. Then find the area.

Decompose the parallelogram into two triangles and a rectangle.

2Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.

3Identify the base and height of the rectangle.

$Base = 10 \, m$

$Height = 6 \, m$

4Write down the formula for the area of a rectangle.

$\text { Area }=\text { Base } \times \text { Height }$

5Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { Base } \times \text { Height } \\\\ &=10 \times 6 \\\\ &=60 \end{aligned}$

6Write down your final answer with units squared.

$\text { Area }=60 \mathrm{~m}^{2}$

Example 2: decompose the parallelogram

Find the area of the parallelogram below:

Decompose the parallelogram into two triangles and a rectangle.

Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.

Identify the base and height of the rectangle.

There are three measurements shown on the diagram, so you must be able to determine what represents the base and the height.

The base, shown at the bottom, is $8 \, m.$

The $6.3 \, m$ measurement shown on the diagram represents the length of the parallelogram’s original diagonal side. This measurement is not needed to find the area.

The height is $6m,$ which is the measurement needed.

Therefore,

$Base = 8 \, m$

$Height = 6 \, m$

Write down the formula for the area of a rectangle.

$\text { Area }=\text { Base } \times \text { Height }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area } & =\text { Base } \times \text { Height } \\\\ & =8 \times 6 \\\\ & =48 \end{aligned}$

Write down your final answer with units squared.

$\text { Area }=48 \mathrm{~m}^2$

Example 3: decompose to find the area of a parallelogram requiring converting units

Decompose the parallelogram into two triangles and a rectangle.

Move one triangle to the opposite side of the parallelogram so that the shape is now a rectangle.

Identify the base and height of the rectangle.

There are two different units of measurement used in the diagram. In order to solve for the area, the units must be the same.

Therefore, you need to convert meters to centimeters or centimeters to meters.

For this question, you will use meters as the common unit. Since there are $100$ centimeters in $1$ meter, you can divide $1,000 \, cm$ by $100$ to get the measurement in meters.

$1,000 \mathrm{~cm} \div 100=10 \mathrm{~m}$

Furthermore, the length of the diagonal of the original parallelogram is not needed.

So,

$Base = 10 \, m$

$Height = 7.5 \, m$

Write down the formula for the area of a rectangle.

$\text { Area }=\text { Base } \times \text { Height }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { Base } \times \text { Height } \\\\ & =10 \times 7.5 \\\\ & =75 \end{aligned}$

Write down your final answer with units squared.

$\text { Area }=75 \mathrm{~m}^2$

Example 4: find the area of a parallelogram using the formula

Identify the base and the perpendicular height of the parallelogram.

The length of the diagonal side of the parallelogram is not needed in order to find its area, so it is just additional information.

$Base = 8.3 \, ft$

$Perpendicular \; height = 12 \, ft$

Write down the formula for the area of a parallelogram.

$\text { Area }=\text { Base } \times \text { Perpendicular Height }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { Base } \times \text { Perpendicular Height } \\\\ & =8.3 \times 12 \\\\ & =99.6 \end{aligned}$

Write down your final answer with units squared.

$\text { Area }=99.6 \mathrm{~ft}^2$

Example 5: use the formula to find the area of a parallelogram requiring converting units

Identify the base and the perpendicular height of the parallelogram.

Before you can identify the perpendicular height and the base, you need to convert one of the measurements so that each measurement has the same unit.

For this question, you will use meters.

To convert km to meters, you need to multiply by $1,000.$

$0.032 \mathrm{~km} \times 1,000=32 \mathrm{~m}$

So,

$\begin{aligned} & \text { Base }=32 \mathrm{~m} \\\\ & \text { Perpendicular height }=49 \mathrm{~m} \end{aligned}$

Write down the formula for the area of a parallelogram.

$\text { Area }=\text { Base } \times \text { Perpendicular Height }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { Base } \times \text { Perpendicular Height } \\\\ & =32 \times 49 \\\\ & =1,568 \mathrm{~m}^2 \end{aligned}$

Write down your final answer with units squared.

$\text { Area }=1,568 \mathrm{~m}^2$

Example 6: calculating base length given the area

Find the base length of the parallelogram below:

Identify the base and the perpendicular height of the parallelogram.

$Base = \, ?$

$Perpendicular \; Height = 11 \, cm$

In this question, you are given the area of the parallelogram as $242 \, cm^2,$ which you can use to calculate the base.

Write down the formula for the area of a parallelogram.

$\text { Area }=\text { Base } \times \text { Perpendicular Height }$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=\text { Base } \times \text { Perpendicular Height } \\\\ 242&=\text { Base } \times 11 \\\\ \text { Base }&=\cfrac{242}{11} \\\\ \text { Base }&=22 \end{aligned}$

Write down your final answer with units.

Since the answer represents the length of the base and not the area of the parallelogram, the answer will not be in square units.

$\text { Base length }=22 \mathrm{~cm}$

Example 7: word problem

A painter needs to paint a logo on the side of an office firm. The logo is composed of four identical parallelograms, as shown below. Each can of paint costs $\$1.20$ and covers an area of $2.5m^2.$ How much will it cost to paint the logo?

Identify the base and the perpendicular height of the parallelogram.

$Base = \, 4 \, m$

$Perpendicular \; Height = 2 \mathrm{~m}$ ( $8 \div 4$ parallelograms)

Write down the formula for the area of a parallelogram.

$\text { Area }=\text { Base } \times \text { Perpendicular Height }$

Since there are $4$ identical parallelograms in the logo, you need to multiply the area by $4.$

$\text { Area }=4 \times(\text { Base } \times \text { Perpendicular Height })$

Substitute the given values and calculate.

$\begin{aligned} \text { Area }&=4 \times(\text { Base } \times \text { Perpendicular Height }) \\\\ & =4 \times(4 \times 2) \\\\ & =32 \end{aligned}$

Write down your final answer with units squared.

$\text { Area }=32 \, m^2$

Now that you have calculated the area, you need to find how many cans of paint are needed to paint the logo.

Since each paint can covers an area of $2.5 \, m^2,$ you need to divide $2.5$ into $32.$

$32 \div 2.5=12.8 \text { cans }$

Since you can’t buy $0.8$ of a can, you will need to round the number of cans to $13.$

Each can costs $\$ 1.20,$ so $13 \times 1.2=\$ 15.60$

Therefore, the total cost to paint the logo is $\$15.60.$

Teaching tips for area of a parallelogram

Provide students with a variety of problems, including word problems with a real-world context. Label parallelograms with the perpendicular height as well as the diagonal length, so that they need to correctly differentiate between the two in order to solve.

Encourage students to follow the step-by-step process used above for each strategy. Have students write these steps in their math notebooks, or post them in the classroom for students to refer to.

Easy mistakes to make

Using incorrect units for the answer
A common error is to forget to include square units when asked to find area.

Forgetting to convert measures to a common unit
Before using the formula for calculating the area of a parallelogram, students must look at the units given in the question. If different units are given, for example, length $= 4 \, m$ and width $= 3 \, cm,$ students must convert them both to $cm$ or both to $m.$

Using length of the diagonal when calculating area and not the perpendicular height of a parallelogram
Sometimes in a question, additional measurements are given that are not needed in order to find the area. Sometimes the length of one of the diagonal sides of the parallelogram will be given, which must be ignored. Only the base and perpendicular height measurements are needed to find the area.

Practice area of a parallelogram questions

17.5 \, m

17.5 \, m^2

66 \, m^2

66 \, m

Multiply the $b \times h,$ which is $12 \times 5.5,$ which equals $66.$

Since you are calculating area, the answer must be in square units.

3150 \, m^2

36.4 \, m^2

14.4 \, m^2

31.5 \, m^2

Convert $450 \, cm$ into meters by dividing by $100.$

Multiply the base length $(7 \, m)$ by the converted perpendicular height $(4.5 \, m)$ to equal $31.5 \, m^2.$

Be careful not to multiply by the length of the diagonal instead of the perpendicular height.

29.6 \, m^2

33.6 \, m^2

12.2 \, m^2

10.2 \, m^2

Find the area of the parallelogram by multiplying the base length times the height.

Find the area of the square by multiplying the base times the height.

Subtract the area of the square by the area of the parallelogram.

1994 \, cm^2

24 \, cm

24 \, cm^2

1994 \, cm

Divide the area, $216 \, cm^2,$ by the perpendicular height of $9 \, cm.$

Remember that you are not calculating the area so your final answer should not be in square units.

126 \, cm^2

98 \, cm^2

126.98 \, cm^2

224 \, cm^2

Convert all measures to $cm.$

Find the area of the parallelogram first by multiplying the base times the height.

Add on the area of the rectangle which is calculated by multiplying the length and the width.

105 \, m^2

78.25 \, m^2

85 \, m^2

131.75 \, m^2

First, find the area of the entire garden by multiplying its length by its width $(15 \times 7 = 105).$

Then, find the areas of the patio and the sandpit by multiplying base times perpendicular height for each one.

$(5 \times 4 = 20,$ and $1.5 \times 4.5 = 6.75)$

Subtract $20$ and $6.75$ from the total area, $105.$

$105-20-6.75 = 78.25m^2.$

Area of a parallelogram FAQs

How do you calculate the area of a parallelogram?

The area of a parallelogram is calculated by multiplying the base of a parallelogram times its perpendicular height.

What is the area of a parallelogram formula?

The formula for area of a parallelogram is
$\text{ area } = \text{ base } \times \text{ perpendicular height. }$

Can the adjacent sides of a parallelogram be right angles?

Yes, if the adjacent sides are right angles, this means the opposite sides are parallel, making the shape a parallelogram or more specifically a rectangle.

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