GCSE Tutoring Programme
Our chosen students improved 1.19 of a grade on average - 0.45 more than those who didn't have the tutoring.
In order to access this I need to be confident with:
Addition and subtraction
Negative numbers Vector notation Column vectors Vector additionThis topic is relevant for:
Here we will learn about vector subtraction.
There are also vector worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if youβre still stuck.
Vector subtraction is subtracting one vector from another vector.
To do this we subtract the horizontal components (top numbers) of the column vector and subtract the vertical components (bottom numbers) of the column vector.
E.g.
Letβs look at vector a and vector b.
Subtracting vectors is based on the addition of vectors. The first vector stays the same, but the second vector reverses to the opposite direction to become a negative vector.
\mathbf{a}-\mathbf{b}=\mathbf{a}+-\mathbf{b}Using vector a and vector b letβs see what happens.
We need the vector –b. The direction of the vector –b is opposite to the direction of the original vector b (but has the same magnitude).
So,
\textbf{a} - \textbf{b}= \textbf{a}+ - \textbf{b}We know from vector addition that when adding two vectors, we add the second onto the end of the first, as shown here:
The final answer is known as the resultant vector.
Therefore
In order to subtract a vector from an original vector:
Get your free vector subtraction worksheet of 20+ vectors questions and answers. Includes reasoning and applied questions.
DOWNLOAD FREEGet your free vector subtraction worksheet of 20+ vectors questions and answers. Includes reasoning and applied questions.
DOWNLOAD FREEVector subtraction is part of our series of lessons to support revision on vectors. You may find it helpful to start with the main vectors lesson for a summary of what to expect, or use the step by step guides below for further detail on individual topics. Other lessons in this series include:
Work out:
Subtract the second top number from the first top number
6-4=22Subtract the y components.
Subtract the second bottom number from the first bottom number
4-3=13Write the resultant vector.
Work out:
Subtract the x components.
Subtract the second top number from the first top number
3-5=-2Subtract the y components.
Subtract the second bottom number from the first bottom number
2-1=1Write the resultant vector.
Write the two answers as a column vector
Work out:
Subtract the x components.
Subtract the second top number from the first top number
2-2=0Subtract the y components.
Subtract the second bottom number from the first bottom number
4-6=-2Write the resultant vector.
Write the two answers as a column vector
Work out:
Subtract the x components.
Subtract the second top number from the first top number
-4-2=-6Subtract the y components.
Subtract the second bottom number from the first bottom number
3-1=2Write the resultant vector.
Write the two answers as a column vector
Work out:
Subtract the x components.
Subtract the second top number from the first top number
-5-(-3)=-2Subtract the y components.
Subtract the second bottom number from the first bottom number
2-(-2)=4Write the resultant vector.
Write the two answers as a column vector
Work out:
Subtract the x components.
Subtract the second top number from the first top number
2-(-4)=6Subtract the y components.
Subtract the second bottom number from the first bottom number
-1-(-3)=2Write the resultant vector.
Write the two answers as a column vector
Mistakes can easily be made when subtracting negative integers.
Make sure that negative numbers skills are well practiced.
E.g.
3-(-4)=3+4=7The order in which subtraction occurs is very important. Vector subtraction is NOT commutative and must be carried out in the stated order.
etc.
Column vectors only have 2 numbers within the brackets, they have the top number and the bottom number.
There is no need for any other punctuation marks such as commas or semicolons and there is no need for a line to separate the numbers.
The x component or the y component can be 0 . If both vector components are 0 then the final resultant vector would be the vector 0 . This is known as the null vector or the zero vector.
E.g.
1. Work out \textbf{v}-\textbf{w} :
\textbf{v}= \begin{pmatrix} \; 7 \;\\ \; 3 \; \end{pmatrix} \; and \; \textbf{w}= \begin{pmatrix} \; 4 \;\\ \; 1 \; \end{pmatrix}
2. Work out \textbf{c}-\textbf{d} :
\textbf{c}= \begin{pmatrix} \; 6 \;\\ \; 2 \; \end{pmatrix} \; and \; \textbf{d}= \begin{pmatrix} \; 3 \;\\ \; 7 \; \end{pmatrix}
3. Work out \textbf{b}-\textbf{a} :
\textbf{a}= \begin{pmatrix} \; -1 \;\\ \; 6 \; \end{pmatrix} \; and \; \textbf{b}= \begin{pmatrix} \; 5 \;\\ \; 4 \; \end{pmatrix}
4. Work out \textbf{p}-\textbf{q} :
\textbf{p}= \begin{pmatrix} \; -3 \;\\ \; 6 \; \end{pmatrix} \; and \; \textbf{q}= \begin{pmatrix} \; -2 \;\\ \; 4 \; \end{pmatrix}
5. Work out \textbf{s}-\textbf{r} :
\textbf{r}= \begin{pmatrix} \; 3 \;\\ \; 5 \; \end{pmatrix} \; and \; \textbf{s}= \begin{pmatrix} \; -2 \;\\ \; -1 \; \end{pmatrix}
6. Work out \textbf{e}-\textbf{d} :
\textbf{d}= \begin{pmatrix} \; -2 \;\\ \; 6 \; \end{pmatrix} \; and \; \textbf{e}= \begin{pmatrix} \; -4 \;\\ \; 3 \; \end{pmatrix}
1. Vector \textbf{v} is \begin{pmatrix} \; 3 \;\\ \; 1 \; \end{pmatrix}
Vector \textbf{w} is \begin{pmatrix} \; 2 \;\\ \; 4 \; \end{pmatrix}
Which of the following vectors is the answer to \textbf{w}-\textbf{v} ?
A | \quad \quad | B | \quad \quad | C | \quad \quad | D |
\begin{pmatrix} \; -1 \;\\ \; 3 \; \end{pmatrix} | \quad \quad | \begin{pmatrix} \; 1 \;\\ \; 3 \; \end{pmatrix} | \quad \quad | \begin{pmatrix} \; 1 \;\\ \; -3 \; \end{pmatrix} | \quad \quad | \begin{pmatrix} \; -1 \;\\ \; -3 \; \end{pmatrix} |
(1 mark)
A
(1)
2. Here are two vectors.
\textbf{m}= \begin{pmatrix} \; 2 \;\\ \; -4 \; \end{pmatrix} \; and \; \textbf{n}= \begin{pmatrix} \; 3 \;\\ \; -6 \; \end{pmatrix}
Work out \; \textbf{n}-\textbf{m}
(2 marks)
For the x component (top number)
(1)
For the y component (bottom number)
(1)
3. Here is a vector subtraction
\begin{pmatrix} \; \text{a} \;\\ \; -1 \; \end{pmatrix} – \begin{pmatrix} \; 2 \;\\ \; \text{b} \; \end{pmatrix} = \begin{pmatrix} \; 4 \;\\ \; 2 \; \end{pmatrix}
(a) Find the value of a .
(b) Find the value of b .
(2 marks)
(a)
a=6
(1)
(b)
b=-3
(1)
You have now learned how to:
Prepare your KS4 students for maths GCSEs success with Third Space Learning. Weekly online one to one GCSE maths revision lessons delivered by expert maths tutors.
Find out more about our GCSE maths tuition programme.