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Here we will learn about vector notation, including what vectors are and how we use notation in mathematics to write about them.

There are also vector worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

**Vector notation** is how we write vectors in mathematics.

A vector is a quantity which has both magnitude and direction. It can be used to show a movement.

We can write vectors in several ways:

- Using an
**arrow**, - Using
**boldface** **Underlined**.

E.g.

\overrightarrow{AB} =\textbf{a}=\underline{a}This diagram shows a vector representing the move from point A to point B.

- Parallel vectors with the
**same direction**and the**same length**are the**same**:

E.g.

Each of these all represent the same vector \textbf{a} .

- Parallel vectors of the same length with opposite directions are called
**negative vectors:**

E.g.

A vector representing the move from point B to point A would be in the opposite direction, but have the same length.

\overrightarrow{BA}=-\textbf{a}=-\underline{a}- A vector can be multiplied by a
**scalar**to change the length of it:

The length is also referred to as the magnitude of the vector

E.g.

- Vectors can also be added together:

E.g.

This diagram shows how to get from point A to point C, going via point B.

Vector \textbf{a} is added to vector \textbf{b} .

\begin{aligned} \overrightarrow{AC}&=\overrightarrow{AB}+\overrightarrow{BC}\\\\ &= \ \textbf{a} \ +\ \textbf{b}\\\\ \text{or handwritten as}\\\\ &=\ \underline{a} \ +\ \underline{b} \end{aligned}Adding a negative vector becomes subtracting.

\begin{aligned} &\textbf{a} \ + \ - \ \textbf{b}=\textbf{a} \ - \ \textbf{b}\\\\ &\text{or handwritten as}\\\\ &\underline{a} \ + \ - \ \underline{b} = \underline{a} \ - \ \underline{b} \end{aligned}In order to use vector notation:

**Check the starting point and the end point.****Decide the route.****Write the vector.****Simplify your answer.**

Get your free vector notation worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free vector notation worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEWrite the vector \overrightarrow{AO} in terms of \textbf{a} and \textbf{b}

**Check the starting point and the end point.**

The vector starts at point A and ends at point O.

2**Decide the route.**

Start at the starting point and go along the sides of the shape to the end point.

However, you can only go along the lines which have vectors.

Here we travel in the opposite direction to vector \textbf{a} .

3**Write the vector.**

Write the route from point A to point O.

\overrightarrow{AO}=-\textbf{a}=-\underline{a}Write the vector \overrightarrow{AC} in terms of \textbf{a} and \textbf{b}

**Check the starting point and the end point.**

\overrightarrow{AC}

The vector starts at point A and ends at point C.

**Decide the route.**

Start at the starting point and go along the sides of the shape to the end point.

However, you can only go along the lines which have vectors.

**Write the vector.**

Write the route from point A to point C.

\begin{aligned}
\overrightarrow{AC}&=\overrightarrow{AB}+\overrightarrow{BC}\\\\
&=\ \textbf{a} \ +\ \textbf{b}\\\\
\text{or handwritten as}\\\\
&=\ \underline{a} \ +\ \underline{b}
\end{aligned}

Write the vector \overrightarrow{BA} in terms of \textbf{a} and \textbf{b}

**Check the starting point and the end point.**

\overrightarrow{BA}

The vector starts at point B and ends at point A.

**Decide the route.**

Start at the starting point and go along the sides of the shape to the end point.

However, you can only go along the lines which have vectors. We can not go directly from point B to point A because there is no vector. We have to go via point C. As we need to go backwards along vector \textbf{b} , we need a negative vector.

**Write the vector.**

Write the route from point B to point A.

\begin{aligned} \overrightarrow{BA}&=\overrightarrow{BO}+\overrightarrow{OA}\\\\ &=\ -\textbf{b} \ +\ \textbf{a}\\ \text{or handwritten as}\\\\ &=\ -\underline{b} \ +\ \underline{a} \end{aligned}

Alternatively, the final answer could be written as:

\overrightarrow{BA}=\textbf{a}-\textbf{b}=\underline{a}-\underline{b}

Write the vector \overrightarrow{BC} in terms of \textbf{a} and \textbf{b}

**Check the starting point and the end point.**

\overrightarrow{BC}

The vector starts at point B and ends at point C.

**Decide the route.**

Start at the starting point and go along the sides of the shape to the end point.

However, you can only go along the lines which have vectors. We can not go directly from point B to point C. We have to go via point O and point A. As we need to go backwards along vector \textbf{b} , we need a negative vector.

**Write the vector.**

Write the route from point B to point C.

\begin{aligned}
\overrightarrow{BC}&=\overrightarrow{BO}+\overrightarrow{OA}+\overrightarrow{AC}\\\\
&=\ -\textbf{b} \ +\ \textbf{a} \ + 2\textbf{b}\\\\
\text{or handwritten as}\\\\
&=\ -\underline{b} \ +\ \underline{a} \ + \ 2\underline{b}
\end{aligned}

**Simplify your answer.**

To simplify we collect like terms. So the final answer is:

\overrightarrow{BC}=\textbf{a}+\textbf{b}=\underline{a}+\underline{b}

Write the vector \overrightarrow{CA} in terms of \textbf{a} and \textbf{b}

**Check the starting point and the end point.**

\overrightarrow{CA}

The vector starts at point C and ends at point A.

**Decide the route.**

Start at the starting point and go along the sides of the shape to the end point.

However, you can only go along the lines which have vectors. We can not go directly from point C to point A. We have to go via point B and point O. As we are going in the opposite direction at times, we will need negative vectors.

**Write the vector.**

Write the route from point C to point A.

\begin{aligned}
\overrightarrow{CA}&=\overrightarrow{CB}+\overrightarrow{BO}+\overrightarrow{OA}\\\\
&=\ -5\textbf{a} \ -\ 2\textbf{b} \ +\ 4\textbf{a}\\\\
\text{or handwritten as}\\\\
&=\ -5\underline{a} \ -\ 2\underline{b} \ + \ 4\underline{a}
\end{aligned}

**Simplify your answer.**

To simplify we collect like terms. So the final answer is:

\overrightarrow{CA}=-\textbf{a}-2\textbf{b}=-\underline{a}-2\underline{b}

Here is a hexagon.

Side *OA* is parallel to side *BE*

Side *OB* is parallel to side *CD*

Side *AC* is parallel to side *ED*

Write the vector \overrightarrow{OE} in terms of \textbf{a}, \; \textbf{b} and \textbf{c}

**Check the starting point and the end point.**

\overrightarrow{OE}

The vector starts at point O and ends at point E.

**Decide the route.**

Start at the starting point and go along the sides of the shape to the end point.

However, you can only go along the lines which have vectors. But we can use the information to add more vectors to the diagram.

**Write the vector.**

Write the route from point O to point E.

\begin{aligned}
\overrightarrow{OE}&=\overrightarrow{OA}+\overrightarrow{AC}+\overrightarrow{CD}+\overrightarrow{DE}\\\\
&=\ \ \textbf{a} \ +\ \textbf{c} \ +\ \textbf{b} \ -\ \textbf{c}\\\\
\text{or handwritten as}\\\\
&=\ \ \underline{a} \ +\ \underline{c} \ + \ \underline{b} \ - \ \underline{c}
\end{aligned}

**Simplify your answer.**

To simplify we collect like terms. So the final answer is:

\overrightarrow{OE}=\textbf{b}+\textbf{a}=\underline{b}+\underline{a}

Alternatively, we could have gone from point O to point B and then to point E.

This would be

\begin{aligned} \overrightarrow{OE}&=\overrightarrow{OB}+\overrightarrow{BE}\\\\ &=\ \textbf{b} \ +\ \textbf{a}\\\\ \text{or handwritten as}\\\\ &=\ \underline{b} \ +\ \underline{a} \end{aligned}

Which is identical to our previous answer.

**Final answers may just involve one vector**

A question may ask you to write a vector in terms of vector \textbf{a} and vector \textbf{b} , but the final answer may just involve one of the vectors.

**Vectors can involve fractions or decimals**

Here is a diagram of vector \textbf{c} . A vector in the same direction, but half of its length will be \frac{1}{2}\textbf{c} or 0.5\textbf{a} .

1. Write the vector \overrightarrow{BO} in terms of \textbf{a} and \textbf{b}

\textbf{b}

\textbf{a}+\textbf{b}

\textbf{a}-\textbf{b}

-\textbf{b}

We need to go in the opposite direction to vector \textbf{b} , so we need a negative vector \textbf{b} .

\overrightarrow{BO}=-\textbf{b}=-\underline{b}

2. Write the vector \overrightarrow{OB} in terms of \textbf{a} and \textbf{b}

\textbf{a}-3\textbf{b}

\textbf{a}+\textbf{b}

\textbf{a}+3\textbf{b}

\textbf{a}-\textbf{b}

We need to go from point O to point B via point A.

\begin{aligned} \overrightarrow{OB}&=\overrightarrow{OA}+\overrightarrow{AB}\\\\ &=\ \ \textbf{a} \ +\ 3\textbf{b}\\\\ \text{or handwritten as}\\\\ &=\ \ \underline{a} \ +\ 3\underline{b} \end{aligned}

3. Write the vector \overrightarrow{AB} in terms of \textbf{a} and \textbf{b}

\textbf{b}-\textbf{a}

2\textbf{b}+\textbf{a}

\textbf{a}+\textbf{b}

\textbf{a}-\textbf{b}

We need to go from point A to point B via point O. We need to go in the opposite direction to vector \textbf{a} , so we need a negative vector \textbf{a} .

\begin{aligned} \overrightarrow{AB}&=\overrightarrow{AO}+\overrightarrow{OB}\\\\ &= -\textbf{a} \ +\ \textbf{b}\\\\ &= \ \ \textbf{b} \ – \ \textbf{a}\\\\ \text{or handwritten as}\\\\ &=\ \ \underline{b} \ -\ \underline{a} \end{aligned}

4. Write the vector \overrightarrow{BC} in terms of \textbf{a} and \textbf{b}

7\textbf{b}-\textbf{a}

-\textbf{b}-\textbf{a}

\textbf{a}+7\textbf{b}

\textbf{a}-\textbf{b}

We need to go from point B to point C via point A and point D. We need to go in the opposite direction to vector 4\textbf{b} , so we need a negative vector.

We need to go in the opposite direction to vector \textbf{a} , so we need another negative vector. When we have worked out the route, we need to simplify the answer.

\begin{aligned} \overrightarrow{BC}&=\overrightarrow{BA} \ +\ \overrightarrow{AD} \ + \ \overrightarrow{DC}\\\\ &= -4\textbf{b} \ -\ \textbf{a} \ + \ 3\textbf{b}\\\\ &= \ \ -\textbf{b} \ + \ \textbf{a}\\\\ \text{or handwritten as}\\\\ &=\ \ -\underline{b} \ -\ \underline{a} \end{aligned}

5. Write the vector \overrightarrow{BA} in terms of \textbf{a} and \textbf{b}

2\textbf{a}+3\textbf{b}

12\textbf{a}+3\textbf{b}

-2\textbf{a}+3\textbf{b}

12\textbf{a}-3\textbf{b}

We need to go from point B to point A via points C and D. We need to go in the opposite direction to vector 7\textbf{a} , so we need a negative vector. When we have worked out the route, we need to simplify the answer.

\begin{aligned} \overrightarrow{BA}&=\overrightarrow{BC} \ + \ \overrightarrow{CD} \ + \ \overrightarrow{DA}\\\\ &= -7\textbf{a} \ +\ 3\textbf{b} \ + \ 5\textbf{a}\\\\ &= \ \ -2\textbf{a} \ + \ 3\textbf{b}\\\\ \text{or handwritten as}\\\\ &=\ \ -2\underline{a} \ + \ 3\underline{b} \end{aligned}

6. Write the vector \overrightarrow{OD} in terms of \textbf{a}, \; \textbf{b} and \textbf{c}

Here is a hexagon.

Side *OA* is parallel to side *CD*

Side *AB* is parallel to side *DE*

Side *BC* is parallel to side *OE*

\textbf{b}-\textbf{c}

\textbf{a}+\textbf{b}+\textbf{c}

2\textbf{a}+\textbf{b}+\textbf{c}

\textbf{b}+\textbf{c}

We need to go from point O to point D. Use the facts about parallel sides to add in more vectors.

\begin{aligned} \overrightarrow{OD}&=\overrightarrow{OE} + \overrightarrow{ED}\\\\ &=\ \textbf{c} \ + \ \textbf{b}\\\\ &= \ \textbf{b} \ + \ \textbf{c}\\\\ \text{or handwritten as}\\\\ &=\ \underline{b} \ + \ \underline{c} \end{aligned}

1. *OABC * is a trapezium

*AB *is parallel to *OC*.

(a) Find, in terms of \textbf{b} , the vector \overrightarrow{BA}

(b) Find, in terms of \textbf{a} and \textbf{b} , the vector \overrightarrow{CA}

**(2 marks)**

Show answer

(a)

\overrightarrow{BA}=-5\textbf{b}=-5\underline{b}

**(1)**

(b)

\overrightarrow{CA}=\textbf{a} \ – \ 3\textbf{b}=\underline{a} \ – \ 3\underline{b}

**(1)**

2. *ABCD* is a parallelogram.

The diagonals of the parallelogram intersect at *O*.

\begin{aligned} \overrightarrow{OA}=\textbf{a}\\ \overrightarrow{OB}=\textbf{b} \end{aligned}

(a) Find, in terms of \textbf{a} , the vector \overrightarrow{AO}

(b) Find, in terms of \textbf{a} , the vector \overrightarrow{CA}

(c) Find, in terms of \textbf{a} and \textbf{b} , the vector \overrightarrow{BA}

**(3 marks)**

Show answer

(a)

\overrightarrow{AO}=-\textbf{a} =-\underline{a}

**(1)**

(b)

\overrightarrow{CA}=2\textbf{a} =2\underline{a}

**(1)**

(c)

\overrightarrow{BA}=\textbf{a} \ – \ \textbf{b} =\underline{a} \ – \ \underline{b}

**(1)**

3. *ABCD * is a trapezium.

*AB *is parallel to *DC*.

(a) Find, in terms of \textbf{a} , the vector \overrightarrow{AO}

(b) Find, in terms of \textbf{a} and \textbf{b} , the vector \overrightarrow{DB}

(c) Find, in terms of \textbf{a} and \textbf{b} , the vector \overrightarrow{CB}

**(4 marks)**

Show answer

(a)

\overrightarrow{AD}=-5\textbf{a} =-5\underline{a}

**(1)**

(b)

\overrightarrow{DB}=5\textbf{a} \ + \ 9\textbf{b} =5\underline{a} \ + \ 9\underline{b}

**(1)**

(c)

\overrightarrow{CB}=-7\textbf{b} \ + \ 5\textbf{a} \ + \ 9\textbf{b} =-7\underline{b} \ + \ 5\underline{a} \ + \ 9\underline{b}

For the correct route

**(1)**

\overrightarrow{CB}=5\textbf{a} \ + \ 2\textbf{b} = 5\underline{a} \ + \ 2\underline{b}

For the correct simplified answer

**(1)**

You have now learned how to:

- Use vector notation to write vector
- Use vector notation to solve a geometry problem

Vectors are very useful and can be extended beyond GCSE mathematics. Vector analysis is the branch of mathematics that studies vectors.

At GCSE we study two-dimensional vectors, but we can also look at three-dimensional vectors.

In A Level maths cartesian coordinates are also referred to as position vectors when we use a coordinate system as our vector space. In maths a vector is an element of a vector space.

Vectors can also be extended further by learning how to multiply two vectors together using the dot product. This is also known as the scalar product of two vectors. It is possible to multiply vectors and this is known as a cross product. This is also known as the vector product of two vectors.

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