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Here we break down everything you need to know about expanding brackets. You’ll learn how to expand single brackets and double brackets in order to leave a simplified algebraic expression.

At the end you’ll find expanding brackets worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

This lesson is part of our series on algebraic expressions. You may find it helpful to start with the main algebraic expressions lesson for a summary of what to expect and then also work through the following:

- Algebraic expressions
- Simplifying algebraic expressions
- Expand and simplify
- Rearranging equations
- Make x the subject
- Substitution

Expanding brackets is the process by which we remove brackets.

Expanding brackets is the reverse process of factorisation and is sometimes referred to as multiplying out.

To expand brackets we multiply everything outside of the bracket, by everything inside of the bracket.

There are three main types of expanding brackets, each of which is covered below:

**Expanding single brackets**

3(2x + 1) = 6x + 3

Expressions with **two** terms like **binomials**.

**Expanding double brackets**

(x + 5)(x – 1) = x^{2}+ 4x – 5

Expressions with **three** terms like **x ^{2} + 4x − 5**

Terms that are raised to the **power of 2** like

**Expanding triple brackets**

(x + 1)(x + 2)(x + 3) = x^{3} + 6x + 11x + 6

A **polynomial** expression consists of **two or more algebraic terms**.

To expand a single bracket we multiply the term outside of the bracket by everything inside of the bracket.

In order to expand single brackets:

- Multiply the term outside of the bracket by the first term inside the bracket.
- Multiply the term outside the bracket by the second term inside the bracket.

Expand:

2(x + 3)

✕ | x | + 3 |

2 | 2x |

- Multiply the term outside of the bracket
(2) by the first term inside the bracket(x) .

2Multiply the value outside the bracket

✕ | x | + 3 |

2 | 2x | + 6 |

*The answer is positive so we need to write + 6*.

Expand:

− 3(y − 4)

Multiply the term outside of the bracket (− 3) by the first term inside the bracket (y).

✕ | y | − 4 |

− 3 | − 3y |

*− *✕* + = − so the answer is negative*.

Multiply the term outside the bracket (− 3) by the second term inside the bracket (− 4).

✕ | y | − 4 |

− 3 | − 3y | + 12 |

*− *✕* − = + so the answer is positive. We need to write + 12.*

Expand:

3x(4x − 2y)

Multiply the term outside of the bracket (3x) by the first term inside the bracket (4x).

✕ | 4x | − 2y |

3x | 12x^{2} |

^{2}

Multiply the term outside the bracket (3x) by the second term inside the bracket (− 2y).

✕ | 4x | − 2y |

3x | 12x^{2} | − 6xy |

*− ✕ + = − so the answer is negative. We need to write − 6xy.*

^{2} − 6xy

Expand:

2x(3 − 5y + 6x^{2})

Multiply the value outside of the bracket (2x) by the first term inside the bracket (3).

✕ | 3 | − 5y | 6x^{2} |

2x | 6x |

a) Multiply the value outside the bracket (2x) by the second term inside the bracket (− 5y).

✕ | 3 | − 5y | 6x^{2} |

2x | 6x | − 10xy |

*− ✕ + = − so the answer is negative. We need to write − 10xy.*

b) Multiply the value outside the bracket (2x) by the third term inside the bracket (6x^{2}).

✕ | 3 | − 5y | 6x^{2} |

2x | 6x | − 10xy | + 12x^{3} |

^{2} = + 12x^{3}

*The answer is positive so we need to write +12x ^{3}. *

\[2x( 3 – 5y + 6x^2) = \]

\[6x - 10xy + 12x^3\]

1. Expand: 6(y − 2)

Show answer

= 6y − 12

2. Expand: − 2(x + 6)

Show answer

= - 2x − 12

3. Expand: y(2y − 3)

Show answer

= 2y^{2} − 3y

4. Expand: - 5x(2x + 4)

Show answer

= − 10x^{2} − 20x

5. Expand: 4(8 − 3x + 2y)

Show answer

= 32 − 12x + 8y

6. Expand: 3y(2 + 7y − 4x)

Show answer

= 6y + 21y^{2} − 12xy

To expand double brackets we multiply every term in the first bracket, by every term in the second bracket.

In order to expand double brackets follow these steps:

- Draw a grid and insert the terms of the first and second brackets.
- Fill in the grid by multiplying each of the terms together.
- Write out each of the terms and simplify the expression by collecting like terms.

In order to expand double brackets:

- Draw a grid and insert the terms of the first and second brackets.
- Fill in the grid by multiplying each of the terms together.
- Write out each of the terms and simplify the expression by collecting like terms.

Expand and simplify:

(x+2)(x+3)

- Draw a grid and insert the terms of the first and second brackets.

✕ | x | + 3 |

x | ||

+ 2 |

2Fill in the grid my multiplying each of the terms together.

✕ | x | + 3 |

x | x^{2} | + 3x |

+ 2 | + 2x | + 6 |

x ✕ x = x^{2}x ✕ 3 = 3x x ✕ 2 = 2x 2 ✕ 3 = 6

3Write out each of the terms and simplify the expression by collecting like terms.

x^{2}+ 3x + 2x + 6 x^{2}+ 5x + 6

Expand and simplify:

(x + 5)(x − 1)

Draw a grid and insert the terms of the first and second brackets.

✕ | x | − 1 |

x | ||

+ 5 |

Fill in the grid my multiplying each of the terms together.

✕ | x | − 1 |

x | x^{2} | − x |

+ 5 | + 5x | − 5 |

x ✕ x = x^{2}x ✕ − 1 = − x

*+ ✕ − = − so the answer is negative.*

x ✕ 5 = 5x 5 ✕ − 1 = − 5

*+ ✕ − = − so the answer is negative.*

Write out each of the terms and simplify the expression by collecting like terms.

x^{2}− x + 5x − 5 x^{2}+ 4x − 5

Expand and simplify:

(2x − 3)(x + 4)

Draw a grid and insert the terms of the first and second brackets.

✕ | x | + 4 |

2x | ||

− 3 |

Fill in the grid my multiplying each of the terms together.

✕ | x | + 4 |

2x | 2x^{2} | + 8x |

− 3 | − 3x | − 12 |

2x ✕ x = 2x^{2}2x ✕ 4 = 8x x ✕ − 3 = − 3x

*+ ✕ − = − so the answer is negative.*

4 ✕ − 3 = − 12

*+ ✕ − = − so the answer is negative.*

Write out each of the terms and simplify the expression by collecting like terms.

2x^{2}+ 8x − 3x − 12 2x^{2}+ 5x − 12

Expand and simplify:

(3x − 4)^{2}

Draw a grid and insert the terms of the first and second brackets.

(3x − 4)^{2}= (3x − 4)(3x − 4)

*Remember: when we square something (raise it to the power of 2) we multiply it by itself.*

✕ | 3x | − 4 |

3x | ||

− 4 |

Fill in the grid my multiplying each of the terms together.

✕ | 3x | − 4 |

3x | 9x^{2} | − 12x |

− 4 | − 12x | + 16 |

3x ✕ 3x = 9x^{2}3x ✕ − 4 = − 12x 3x ✕ − 4 = − 12x

*+ ✕ − = − so the answer is negative.*

− 4 ✕ − 4 = + 16

*− ✕ − = + so the answer is positive.*

Write out each of the terms and simplify the expression by collecting like terms.

9x^{2}− 12x − 12x + 16 9x^{2}− 24x + 16

1. Expand and simplify: (x + 5)(x + 6)

Show answer

= x^{2} + 11x + 30

2. Expand and simplify: (x − 4)(x + 2)

Show answer

= x^{2} − 2x − 8

3. Expand and simplify: (2x + 3)(x + 4)

Show answer

=2x^{2} + 11x + 12

4. Expand and simplify: (3x − 2)(x + 1)

Show answer

= 3x^{2} + x − 2

5. Expand and simplify: (x − 4)^{2}

Show answer

= x^{2} − 8x + 16

6. Expand and simplify: (2x + 5)^{2}

Show answer

= 4x^{2} + 20x + 25

To expand triple brackets we first multiply the first two brackets together. We then multiply every term in this new expression by every term in the third bracket.

In order to expand triple brackets:

- Draw a grid, insert the terms of the first and second brackets, then fill it in by multiplying each of the terms together.
- Write out each of the terms and simplify the expression by collecting like terms.
- Draw a grid, insert the terms from this new expression and the third bracket, then fill it in by multiplying each of the terms together.
- Write out each of the terms and simplify the expression by collecting like terms.

Expand and simplify:

(x + 1)(x + 2)(x + 3)

- Draw a grid, insert the terms of the first and second brackets, then fill it in by multiplying each of the terms together.

✕ | x | + 2 |

x | x^{2} | + 2x |

+ 1 | + x | + 2 |

x ✕ x = x^{2}x ✕ 2 = 2x x ✕ 1 = x 1 ✕ 2 = 2

2Write out each of the terms and simplify the expression by collecting like terms.

x^{2}+ 2x + x + 2 x^{2}+ 3x + 2

3Draw a grid, insert the terms from this new expression and the third bracket, then fill it in by multiplying each of the terms together.

✕ | x^{2} | + 3x | + 2 |

x | x^{3} | + 3x^{2} | + 2x |

+ 3 | + 3x^{2} | + 9x | + 6 |

x ✕ x^{2}= x^{3}x ✕ 3x = 3x^{2}x ✕ 6 = 6x 3 ✕ x^{2}= 3x^{2}3 ✕ 3x = 9x 3 ✕ 6 = 18

4Write out each of the terms and simplify the expression by collecting like terms.

x^{3}+ 3x^{2}+ 3x^{2}+ 9x + 2x + 6 x^{3}+ 6x^{2}+ 11x + 6

Expand and simplify:

(x + 3)^{2}(x − 1)

Draw a grid, insert the terms of the first and second brackets, then fill it in by multiplying each of the terms together.

✕ | x | + 3x |

x | x^{2} | + 3x |

+ 3 | + 3x | + 9 |

(x + 3)^{2}= (x + 3)(x + 3) x ✕ x = x^{2}x ✕ 3 = 3x x ✕ 3 = 3x 3 ✕ 3 = 9

Write out each of the terms and simplify the expression by collecting like terms.

x^{2}+ 3x + 3x + 9 x^{2}+ 6x + 9

Draw a grid, insert the terms from this new expression and the third bracket, then fill it in by multiplying each of the terms together.

✕ | x^{2} | + 6x | + 9 |

x | x^{3} | + 6x^{2} | + 9x |

− 1 | − x^{2} | − 6x | − 9 |

x ✕ x^{2}= x^{3}x ✕ 6x = 6x^{2}x ✕ 9 = 9x − 1 ✕ x^{2}= − x^{2}− 1 ✕ 6x = − 6x − 1 ✕ 9= − 9

Write out each of the terms and simplify the expression by collecting like terms.

x^{3}+ 6x^{2}− x^{2}+ 9x − 6x − 9 x^{3}+ 5x^{2}+ 3x − 9

1. Expand and simplify: (x + 2)(x + 3)(x + 4)

Show answer

= x^{3} + 9x^{2} + 26x + 24

2. Expand and simplify: (x + 3)(x − 2)^{2}

Show answer

= x^{3} − x^{2} − 8x + 12

3. Expand and simplify: (2x + 1)^{3}

Show answer

= 8x^{3} + 12x^{2} + 6x + 1

**We must multiply the value outside the brackets by every term inside the brackets.**

2(6x^{2}− 3x) = 12x^{2}− 3x ✖

Here we have multiplied the value outside of the brackets by the first term inside of the bracket, but not the second term.

The correct answer is ^{2} − 3x) = 12x^{2} − 6x

We need to multiply all the terms inside the bracket.

**For two numbers to multiply to give a + their signs must be the same.**

+ ✕ + = +

− ✕ − = +

e.g. 2 ✕ 3 = 6

e.g. − 2 ✕ − 3 = 6

4 ✕ 5 = 20

− 4 ✕ − 5 = 20

**For two numbers to multiply to give a − their signs must be different.**

+ ✕ − = −

− ✕ + = −

e.g. 2 ✕ − 3 = − 6

e.g. − 2 ✕ 3 = − 6

4 ✕ − 5 = − 20

− 4 ✕ 5 = − 20

`− 4(3y − 5) = − 4y − 20 ✖`

Here we have not used − ✕ − = +

− 4 ✕ − 5 = + 20

The correct answer is

**When we square something, we multiply it by itself.**

3^{2}= 3 ✕ 3 x^{2}= x ✕ x (5y)^{2 }= 5y ✕ 5y

**When we square a bracket, we multiply it by the entire bracket.**

(x + 3)^{2}= (x + 3)(x + 3) ✔ NOT x^{2}+ 9 ✖

1. Expand: 3(x - 2)

Show answer

3x - 6

(1 mark)

2. Expand: 4x(2x - 7)

Show answer

8x^{2} - 28x

(1 mark)

3. Expand and simplify: 5(x - 3) - 3(x + 5)

Show answer

2x - 30

(2 marks)

Download a free expanding brackets worksheet with 20+ reasoning and applied questions, answers and mark scheme to help your students prepare for GCSEs. Includes reasoning and applied questions.

You have now learned how to:

- Multiply a single term over a bracket
- Expand products of 2 or more binomials

- Expand and simplify
- Factorising
- Factorising single brackets
- Factorising quadratics
- Difference of two squares
- Solving equations
- Quadratic equations (factorising)

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