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Skip counting Money word problems Decimal number line Calculator skillsHere you will learn about absolute value, including what it is, how to find it, and its connection to real-world situations.
Students will first learn about absolute value as part of the number system in 6th grade.
Absolute value is the distance a number is from 0.
To find the absolute value, place the number on a number line and measure the distance from 0.
For example,
What is the absolute value of -2?
-2 is 2 away from 0, so the absolute value is 2.
To write this mathematically, use the absolute value symbol, which is two vertical bars around a number or expression: |-2|=2.
This equation reads βthe absolute value of -2 is 2 β.
Now, what is |2|= ?
2 is also 2 away from 0, so the absolute value is 2. Both -2 and 2 have the same absolute value, because they are the same distance from 0.
How does this relate to 6th grade math?
In order to find the absolute value:
In order to understand absolute value in a real-world situation:
Use this quiz to check your grade 6 studentsβ understanding of types of numbers. 10+ questions with answers covering a range of 2nd, 4th and 6th grade types of numbers topics to identify areas of strength and support!
DOWNLOAD FREEUse this quiz to check your grade 6 studentsβ understanding of types of numbers. 10+ questions with answers covering a range of 2nd, 4th and 6th grade types of numbers topics to identify areas of strength and support!
DOWNLOAD FREESolve | 6.8 |= \, ?
2Measure the distance from zero.
6.8 is 6.8 away from 0, so |6.8|= 6.8.
Notice that even though the direction from 6.8 to 0 is down (or negative), the absolute distance is not – it only shows the distance, not the direction.
Solve \bigl|-\cfrac{7}{8}\bigr|= \, ?
Find the value on a number line.
Measure the distance from zero.
-\cfrac{7}{8} \, is \, \cfrac{7}{8} \, away from 0, so \bigl|-\cfrac{7}{8}\bigr|=\cfrac{7}{8} \, .
Solve |-15|= \, ?
Find the value on a number line.
Measure the distance from zero.
-15 is 15 away from 0, so |-15|= 15.
The number line shows the temperature in ^{\circ}C.
Find the absolute value.
3^{\circ} is 3^{\circ} away from 0^{\circ}, so |3^{\circ}|= 3^{\circ}.
Explain the absolute value in terms of the real-world situation.
The actual temperature is 3^{\circ} above freezing, so the | 3^{\circ} | is the distance from the freezing/melting point, which is at 0^{\circ}C.
The number line shows the balance on a cafeteria account.
Find the absolute value.
-\$3.50 is \$3.50 away from \$0, so |-\$3.50|= \$3.50.
Explain the absolute value in terms of the real-world situation.
The actual balance is -\$3.50, so the |-\$3.50| is the distance from having no money (neither debt nor credit), which is at \$0.
The number line shows the elevation in kilometers.
Find the absolute value.
1 \, \cfrac{6}{10} \mathrm{~km} is 1 \, \cfrac{6}{10} \mathrm{~km} away from 0 \mathrm{~km}, so \bigl|1 \cfrac{6}{10} \mathrm{~km}\bigr|=1 \cfrac{6}{10} \mathrm{~km}.
Explain the absolute value in terms of the real-world situation.
The actual elevation is 1 \, \cfrac{6}{10} \mathrm{~km} above sea level, so the \bigl|1 \, \cfrac{6}{10} \mathrm{~km}\bigr| is the distance from sea level, which is 0 \mathrm{~km}.
1. Complete the equation: |18|= \, ?
Show 18 on a number line and measure the distance from 0.
18 is 18 away from 0, so |18|= 18.
Notice that even though the direction from 18 to 0 is down (or negative), the absolute distance is not – it only shows the distance, not direction.
2. Complete the equation: |-0.2|= \, ?
Show -0.2 on a number line and measure the distance from 0.
-0.2 is 0.2 away from 0, so |-0.2|= 0.2.
3. Complete the equation: \bigl|9 \cfrac{3}{7}\bigr|= \, ?
Show 9 \, \cfrac{3}{7} \, on a number line and measure the distance from 0.
9 \, \cfrac{3}{7} \, is 9 \, \cfrac{3}{7} \, away from 0, so \bigl|9 \, \cfrac{3}{7}\bigr|=9 \, \cfrac{3}{7} \, .
4. Which statement is true about the temperature 21^{\circ} \mathrm{C} ?
The absolute value is -21^{\circ} \mathrm{C}.
21^{\circ} \mathrm{C} is 21^{\circ} \mathrm{C} away from the freezing point.
-21^{\circ} \mathrm{C} is 21^{\circ} \mathrm{C} away from the freezing point.
The absolute value is 0^{\circ} \mathrm{C}
Find the absolute value.
21^{\circ} \mathrm{C} is 21^{\circ} \mathrm{C} away from 0^{\circ} \mathrm{C}, so \left|21^{\circ} \mathrm{C}\right|=21^{\circ} \mathrm{C}.
The temperature is 21^{\circ} \mathrm{C} above freezing, so the \left|21^{\circ} \mathrm{C}\right| is the distance from the freezing point, which is 0^{\circ} \mathrm{C}.
5. Which statement is true for an account balance -\$0.75?
The absolute value is \$0.00.
The absolute value is -\$0.75.
\$0.75 is -\$0.75 away from no debt.
-\$0.75 is \$0.75 away from no debt.
Find the absolute value.
-\$0.75 is \$0.75 away from \$0.00, so \left|-\$0.75 \right|=\$0.75.
The account balance is a debt of \$0.75, so the \left|-\$0.75 \right| is the distance from \$0.00, which is no debt.
6. Which statement is true for the elevation -45m?
\left|-45 \, m \right| is the distance from sea level.
45 \, m is -45 \, m away from sea level.
\left|0 \, m \right| is the distance from sea level.
The absolute value is -45 \, m.
Find the absolute value.
-45 \, m is 45 \, m away from 0 \, m, so \left|-45 \, m \right|= 45 \, m.
-45 \, m is 45 \, m below sea level, so the \left|-45 \, m \right| is the distance from sea level, which is 0 \, m.
This page is just an introduction to absolute value. In later standards, students will learn how to solve and graph absolute value equations and absolute value functions that involve any real number, including square roots. They will also learn how to solve and graph inequalities that include absolute value.
Yes, an expression can have more than one, such as |4-3|+\left|5^2+2\right|. Just like an expression can have multiple operations or sets of parentheses, it can have multiple absolute value operations. To solve, follow the order of operations within the absolute value symbols first.
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