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3D shapes Pyramid shape Volume Volume of a prismHere you will learn about the volume of a pyramid, including how to find the volume and how to apply it to real world scenarios.

Students first learn about the volume of a pyramid with their work in geometry in the 7 th grade and expand that knowledge as they progress through high school.

The **volume** **of a pyramid** is how much **space** there is inside the pyramid. Volume is measured in cubic units.

For example, the number of small red balls inside the pyramid represents the approximate volume of the pyramid because it represents the space inside the pyramid.

Did you know that the volume of a pyramid is the same as \cfrac{1}{3} \, the volume of a prism with the same height and base?

Let’s look at an example by comparing the volumes of a pyramid and a prism with the same heights (perpendicular height) and the same square bases.

Recall how to find the volume of a prism,

V=\text { area of the base } \cdot \text { height }

The base of the prism is a square with side length of 4 units.

The area of the base is 4 \times 4=16

The height of the prism is 9 units, so the volume is:

\begin{aligned}& V=(16) \times 9 \\\\ & V=144\end{aligned}

The volume of the prism is 144 \text {~units}^3.

The volume of a pyramid is:

V=\cfrac{1}{3} \, \times \text { area of the base } \times \text { height }

The base of the pyramid is a square, the same as the prism, with side lengths of 4 units.

The area of the base is 4 \times 4=16

The height of the pyramid is 9 units, so the volume is:

\begin{aligned}& V=\cfrac{1}{3} \times 16 \times 9 \\\\ & V=48\end{aligned}

The volume of the pyramid is 48 \text {~units}^3.

\cfrac{1}{3} \times 144=48 → one-third the volume of the prism is the volume of the pyramid

To find the volume of a pyramid, you can always use:

V=\cfrac{1}{3} \times \text { area of the base } \times \text { height }

You can also use the formula:

V=\cfrac{1}{3} \, Bh

B = \text { area of the base}

h = \text { perpendicular height of the 3D object }

How does this apply to 7 th grade math?

**Grade 7 – Geometry (7.G.B.6)**Solve real-world and mathematical problems involving area, volume and surface area of two- and three-dimensional objects composed of triangles, quadrilaterals, polygons, cubes, and right prisms.

In order to calculate the volume of a pyramid:

**Calculate the area of the base.****Substitute values into the formula and solve.****Write the answer, including the units.**

Use this quiz to check your grade 6 to 8 students’ understanding of volume. 10+ questions with answers covering a range of 6th, 7th and 8th grade volume topics to identify areas of strength and support!

DOWNLOAD FREEUse this quiz to check your grade 6 to 8 students’ understanding of volume. 10+ questions with answers covering a range of 6th, 7th and 8th grade volume topics to identify areas of strength and support!

DOWNLOAD FREEThe Great Pyramid in Egypt is 137 \, meters in height and has a square base that has an area of 52,900 \text { meters }{ }^2. What is the volume of the Great Pyramid rounded to the nearest whole number?

**Calculate the area of the base.**

The base of the Great Pyramid is a square. The area of the base is given to be 52,900 \text { meters}^2.

2**Substitute values into the formula and solve.**

The height of the Great Pyramid is 137 \, meters.

To find volume of a pyramid, you can use:

\begin{aligned}& V=\cfrac{1}{3} \times \text { area of base } \times \text { height } \\\\ & V=\cfrac{1}{3} \times52,900 \times 137 \\\\ & V=2,415,766.67 \end{aligned}

Rounded to the nearest whole number is 2,415,767.

3**Write the answer, including the units.**

The volume of the Great Pyramid is about 2,415,767 \text { meters }^3.

Find the volume of the pyramid.

**Calculate the area of the base.**

The base of the pyramid is a square with side length 6 \, cm.

Area of a square is b \times h

\begin{aligned}& \text { Area of base }=6 \times 6 \\\\
& \text { Area of base }=36\end{aligned}

**Substitute values into the formula and solve.**

To find the volume of a pyramid you can use:

\begin{aligned}& V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\
& \text { area of the base }=36 \\\\
& \text { height }=8 \\\\
& V=\cfrac{1}{3} \times 36 \times 8 \\\\
& V=96\end{aligned}

**Write the answer, including the units.**

The volume of the pyramid is 96 \mathrm{~cm}^3.

Find the volume of the rectangular pyramid.

**Calculate the area of the base.**

The base of the pyramid is a rectangle with side lengths 1 inch and 2 inches.

Area of a rectangle is b \times h

\begin{aligned}& \text { Area of base }=1 \times 2 \\\\
& \text { Area of base }=2\end{aligned}

**Substitute values into the formula and solve.**

To find the volume of a pyramid you can use:

\begin{aligned} & V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\ & \text { area of the base }=2 \\\\ & \text { height }=2 \\\\ & V=\cfrac{1}{3} \times 2 \times 2 \\\\ & V=\cfrac{4}{3}=1 \cfrac{1}{3}\end{aligned}

**Write the answer, including the units.**

The volume of the pyramid is 1 \cfrac{1}{3} \text { inches}^3.

The volume of a triangular pyramid that has a triangular base with an area of 33 \text { units}^2 and a perpendicular height of 15 \, units.

**Calculate the area of the base.**

The base is a triangle with an area of 33 \text { units}^2.

**Substitute values into the formula and solve.**

To find the volume of a pyramid you can use:

\begin{aligned}& V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\
& \text { area of the base }=33 \\\\
& \text { height }=15 \\\\
& V=\cfrac{1}{3} \times 33 \times 15 \\\\
& V=165\end{aligned}

**Write the answer, including the units.**

The volume of the pyramid is 165 \text { units}^3.

Calculate the volume of this pyramid.

**Calculate the area of the base.**

The base of the pyramid is a hexagon with an area of 14.2 \mathrm{~cm}^2.

**Substitute values into the formula and solve.**

To find the volume of a pyramid you can use:

\begin{aligned}& V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\
& \text { area of the base }=14.2 \\\\
& \text { height }=5.1 \\\\
& V=\cfrac{1}{3} \times 14.2 \times 5.1 \\\\
& V=24.14\end{aligned}

**Write the answer, including the units.**

The volume of the hexagonal pyramid is 24.14 \mathrm{~cm}^3.

Calculate the height of a rectangular pyramid with volume 40 \mathrm{~cm}^3 and base area 12 \mathrm{~cm}^2.

**Calculate the area of the base.**

The area of the base of the pyramid is 12 \mathrm{~cm}^2.

**Substitute values into the formula and solve.**

Using the formula for the volume of a pyramid:

\begin{aligned} & V =\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\ & \text {area of the base } =12 \\\\ & volume = 40 \\\\ & height = \, ? \end{aligned}

\begin{aligned} 40 & =\cfrac{1}{3} \times 12 \times h \\\\ 40 & =4 \times h \\\\ 40 & =4 h \\\\ \cfrac{40}{4} & =\cfrac{4 h}{4} \\\\ 10 & =h\end{aligned}

**Write the answer, including the units.**

The height of the pyramid is 10 \mathrm{~cm}.

- Provide opportunities for students to work with manipulatives of 3D objects so that they can gain a sense of what volume means in relation to the object.

- Infusing activities where students can see patterns in numbers to formulate understanding is essential for deep understanding. For example, understanding that the volume of a pyramid is \cfrac{1}{3} the volume of a prism.

- Worksheets have a place in the classroom for practicing skills. However, include real world problems that incorporate the volume of pyramids so that students can see the relevance of the concept in the world around them.

**The height is the perpendicular height**

Sometimes when you are provided with several dimensions of 3D objects, be sure that you are reading the perpendicular height dimension correctly.

For example, in the pyramid pictured below, 6 \, cm is the slant height and 4 \, cm is the perpendicular height.

The perpendicular height is needed to find the volume of a pyramid whereas the slant height is needed for surface area of a pyramid.

**Writing the incorrect units or forgetting to include the units**

Always include units when recording a measurement. Volume is measured in cubic units.

For example, \mathrm{mm}^3, \mathrm{~cm}^3, \mathrm{~m}^3, etc.

**Base is not always a square**

Like prisms, pyramids can have any polygon as a base and more importantly, if the base is a quadrilateral, you cannot assume that it is a square. Always check for the base dimensions when working with area.

- Volume
- Volume of a cylinder
- Volume of a hemisphere
- Volume of a sphere
- Volume of a cone
- Volume of a cube
- Volume of a triangular prism
- Volume formula
- Volume of a prism
- Volume of square pyramid
- Volume of a rectangular prism

1. Calculate the volume of the pyramid below.

45 \text{ cm}^3

15 \text{ cm}^3

11 \text{ cm}^3

30 \text{ cm}^3

To find the volume of a pyramid:

V=\cfrac{1}{3} \times \text { area of the base } \times \text { height }

The base of the pyramid is a square with side length 3 \, cm.

\begin{aligned}& \text { Area of base }=3 \times 3=9 \\\\ & \text { height }=5 \mathrm{~cm} \\\\ & V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\ & V=\cfrac{1}{3} \times 9 \times 5 \\\\ & V=15 \end{aligned}

The volume of the pyramid is 15 \mathrm{~cm}^3.

2. The heights of the prism and pyramid are equal, and the area of the bases is equal. If the volume of the prism is 96 \text{ units}^3, what is the volume of the pyramid?

48 \text { units}^3

288 \text { units}^3

96 \text { units}^3

32 \text { units}^3

The volume of a pyramid is \cfrac{1}{3} the volume of a prism with the same height and base area.

Since the volume of the prism is 96 you can either multiply 96 by \cfrac{1}{3} or divide 96 by 3 to get the volume of the pyramid.

96 \times \cfrac{1}{3}=32 \, or \, 96 \div 3=32

3. Calculate the volume of the pyramid below.

229.5 \text{ mm}^3

668.8 \text{ cm}^3

229.6 \text{ mm}^3

229.6 \text{ cm}^3

To find the volume of a pyramid:

V=\cfrac{1}{3} \times \text { area of the base } \times \text { height }

The base of the pyramid is a square with side length 8.7 \, cm.

\begin{aligned}& \text { Area of base }=8.7 \times 8.7=75.69 \\\\ & \text { height }=9.1 \\\\ & V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\ & V=\cfrac{1}{3} \times 75.69 \times 9.1 \\\\ & V=229.593\end{aligned}

The volume of the pyramid rounded to the nearest tenth is 229.6 \text{ mm}^3 .

4. Find the volume of a rectangular pyramid.

180 \text{ m}^3

120 \text{ m}^3

270 \text{ m}^3

540 \text{ m}^3

To find the volume of a pyramid:

V=\cfrac{1}{3} \times \text { area of the base } \times \text { height }

The base of the pyramid is a rectangle with side lengths 9 \, m and 6 \, m.

\begin{aligned}& \text { Area of base }=9 \times 6=54 \\\\ & \text { height }=10 \\\\ & V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\ & V=\cfrac{1}{3} \times 54 \times 10 \\\\ & V=180\end{aligned}

The volume of the rectangular pyramid is 180 \mathrm{~m}^3.

5. Find the volume of the triangular pyramid.

24 \mathrm{~cm}^3

12 \mathrm{~cm}^3

18 \mathrm{~cm}^3

36 \mathrm{~cm}^3

To find the volume of a pyramid:

V=\cfrac{1}{3} \times \text { area of the base } \times \text { height }

The base of the pyramid is a triangle.

The area of a triangle is: \cfrac{1}{2} \times b \times h

\begin{aligned}& \text { Area of base }=\cfrac{1}{2} \times 3 \times 4 \\\\ & \text { Area of base }=6 \\\\ & \text { height }=6 \\\\ & V=\cfrac{1}{3} \times \text { area of the base } \times \text { height } \\\\ & V=\cfrac{1}{3} \times 6 \times 6 \\\\ & V=12\end{aligned}

The volume of the triangular pyramid is 12 \mathrm{~cm}^3.

6. Find the height of the pyramid if the volume is 144 \, m^3 and the area of the base is 18 \, m^3.

24 \mathrm{~cm}

25 \mathrm{~cm}

8 \mathrm{~cm}

18 \mathrm{~cm}

Use the formula:

V=\cfrac{1}{3} \times \text { area of the base } \times \text { height }

Substitute the known values into the equation.

V= 144

\text{Area of base } = 18

\begin{aligned}& 144=\cfrac{1}{3} \times 18 \times h \\\\ & 144=6 \times h \\\\ & 144=6 h \\\\ & \cfrac{144}{6}=\cfrac{6 h}{6} \\\\ & 24=h\end{aligned}

The height of the pyramid is 24 \mathrm{~cm}.

No, there are many different types of pyramids that can have any polygonal base. For example, triangular pyramids have triangle bases, hexagonal pyramids have hexagon bases, square pyramids have square bases, rectangular pyramids have rectangular bases, Pentagonal pyramids have pentagonal bases, etc..

A polyhedron is a 3D object that is made up of polygonal sides.

The slant height of a pyramid is the height of the triangular faces of the pyramid. The perpendicular height is the distance from the apex (top vertex) of the pyramid to the center of the base of the pyramid.

A regular pyramid is a pyramid that has a regular polygon as its base.

You find the volume of a cone similarly to how you find the volume of a pyramid. Take one-third of the product of the area of the circular base and the height of the cone.

- Surface area
- Pythagorean theorem
- Congruence and similarity

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[FREE] Common Core Practice Tests (Grades 3 to 6)

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Prepare for math tests in your state with these Grade 3 to Grade 6 practice assessments for Common Core and state equivalents.

40 multiple choice questions and detailed answers to support test prep, created by US math experts covering a range of topics!