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3D shapes

Area of triangles and quadrilaterals Substituting into formulaeThis topic is relevant for:

Here we will learn about** prisms**, including what prisms are, types of prisms, nets of prisms and how to find the volume and surface area of prisms.

There are also volume and surface area of prisms worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

A **prism shape **is a polyhedron (a 3D shape made from polygons) with a constant cross section through one dimension. A prism shape has two congruent faces (identical ends).

For example, below are three different types of prisms:

The name of the prism is represented by the shape of its cross section.

A prism can be characterised using three features: faces, vertices and edges:

**Face**: a closed, flat surface surrounded by edges and vertices.**Edge**: connects two vertices with a straight line**Vertex**(pl. vertices): a point where two or more edges meet.

We can label the vertices (corners) of a prism to help us identify certain edges or faces. Below is an example of a triangular prism where the letters A – F represent the 6 vertices of the prism:

Using this labelling we can identify lengths such as the length AB :

We can also identify faces such as the face ABC :

The number of faces, edges and vertices can vary depending on the prism. Let’s look at some examples:

Shape | Faces | Edges | Vertices |

Triangular prism | 5 | 9 | 6 |

Cuboid (rectangular prism) | 6 | 12 | 8 |

Pentagonal prism | 7 | 15 | 10 |

L-shaped prism | 8 | 18 | 12 |

A prism is** irregular** if the cross section is not a regular polygon. For example, the L-shaped prism above is an **irregular prism** because the cross section is not a regular polygon.

If you unfold a three-dimensional shape and lay it down so that it is flat, the result would be the net of the shape. We can draw a net for any prism.

E.g.

The volume of a prism is how much space there is inside a prism.

To calculate the volume of a prism, we find the **area of the cross section and multiply it by the depth**.

*Volume of prism = Area of cross section × Depth*

Volume is measured in cubic units (e.g. mm^3, cm^3, m^3 etc).

**Step-by-step guide:** Volume of a prism

In order to do this I need to follow the steps:

**Write down the formula.****Calculate the area of the cross section.****Calculate the volume of the prism.****Write the answer, including the units.**

Get your free prism shape worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEGet your free prism shape worksheet of 20+ questions and answers. Includes reasoning and applied questions.

DOWNLOAD FREEBelow is a triangular prism:

The cross-sectional area of the prism is 43cm^2 . Calculate the volume of the prism.

**Write down the formula.**

*Volume of prism = Area of cross section × Depth*

2**Calculate the area of the cross section.**

The area of the cross section is already stated as 43cm^2 so we can move on to the next step.

3**Calculate the volume of the prism.**

\[\text{Volume of prism }=\text{Area of cross section }\times\text{Depth}\\
=43\times{9}\\
=387\]

4**Write the answer, including the units.**

The measurements on this prism are in cm so the volume will be measured in cm^3 .

Volume = 387cm^3 .

Work out the volume of the prism

**Write down the formula.**

*Volume of prism = Area of cross section × Depth*

2**Calculate the area of the cross section.**

\[\text{Area of a parallelogram }=b\times{h}\\
=8\times{3}\\
=24\]

3**Calculate the volume of the prism.**

\[\text{Volume of prism }=\text{Area of cross section }\times{Depth}\\
=24\times{20}\\
=480\]

4**Write the answer, including the units.**

The measurements on this prism are in m so the volume will be measured in m^3 .

Volume = 480m^3 .

Calculate the volume of the prism below.

**Write down the formula.**

*Volume of prism = Area of cross section × Depth*

2**Calculate the area of the cross section.**

\[\text{Area of cross section (trapezium) }=\frac{1}{2}(a+b)h\\
=\frac{1}{2}(5+9)\times{4}\\
=28\text{cm}^{2}\]

3**Calculate the volume of the prism.**

\[\text{Volume of prism }=\text{Area of cross section }\times\text{Depth}\\
=28\times{10}\\
=280\]

4**Write the answer, including the units.**

Volume = 280cm^3

The **surface area of a prism** is the **total area of all of the faces**.

The surface area of a prism is special because all of the** lateral faces are rectangles**. To calculate the surface area of a prism, we calculate **twice the area of the cross section** and add the** perimeter of the cross section** multiplied by the **depth** of the prism.

In general, the surface area of any prism is:

Surface Area of a Prism = 2A+PD

where:

- A = Area of the cross section
- P = Perimeter of the cross section
- D = Depth of the prism

**Step-by-step guide:** __Surface area of a prism__ (coming soon)

In order to work out the surface area of a prism:

**Calculate the area of the cross section.****Calculate the perimeter of the cross section.****Substitute all known values into the formula and solve.****Write the answer, including the units.**

Calculate the surface area of the following triangular prism.

**Calculate the area of the cross section.**

The cross section is a right angle triangle.

\[A=\frac{1}{2}(b\times{h})\\
=\frac{1}{2}(5\times{12})\\
=30\text{cm}^{2}\]

2**Calculate the perimeter of the cross section.**

The perimeter is the sum of the edges of the cross section:

P=5+12+13=30\text{cm}3**Substitute all known values into the formula and solve.**

Using the formula Surface Area of a Prism = 2A+PD , when A=30, P=30, and D=10 , we have

\[\text{SA}=2\times{30}+(30\times{10})\\
=60+300\\
=360.\]

4**Write the answer, including the units.**

The surface area of the triangular prism is 360cm^2 .

A cylinder has a height of 5m and a radius of 2m . Calculate the surface area of the cylinder. Write your answer in terms of \pi .

**Calculate the area of the cross section.**

The cross section is a circle.

\[A=\pi\times{r}^{2}\\
=\pi\times{2}^{2}\\
=4\pi\text{ m}^{2}\]

2**Calculate the perimeter of the cross section.**

The perimeter of a circle is the circumference:

P=\pi\times{2r}=\pi\times{2}\times{2}=4\pi\text{ m}3**Substitute all known values into the formula and solve.**

Using the formula Surface Area of a Prism = 2A+PD , when A=4, P=4, and D=5 , we have

\[\text{SA}=2\times{4\pi}+(4\pi\times{5})\\
=8\pi+20\pi\\
=28\pi.\]

4**Write the answer, including the units.**

The surface area of the triangular prism is 28\pi\text{ m}^{2}

Calculate the surface area of the compound prism below.

**Calculate the area of the cross section.**

The cross section is a kite.

\[A=\frac{1}{2}(w\times{h})\\
=\frac{1}{2}(16\times{21})\\
=168\text{cm}^{2}\]

2**Calculate the perimeter of the cross section.**

The perimeter is the sum of the edges of the cross section:

P=10+17+17+10=54\text{cm}3**Substitute all known values into the formula and solve.**

Using the formula Surface Area of a Prism = 2A+PD , when A=168, P=54, and D=4, we have

\[\text{SA}=2\times{168}+(54\times{4})\\
=336+216\\
=552.\]

4**Write the answer, including the units.**

The surface area of the compound prism is 552cm^2 .

**Calculating the volume instead of the surface area of the prism**

Volume and surface area are different things – volume tells us the space within the shape whereas surface area is the total area of the faces. To find surface area, work out the area of each face and add them together.

**A****ll of the rectangles have the same area**

Usually all of the rectangles have different areas (unless the shape of the cross section is a regular polygon)

**Missing faces**

This usually occurs on a compound prism where it can be difficult to visualise all of the face

**Missing/incorrect units**

You should always include units in your answer. Remember, volume is measured in units cubed (e.g. mm^3, cm^3, m^3 etc) and surface area is measured in units squared (e.g. mm^2, cm^2, m^2 etc)

**Calculating with different units**

You need to make sure all measurements are in the same units before calculating volume or surface area. (E.g. you can’t have some in cm and some in m )

**Using the wrong formula**

Be careful to apply the correct prism related formula to the correct question type.

1. Work out the volume of the prism

160cm^3

90cm^3

72cm^3

144cm^3

\text{Area of trapezium }=\frac{1}{2}(3+5)\times{4}\\
=16

\text{Volume of prism }=16\times{9}\\ =144\mathrm{cm}^{3}

2. Calculate the volume of the L-shaped prism.

630cm^3

990cm^3

526cm^3

17820cm^3

Area of cross section:

6 \times 5=30\\
3\times 11=33\\
30+33=63

\text{Volume of prism }=63 \times 10\\ =630\mathrm{cm}^{3}

3. The volume of this regular octagonal prism is 360m^3 . The area of the cross section is 45m^2 . Work out the length, L, of the prism.

16200m

8m

0.178m

6m

We know the area of the octagon is 45m^2 and the volume of the prism is 360m^3 .

\text{Volume of prism } = \text{Area of cross-section } \times \text{Depth}\\ 360=45 \times{D}\\ D=8

The depth of the prism is 8m .

4. Work out the surface area of this parallelogram prism

1056m^2

800m^2

960m^2

776m^2

Work out the area of each face:

Face | Area |

Front | 12×4=48 |

Back | 48 |

Bottom | 12×20=240 |

Top | 240 |

Left side | 5×20=100 |

Right side | 100 |

\text{Total surface area }=48+48+240+240+100+100=776\mathrm{m}^{2}

5. Work out the surface area of the prism. Write your answer in cm^2 .

252000cm^2

28200cm^2

4440cm^2

6600cm^2

1.2m=120cm

Face | Area |

Front | 70×30=2100 |

Back | 2100 |

Bottom | 70×120=8400 |

Top | 8400 |

Left side | 30×120=3600 |

Right side | 3600 |

\text{Total surface area }=2100+2100+8400+8400+3600+3600=28200\mathrm{cm}^{2}

6. Work out the surface area of the prism

484mm^2

398mm^2

374mm^2

286mm^2

Area of cross section:

Area A: \frac{1}{2} \times 8 \times 3=12

Area B: 4\times 8=32

Total area = 12+32=44

Work out the area of each face:

Face | Area |

Front | 44 |

Back | 44 |

Bottom | 8×11=88 |

Left side | 4×11=44 |

Top left | 5×11=55 |

Top right | 55 |

Right side | 44 |

\text{Total surface area }=44+44+88+44+55+55+44=374\mathrm{mm}^{2}

1. Work out the surface area of the prism

**(3 marks)**

Show answer

\frac{1}{2}(7+17) \times 12=144

For calculating the area of the cross section (trapezium)

**(1)**

272, 208, 208 and 112

For calculating the area of each lateral face (rectangles)

**(1)**

144+144+272+208+208+112=1088\mathrm{cm}^{2}

For calculating the total surface area of the prism

**(1)**

2. (a) The volume of this prism is 132m^3 . Work out the height of the prism.

(b) Hence calculate the surface area of the prism.

Show answer

(a)

5h

For calculating the area of the cross section

**(1)**

5h\times 12=60h

For calculating the volume of the prism

**(1)**

60h=132

For forming an equation to calculate the height of the prism

**(1)**

h=132\div{60}=2.2\text{m}

For the correct answer

**(1)**

(b)

5 \times 2.2=11

For calculating the area of the cross section

**(1)**

60(T), 60(B), 36(L), 36(R)

For calculating the area of the rectangular faces

**(1)**

\text{Total surface area: }11+11+60+60+36+36=214\mathrm{m}^{2}

For calculating the total surface area of the prism

**(1)**

3. Richard would like to fill the container below with apple juice.

Can Richard pour 5 litres of apple juice into the container without it overflowing?

**(4 marks)**

Show answer

\frac{1}{2} (12+16) \times 12=168

For calculating the area of the cross section (trapezium)

**(1)**

168 \times 25 = 4200\mathrm{cm}^{3}

For calculating the volume of the container

**(1)**

4200\mathrm{cm}^{3}=4.2\text{ litres}

For converting the volume into litres

**(1)**

No, it will not fit

For correct conclusion

**(1)**

You have now learned how to:

- Derive and apply formulae to calculate and solve problems involving prisms
- Use the properties of faces, surfaces, edges and vertices of prisms to solve problems in 3-D
- Calculate surface areas and volumes of composite solids

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#### GCSE Maths Papers - November 2022 Topics

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Practice paper packs based on the November advanced information for Edexcel 2022 Foundation and Higher exams.

Designed to help your GCSE students revise some of the topics that are likely to come up in November exams.