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Here you will learn about the properties of equality, including what they are and how to use them to solve problems.
Students will first learn about the properties of equality as part of operations and algebraic thinking in 3rd grade and continue to build on this knowledge in operations and algebraic thinking in 5th grade and expressions and equations in 6th grade.
Properties of equality are general rules that can be applied to an equation to create equivalent equations, which can be useful when comparing or solving equations.
The associative property states that numbers can be grouped in different ways when they are added or multiplied and the answer will stay the same.
For example,
When adding 7 + 8 + 10, the addends can be grouped in different ways:
For example,
When multiplying 4 \times 6 \times 2, the numbers can be grouped in different ways:
The associative property works for both addition and multiplication, because it creates equivalent equations.
(4 \times 6) \times 2=4 \times(6 \times 2) \quad and \quad (7+8)+10=7+(8+10)
Step-by-step guide: Associative property
The commutative property states that the order of numbers can be changed when they are added or multiplied and the answer will stay the same.
For example,
When adding 11 + 15, you can change the order of the addends:
For example,
When multiplying 6 \times 5, you can change the order of the numbers:
Notice that even with a different order, the sum and the product are the same.
Step-by-step guide: Commutative property
The distributive property says that multiplying the sum of two or more numbers is equivalent to separately multiplying the addends.
For example,
When multiplying 2 \times 7, you can break 7 up into 2 + 5.
The distributive property allows us to multiply each part and then add the products together.
Any way you solve the equivalent expressions, the product is the same.
Initially, the distributive property is used to think flexibly about numbers. In later grades, students learn to simplify algebraic expressions using the distributive property.
Step-by-step guide: Distributive property
Order of operations is the sequence of steps followed to evaluate an expression.
All the mathematical operations must be completed in a specific order, following the acronym PEMDAS.
PEMDAS stands for:
Parentheses, Exponents, Multiplication and Division, Addition and Subtraction
The operations of multiplication and division are given equal priority, and addition and subtraction are also given equal priority.
Always solve these operations starting from the left side and working to the right side, unless there are parentheses.
For example,
Step-by-step guide: Order of operations
Use this quiz to check your grade 3 to 6 studentsβ understanding of properties of equality. 10+ questions with answers covering properties of equality topics to identify learning gaps!
DOWNLOAD FREEUse this quiz to check your grade 3 to 6 studentsβ understanding of properties of equality. 10+ questions with answers covering properties of equality topics to identify learning gaps!
DOWNLOAD FREEHow does this relate to 3rd grade math, 5th grade math, and 6th grade math?
There are a lot of ways to use properties of equalities. For more specific step-by-step guides, check out the individual pages linked in the βWhat are properties of equalities?β section above or read through the examples below.
Use the associative property to solve 17 + 6 + 34.
The associative property can be used since all the numbers are being added.
2Change the grouping of the numbers and solve.
\begin{aligned} & 17+6+34 \\\\ & =17+(6+34) \quad \text{ *Group and add these numbers first} \\\\ & =17+40 \\\\ & =57 \end{aligned}
Use the associative property with friendly numbers to solve 77 + 16.
Check to see that the operation is addition or multiplication.
The associative property can be used, since all the numbers are being added.
Change the grouping of the numbers and solve.
\begin{aligned} & 77+16 \\\\ & =77+(3+13) \quad \text{ *Break apart } 16 \\\\ & =(77+3)+13 \quad \text{*Regroup and add these numbers first} \\\\ & =80+13 \quad \quad \;\;\; \text{ *80 is a friendly number because it is a multiple of } 10 \\\\ & =93 \end{aligned}
Notice that friendly numbers can be multiples of 10, because they are easier to add mentally.
Use the commutative property to create a friendly number and solve 3 \times 9 \times 2.
Check to see that the operation is addition or multiplication.
The commutative property can be used, since all the numbers are being multiplied.
Change the order of the numbers and solve.
\begin{aligned} & 3 \times 9 \times 2 \\\\ & =3 \times 2 \times 9 \quad \text{ *Change the order of the 9 and 2 }\\\\ & =6 \times 9 \quad \quad \; \text{ *Multiplying 3 and 2 creates 6} \\ &\quad \quad \quad \quad \quad \;\; \text{ - a single digit number easier to multiply }\\ & =54 \end{aligned}
Notice that when multiplying, friendly numbers can be single digit numbers.
If you know your basic facts, it is easier to solve 6 \times 9 than solving 3 \times 9 \times 2=27 \times 2.
Show how to solve 8 \times 11 using the distributive property.
Identify an equation multiplying two numbers.
You can use the distributive property with 8 \times 11, since it is multiplication.
Show one of the numbers being multiplied as a sum of numbers.
Either 8 or 11 can be shown as a sum, but for this example letβs break up 8 into 5 + 3.
8 \times 11=(5+3) \times 11
Multiply each number in the sum.
\begin{aligned} & (5+3) \times 11 \\\\ & =(5 \, \times \, 11)+(3 \times 11) \\\\ & =55+33 \end{aligned}
Add the partial products together to find the final product.
55 + 33 = 88
8 \times 11=88 can be solved using the distributive property.
Evaluate 40-8 \div 4.
Solve any calculations within parentheses.
There are no parentheses.
Solve for any exponents.
There are no exponents.
Solve any division and multiplication calculations.
The division you need to calculate is 8 \div 4=2.
Replacing 8\div{4} with 2 gives us the calculation 40-2.
Solve any addition and subtraction calculations.
40-2=38
So, 40-8 \div 4=38.
Evaluate 12+(16 \, \div \, 4 \times 5)^2.
Solve any calculations within parentheses.
Within the set of parentheses, you have the calculation 16 \div 4 \times 5. Since it is the operations of multiplication and division, work from left to right.
Completing the division, you have 16 \div 4=4.
Next, 4 \times 5=20.
Therefore, 16 \div 4 \times 5=20.
Replacing 16 \div 4 \times 5 with 20, you now have the updated calculation: 12+20^2.
Solve for any exponents.
Now solve 20^2=20 \times 20=400.
Updating the calculation, you now have 12+400.
Solve any division and multiplication calculations.
There is no division or multiplication left to solve.
Solve any addition and subtraction calculations.
12+400=412 which gives us the final answer:
12+(16 \div 4 \times 5)^2=412
or
\begin{aligned} & 10-(5-2) \ & =10-3 \ & =7 \end{aligned}or
\begin{aligned} & 5-10-2 \ & =-5-2 \ & =-7 \end{aligned}1. Which of the following equations shows how to solve 4 \times 4 \times 10 using the associative property?
All the numbers are being multiplied, so the associative property can be used.
Change the grouping of the numbers and solve.
\begin{aligned} & 4 \times 4 \times 10 \\ & =4 \times(4 \times 10) \quad \text{ *Group and multiply these numbers first}\\ & =4 \times 40 \\ & =160 \end{aligned}
2. Which of the following equations shows how to solve 53 + 12 + 17 using the commutative property?
The commutative property says that changing the order in the equation does not change the sum.
\begin{aligned} & 53+12+17 \\ & =53+17+12 \;\; \text{ Change the order of 12 and 17} \\ & =70+12 \quad \quad \text{ *Adding 53 and 17 first gives us 70 – a friendly number} \end{aligned}
3. Which of the following equations shows how to solve 6 \times 3 \times 5 using the commutative property to create a friendly number?
The commutative property says that changing the order in the equation does not change the product.
Friendly numbers are numbers that are easy to multiply mentally – like multiples of 10.
\begin{aligned} & 6 \times 3 \times 5\\ & =6 \times 5 \times 3 \quad \text{ *Change the order of 3 and 5} \\ & =30 \times 3 \quad \quad \text{ *Multiplying 6 and 5 first gives us 30 – a friendly number} \end{aligned}
4. Which of the following equations shows 6 \times 7 using the distributive property?
The numbers are being multiplied, so the distributive property can be used.
\begin{aligned} & 6 \times 7 \\ & =6 \times(1+3+3) \quad \quad \quad \quad \quad \text{ *Break 7 up into } 1 + 3 + 3 \\ & =(6 \times 1)+(6 \times 3)+(6 \times 3) \;\; \text{ *Multiply 1, 3, and 3 by 6 } \\ & =6+18+18 \quad \quad \quad \quad \quad \quad \text{ *Add the partial products back together}\\ & =42 \end{aligned}
5. Calculate 7+3 \times 12.
To solve, follow the order of operations by using PEMDAS.
6. Calculate 458+(5 \div 2 \times 4)^3.
To solve, follow the order of operations by using PEMDAS.
Yes, these properties can be applied to any equation, expression or inequality that includes real numbers (which includes fractions, decimals, negative and irrational numbers).
As students are learning the operations, they learn that subtraction is the inverse of addition and division is the inverse of multiplication.
As students work with the operations, they will begin to notice other patterns that are later formalized. These include the addition property of equality, subtraction property of equality, multiplication property of equality, and the division property of equality, where students learn that the same operation can be done to both sides of an equation without jeopardizing equality.
This is because the equal sign can be thought of as a balance, so as long as the same operation is done to both sides of the equation, equivalence is maintained.
As students begin to work with equations with unknown variables, they will learn that these are also algebraic properties that can be used when working with algebraic equations.
For example, students can use the distributive property to simplify linear equations and then use the addition property of equality and the division property of equality to solve for a specific value.
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