[FREE] End of Year Math Assessments (Grade 4 and Grade 5)

The assessments cover a range of topics to assess your students' math progress and help prepare them for state assessments.

Download free

In order to access this I need to be confident with:

Factors and multiples

Multiplying multi digit numbers

Place value

Elementary math Number and quantity Properties of equality

Distributive property

Here you will learn about the distributive property, including what it is, and how to use it to solve problems.

Students will first learn about the distributive property as part of operations and algebraic thinking in 3rd grade.

What is the distributive property?

The distributive property states that multiplying the sum of two or more numbers is the same as multiplying the addends separately.

For example,

When multiplying $2 \times 8,$ you can break $8$ up into $2 + 6.$

The distributive property says that you can multiply the parts separately and then add the products together.

Any way you solve the equivalent expressions, the product is the same.

For most expressions, there is more than one way to use the distributive property.

For example,

When multiplying $2 \times 8,$ you can break $8$ up into $5 + 3.$

The distributive property says that you can multiply the parts separately and then add the products together.

Any way you solve the equivalent expressions, the product is the same.

What is the distributive property?

Common Core State Standards

How does this relate to 3rd grade math?

Grade 3 – Operations and Algebraic Thinking (3.OA.B.5)
Apply properties of operations as strategies to multiply and divide.
Examples: If $6 \times 4 = 24$ is known, then $4 \times 6 = 24$ is also known. (Commutative property of multiplication.)
$3 \times 5 \times 2$ can be found by $3 \times 5 = 15,$ then $15 \times 2 = 30,$ or by $5 \times 2 = 10,$ then $3 \times 10 = 30.$ (Associative property of multiplication.)
Knowing that $8 \times 5 = 40$ and $8 \times 2 = 16,$ one can find $8 \times 7$ as $8 \times (5 + 2) = (8 \times 5) + (8 \times 2) = 40 + 16 = 56.$ (Distributive property.)

How to use the distributive property

In order to use the distributive property:

Identify an equation multiplying two numbers.
Show one of the numbers being multiplied as a sum of numbers.
Multiply each number in the sum.
Add the partial products together to find the final product.

[FREE] End of Year Math Assessments (Grade 4 & Grade 5)

Assess math progress for the end of grade 4 and grade 5 or prepare for state assessments with these mixed topic, multiple choice questions and extended response questions!

DOWNLOAD FREE

[FREE] End of Year Math Assessments (Grade 4 & Grade 5)

Assess math progress for the end of grade 4 and grade 5 or prepare for state assessments with these mixed topic, multiple choice questions and extended response questions!

DOWNLOAD FREE

Distributive property examples

Example 1: distributive property with basic facts

Show how to solve $3 \times 5$ using the distributive property.

Identify an equation multiplying two numbers.

You can use the distributive property with $3 \times 5,$ since it is multiplication.

2Show one of the numbers being multiplied as a sum of numbers.

Either number can be used, but for this example let’s break up $5$ into $4 + 1.$

$3 \times 5=3 \times(4+1)$

3Multiply each number in the sum.

$\begin{aligned} & 3 \times(4+1) \\\\ & =(3 \times 4)+(3 \times 1) \\\\ & =12+3 \end{aligned}$

4Add the partial products together to find the final product.

$12 + 3 = 15$

$3 \times 5=15$ can be solved using the distributive property.

Example 2: distributive property with basic facts

Show how to solve $12 \times 9$ using the distributive property.

Identify an equation multiplying two numbers.

You can use the distributive property with $12 \times 9,$ since it is multiplication.

Show one of the numbers being multiplied as a sum of numbers.

Either number can be used, but for this example let’s break up $9$ into $3 + 3 + 3.$

$12 \times 9=12 \times(3+3+3)$

Multiply each number in the sum.

$\begin{aligned} & 12 \times(3+3+3) \\\\ & =(12 \times 3)+(12 \times 3)+(12 \times 3) \\\\ & =36+36+36 \end{aligned}$

Add the partial products together to find the final product.

$36 + 36 + 36 = 108$

$12 \times 9=108$ can be solved using the distributive property.

Example 3: distributive property with basic facts

Show how to solve $7 \times 6$ using the distributive property.

Identify an equation multiplying two numbers.

You can use the distributive property with $7 \times 6,$ since it is multiplication.

Show one of the numbers being multiplied as a sum of numbers.

Either number can be used, but for this example let’s break up $7$ into $4 + 3.$

$7 \times 6=(4+3) \times 6$

Multiply each number in the sum.

$\begin{aligned} & (4+3) \times 6 \\\\ & =(4 \times 6)+(3 \times 6) \\\\ & =24+18 \end{aligned}$

Add the partial products together to find the final product.

$24 + 18 = 42$

$7 \times 6=42$ can be solved using the distributive property.

Example 4: distributive property with basic facts

Show how to solve $4 \times 11$ using the distributive property.

Identify an equation multiplying two numbers.

You can use the distributive property with $4 \times 11,$ since it is multiplication.

Show one of the numbers being multiplied as a sum of numbers.

Either number can be used, but for this example let’s break up $11$ into $10 + 1.$

$4 \times 11=4 \times(10+1)$

Multiply each number in the sum.

$\begin{aligned} & 4 \times(10+1) \\\\ & =(4 \times 10)+(4 \times 1) \\\\ & =40+4 \end{aligned}$

Add the partial products together to find the final product.

$40 + 4 = 44$

$4 \times 11=44$ can be solved using the distributive property.

Example 5: distributive property with basic facts

Show how to solve $8 \times 5$ using the distributive property.

Identify an equation multiplying two numbers.

You can use the distributive property with $8 \times 5,$ since it is multiplication.

Show one of the numbers being multiplied as a sum of numbers.

Either number can be used, but for this example let’s break up $8$ into $2 + 6.$

$8 \times 5=(2+6) \times 5$

Multiply each number in the sum.

$\begin{aligned} & (2+6) \times 5 \\\\ & =(2 \times 5)+(6 \times 5) \\\\ & =10+30 \end{aligned}$

Add the partial products together to find the final product.

$10 + 30 = 40$

$8 \times 5=40$ can be solved using the distributive property.

Example 6: distributive property with basic facts

Show how to solve $3 \times 12$ using the distributive property.

Identify an equation multiplying two numbers.

You can use the distributive property with $3 \times 12,$ since it is multiplication.

Show one of the numbers being multiplied as a sum of numbers.

Either number can be used, but for this example let’s break up $12$ into $1 + 1 + 10.$

$3 \times 12=3 \times(1+1+10)$

Multiply each number in the sum.

$\begin{aligned} & 3 \times(1+1+10) \\\\ & =(3 \times 1)+(3 \times 1)+(3 \times 10) \\\\ & =3+3+30 \end{aligned}$

Add the partial products together to find the final product.

$3 + 3 + 30 = 36$

$3 \times 12=36$ can be solved using the distributive property.

Teaching tips for the distributive property

Intentionally choose practice problems that lend themselves to being solved with the distributive property, as it is not always necessary or useful in all solving situations.

Instead of just giving students the distributive property definition, draw attention to examples of the distributive property as they come up in daily math activities. You may even keep an anchor chart of different examples. Over time, students will start using it and recognizing it on their own and then you can introduce them to the property and its official definition through their own examples.

Include plenty of student discourse around this topic to ensure that students understand that breaking apart a number and then multiplying it in parts does not change the total product. This could include students sharing their thinking or critiquing the thinking of others.

Easy mistakes to make

Thinking there is only one way to use the distributive property to solve
Often, there is more than one way to use the distributive property when solving.
For example,

$\begin{aligned} & 4 \times 5 \hspace{4.65cm} 4 \times 5 \\ & =(2+2) \times 5 \hspace{3.5cm} =(1+3) \times 5 \\ & =(2 \times 5)+(2 \times 5) \hspace{1cm} \text{ OR } \hspace{1cm} =(1 \times 5)+(3 \times 5) \\ & =10+10 \hspace{3.9cm} =5+15 \\ & =20 \hspace{4.63cm} =20 \end{aligned}$

Decomposing with multiplication instead of addition
To use the distributive property, break apart a number being multiplied with addition. Using multiplication can lead to the incorrect answer.
For example,

$\hspace{1cm} \text{ OR } \hspace{1.1cm}$

Not decomposing by place value
To use the distributive property, break apart a number being multiplied in a way that keeps the overall value the same. This includes preserving place value. Otherwise the products will not be equivalent.
For example,

$\hspace{1cm} \text{ OR } \hspace{1.1cm}$

Practice distributive property questions

(10 \times 2) \times 6=(10 \times 2)+(10 \times 6)

12 \times(2+4)=12 \times 2+2 \times 4

(1 \times 2)+6=(1 \times 6)+(1 \times 2)

12 \times(3+3)=(12 \times 3)+(12 \times 3)

The numbers are being multiplied, so the distributive property can be used.

\begin{aligned} & 12 \times 6 \\\\ & =12 \times(3+3) \hspace{1.2cm} \text{ *Break 6 up into 3 + 3}\\\\ & =(12 \times 3)+(12 \times 3) \hspace{0.3cm} \text{ *Multiply each 3 by 12} \\\\ & =36+36 \hspace{1.8cm} \text{ *Add the partial products back together} \\\\ & =72 \end{aligned}

(1+7) \times 9=(1 \times 9)+(7 \times 9)

7 \times(3 \times 3)=(7 \times 3)+(7 \times 3)

(4+3) \times 9=(4 \times 9)+(3 \times 9)

7 \times(6+3)=7 \times 6+6 \times 3

The numbers are being multiplied, so the distributive property can be used.

\begin{aligned} & 7 \times 9 \\\\ & =(4+3) \times 9 \hspace{1.2cm} \text{ *Break 7 up into 4 + 3}\\\\ & =(4 \times 9)+(3 \times 9) \hspace{0.4cm} \text{ *Multiply both 4 and 3 by 9} \\\\ & =36+27 \hspace{1.6cm} \text{ *Add the partial products back together} \\\\ & =63 \end{aligned}

(1+10) \times 8=(1 \times 8)+(10 \times 8)

(1+1) \times 8=(1 \times 8)+(1 \times 8)

11 \times(4 \times 2)=(11 \times 4)+(11 \times 2)

11 \times(4+4)=(11 \times 4)+4

The numbers are being multiplied, so the distributive property can be used.

\begin{aligned} & 11 \times 8 \\\\ & =(1+10) \times 8 \hspace{1.1cm} \text{ *Break 11 up into 1 + 10}\\\\ & =(1 \times 8)+(10 \times 8) \hspace{0.3cm} \text{ *Multiply both 1 and 10 by 8} \\\\ & =8+80 \hspace{1.8cm} \text{ *Add the partial products back together} \\\\ & =88 \end{aligned}

(2+1) \times 7=(2 \times 7)+(2 \times 1)

3 \times(2+2+3)=(3 \times 2)+(3 \times 2)

3 \times(1+3+3)=(3 \times 1)+(3 \times 3)+(3 \times 3)

(3 \times 1) \times 7=3 \times(1 \times 7)

The numbers are being multiplied, so the distributive property can be used.

\begin{aligned} & 3 \times 7 \\\\ & =3 \times(1+3+3) \hspace{1.8cm} \text{ *Break 7 up into 1 + 3 + 3}\\\\ & =(3 \times 1)+(3 \times 3)+(3 \times 3) \hspace{0.3cm} \text{ *Multiply 1, 3 and 3 by 3} \\\\ & =3+9+9 \hspace{2.6cm} \text{ *Add the partial products back together} \\\\ & =21 \end{aligned}

(5+5) \times 5=(5 \times 5)+(5 \times 5)

(2 \times 5) \times 5=(2 \times 5)+(2 \times 5)

10 \times(2+3)=(10 \times 2)+(10 \times 3)

10 \times(1+4)=(10 \times 4)+(10 \times 1)

\begin{aligned} & 10 \times 5 \\\\ & =(2 \times 5) \times 5 \hspace{1.2cm} \text{ *This breaks up 10, but not into a sum} \\\\ & =(2 \times 5)+(2 \times 5) \hspace{0.4cm} \text{ *This is equal to } (2 + 2) \times 5, \text{ but not } (2 \times 5) \times 5 \end{aligned}

This strategy is NOT a way to solve with the distributive property.

All the other equations break $10$ or $5$ up into a sum and add the products of the parts, using the distributive property correctly:

Distributive Property image 11

(4+5) \times 8=(4 \times 8)+(5 \times 8)

9 \times(1+7)=(9 \times 1)+(9 \times 7)

9 \times(3+5)=(9 \times 3)+(9 \times 5)

(2+6) \times 8=(2 \times 8)+(6 \times 8)

\begin{aligned} & 9 \times 8 \\\\ & =(2+6) \times 8 \hspace{1.2cm} \text{ *This breaks up 8 instead of 9} \\\\ & =(2 \times 8)+(6 \times 8) \hspace{0.4cm} \text{ *This is equal to } (2 + 6) \times 8, \text{ or } 8 \times 8 \text{ not } 9 \times 8 \end{aligned}

This strategy is NOT a way to solve $9 \times 8$ with the distributive property.

All the other equations break $9$ or $8$ up into a sum and add the products of the parts, using the distributive property correctly:

Distributive Property image 12

Distributive property FAQs

Does the distributive property work with other groupings of numbers besides whole numbers?

Yes, the distributive property can be used with integers (including negative numbers) and rational numbers (including fractions and decimals), as long as the numbers are all being multiplied. In middle and high school, students will learn how to use the distributive property with any real number and/or algebraic expression.

Is the distributive property the same as the associative property?

No, even though the associative property also uses parentheses, they are different properties. The associative property says you can change the grouping of numbers when adding or multiplying and the sum or product will be the same. This is different from the distributive property.

Can you use the distributive property with subtraction?

Yes, this is called the distributive property of multiplication over subtraction.

What is the distributive law of multiplication?

This is a general term and means the same as the distributive property.

Do you have to use parentheses when writing equations for the distributive property?

No, because of the order of operations (or PEMDAS), the products will be found first and then added together. However, it is good practice to group each partial product with parentheses.

The next lessons are

Addition and subtraction
Multiplication and division
Types of numbers

Still stuck?

At Third Space Learning, we specialize in helping teachers and school leaders to provide personalized math support for more of their students through high-quality, online one-on-one math tutoring delivered by subject experts.

Each week, our tutors support thousands of students who are at risk of not meeting their grade-level expectations, and help accelerate their progress and boost their confidence.