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Fractions Decimals Simplifying fractions Converting fractions decimals and percentagesHere you will learn about theoretical probability, including probability scales, mutually exclusive events and the probability of something not happening.
Students will first learn about theoretical probability as part of statistics and probability in 7 th grade and continue to learn about theoretical probability in high school.
Theoretical probability uses mathematics rather than an experiment to determine the chance of something happening.
To do this, we need to think about two things – the number of times an event may occur and the total number of outcomes available.
\text{Theoretical probability } =\cfrac{\text{frequency of the event occurring}}{\text{total frequency of possible outcomes}}
Some events are known as mutually exclusive. This means they cannot happen at the same time. For example, a fair dice cannot land on a 3 and a 4 at the same time and so the probability of this event would be 0 (impossible).
You can, however, find the probability of rolling a 3 or a 4. As these events are mutually exclusive we can add the probabilities together. Here, it is stated that the dice is fair and so the probability of landing on each number is the same.
To calculate the theoretical probability, create a probability model with all the possible outcomes.
The probability of the event occurring can be written as a fraction, decimal or percentage. Use the model to write the fraction.
This is written as P(3)=\cfrac{1}{6} which reads βThe probability of rolling a 3 is \cfrac{1}{6}. β
Since P(3)=\cfrac{1}{6} and P(4)=\cfrac{1}{6}, this means that P(3 or 4)=\cfrac{1}{6}+\cfrac{1}{6}=\cfrac{2}{6}=\cfrac{1}{3}.
Consider this value on a probability scale.
The probability scale goes from 0 (impossible) to 1 (certain). This means the probability of something NOT happening must be 1 subtract the probability of it happening.
P( not A)=1-P(A).
For example, find the probability of NOT rolling a 3 or a 4.
P( not 3 or 4)=1-\left(\cfrac{1}{6}+\cfrac{1}{6}\right)=\cfrac{4}{6}=\cfrac{2}{3}.
In probability theory, the difference between theoretical and experimental probability is that theoretical probability is based solely on math, whereas experimental probability is based on the outcomes of an experiment and so there is no known probability until the experiment has taken place.
Use this quiz to check your grade 7 to 12 studentsβ understanding of probability. 15+ questions with answers covering a range of 7th to 12th grade probability topics to identify areas of strength and support!
DOWNLOAD FREEUse this quiz to check your grade 7 to 12 studentsβ understanding of probability. 15+ questions with answers covering a range of 7th to 12th grade probability topics to identify areas of strength and support!
DOWNLOAD FREEHow does this relate to 7 th grade math?
In order to calculate the theoretical probability of an event:
Lettered cards spell out the word mathematics.
The cards are mixed up and one is selected at random.
What is the probability that the card selected is a vowel? Display it on the probability scale.
There are 11 cards altogether in the word MATHEMATICS.
2Determine the frequency of the event occurring.
The set of vowels are: A, E, I, O, and U. There are 4 vowel cards in the word MATHEMATICS.
3Substitute these values into the formula. Write your answer as a fraction, decimal or percentage.
The frequency of the event occurring is 4 and the total frequency of possible outcomes is 11, the theoretical probability is
P( Vowel)=\cfrac{4}{11}
A fair six-sided die is rolled. What is the probability of it landing on a prime number? Display it on the probability scale.
Determine all possible outcomes.
As the die is six-sided, the total number of outcomes from a single roll is 6.
Determine the frequency of the event occurring.
The prime numbers on a fair six-sided die are 2, 3, and 5. Therefore the frequency of prime numbers is 3.
Substitute these values into the formula. Write your answer as a fraction, decimal or percentage.
P( Prime number)=\cfrac{3}{6}=\cfrac{1}{2} \ (=0.5)
A bag contains 6 yellow counters, 3 blue counters and 1 white counter. A counter is selected from the bag at random. Find the probability that the counter is not yellow.
Determine all possible outcomes.
The total number of counters in the bag is 6+3+1=10.
Determine the frequency of the event occurring.
The frequency of yellow counters is 6.
Substitute these values into the formula. Write your answer as a fraction, decimal or percentage.
P( Yellow)=\cfrac{6}{10}=0.6
Since the events are mutually exclusive, the probabilities will all add to 1. The probability of not picking a yellow counter is found by subtracting this answer from 1.
Using decimals,
P( Not Yellow)=1-0.6=0.4.
Using fractions,
P( Not Yellow)=1-\cfrac{6}{10}=\cfrac{4}{10}.
A bag contains 6 yellow counters, 3 blue counters and 1 white counter. A counter is selected from the bag at random. Find the probability of the counter being yellow or white.
Determine all possible outcomes.
The total number of counters in the bag is 10.
Determine the frequency of the event occurring.
The frequency of yellow counters is 6 and the frequency of white counters is 1. This means that the frequency of yellow or white counters is 6+1=7.
Substitute these values into the formula. Write your answer as a fraction, decimal or percentage.
P( Yellow or White)=\cfrac{7}{10}=0.7
Ariel is playing a game and rolls two dice. What is the probability that Ariel rolls two fours?
Determine all possible outcomes.
Use a list to show all possible outcomes.
\begin{aligned} 1β1 \quad \;\; 2β1 \quad \;\; 3β1 \quad \;\; 4β1 \quad \;\; 5β1 \quad \;\; 6β1 \\ 1β2 \quad \;\; 2β2 \quad \;\; 3β2 \quad \;\; 4β2 \quad \;\; 5β2 \quad \;\; 6β2 \\ 1β3 \quad \;\; 2β3 \quad \;\; 3β3 \quad \;\; 4β3 \quad \;\; 5β3 \quad \;\; 6β3 \\ 1β4 \quad \;\; 2β4 \quad \;\; 3β4 \quad \;\; 4β4 \quad \;\; 5β4 \quad \;\; 6β4 \\ 1β5 \quad \;\; 2β5 \quad \;\; 3β5 \quad \;\; 4β5 \quad \;\; 5β5 \quad \;\; 6β5 \\ 1β6 \quad \;\; 2β6 \quad \;\; 3β6 \quad \;\; 4β6 \quad \;\; 5β6 \quad \;\; 6β6 \end{aligned}
There are 36 possible outcomes.
Determine the frequency of the event occurring.
4\text{β}4 only appears once in the list of all possible outcomes. The frequency of two fours is therefore 1.
Substitute these values into the formula. Write your answer as a fraction, decimal or percentage.
P( two fours)=\cfrac{1}{36} \, (=0.02\bar{7})
A coin is flipped three times. What is the probability that the coin lands on tails twice and heads once?
Determine all possible outcomes.
Use a tree diagram to show all possible outcomes.
There are 8 possible outcomes: TTT, TTH, THT, THH, HTT, HTH, HHT, HHH.
Determine the frequency of the event occurring.
In the possible outcomes there are Tails-Tails-Heads, Tails-Heads-Tails and Heads-Tails-Tails. The frequency of two tails and one heads is 3.
Substitute these values into the formula. Write your answer as a fraction, decimal or percentage.
P(2 tails, 1 head)=\cfrac{3}{8}.
1. Lettered cards spell out the word FRACTION.
The cards are mixed up and placed into a bag, where one is selected at random. Determine the probability of drawing a vowel.
There are 3 vowels and 8 total lettered cards in total and so P( Vowel)=\cfrac{3}{8}.
2. Cards numbered 1 to 10 are mixed up and one is selected at random.
What is the theoretical probability that the card selected is a square number?
There are 3 square numbers (1, 4, 9) and 10 numbered cards in total and so P( square number)=\cfrac{3}{10}.
3. A bag contains 3 green counters, 5 white counters and 4 red counters. A counter is selected at random. Calculate the probability of the counter being green or red.
There are 7 green or red counters and 12 counters in total and so
P( green or red)=\cfrac{7}{12}.
4. A bag contains 3 green counters, 5 white counters and 4 red counters. A counter is selected at random. Calculate the probability of the counter that is selected is not green. Display your answer on a probability scale.
There are 3 green counters and 12 counters in total.
1-\cfrac{3}{12}=1-\cfrac{1}{4}=\cfrac{3}{4}
5. A six-sided spinner shows only the numbers 1, 2, 3 and 4.
There is an equal chance of it landing on a 2 or a 4, but more of a chance of it landing on an odd number than an even number.
Select the spinner that satisfies those probability statements.
There must be the same number of 2 s and 4 s. There must be more odd numbers than even numbers and so the remaining values must all contain either a 1 or a 3.
6. A bag contains 3 red counters and 2 blue counters. Another bag has 2 quarters and 1 penny. What is the probability of picking a red counter from the first bag and a quarter from the second bag?
Letβs look at all the possible outcomes in a list.
\begin{aligned}&R1βQ1 \quad \;\; R1βQ2 \quad \;\; R1βP \\ &R2βQ1 \quad \;\; R2βQ2 \quad \;\; R2βP \\ &R3βQ1 \quad \;\; R3βQ2 \quad \;\; R3βP \\ &B1βQ1 \quad \;\; B1βQ2 \quad \;\; B1βP \\ &B2βQ1 \quad \;\; B2βQ2 \quad \;\; B2βP \end{aligned}
Notice, the list indicates that there are 3 different reds, 2 different blues and 2 different quarters.
This makes it clear that none of the counters or quarters are being used more than once; just showing that there are multiple.
For example, R1 is a different counter from R2. The penny (P) does not need this label, because there is only one.
There are 6 possible outcomes of a red counter (R) and a quarter (Q).
There are 15 total possible outcomes, so the probability is \cfrac{6}{15}.
There are four: theoretical probability, empirical probability, axiom probability and subjective probability.
It is the probability result from a preformed experiment. It can be compared to the theoretical probability.
The probability that something will occur, given a previous event, or condition, has already occurred.
See also: Conditional probability
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