High Impact Tutoring Built By Math Experts
Personalized standards-aligned one-on-one math tutoring for schools and districts
In order to access this I need to be confident with:
Multiplication Factors and multiples Greatest common factor Least common multiple Probability Independent events Mutually exclusive eventsHere you will learn about the fundamental counting principle, including selecting from one set and selecting from multiple sets.
Students will first learn about the fundamental counting principle as part of statistics and probability in 7 th grade.
The fundamental counting principle is a method for finding the total number of ways of selecting items from a set or sets.
The fundamental counting principle (also called the fundamental principle of counting) states that if one event can occur in m ways and a second independent event can occur in n ways, then the total number of ways both events can occur in sequence is m \times n.
In other words, if there are multiple independent events, the total number of possible outcomes is found by multiplying the number of ways each event can occur.
For example,
A teacher needs to select one boy and one girl from his class to show a visitor around the school. There are 4 boys and 3 girls in his class.
The number of different pairs of children can be calculated by thinking about how many different options there are for each boy.
Each boy could be paired with 3 girls.
As there are 4 boys, this means there will be 4 groups of 3 pairings.
4\times 3=12, so there are 12 different pairs (permutations) the teacher could select.
If the boys are called A, \, B, \, C and D and the girls are called X, \, Y, \, Z the sample space would be:
If the teacher decided to just select two girls from his class, you would need to think more carefully.
There would be 3 options for the first choice, and then 2 options for the second choice. However, calculating 3\times 2 would give double the amount of options as it would include each pair of girls twice, and the order of selecting the girls doesnβt matter.
So there are \cfrac{3\times 2}{2}=3 pairs of girls to select.
The possible combinations would be: XY \, ( same as YX), \, XZ \, ( same as ZX) and YZ \, ( same as ZY).
How does this relate to 7 th grade math?
Use this quiz to check your grade 7 to 12 studentsβ understanding of finding probability. 15+ questions with answers covering a range of 7th to 12th grade probability topics to identify areas of strength and support!
DOWNLOAD FREEUse this quiz to check your grade 7 to 12 studentsβ understanding of finding probability. 15+ questions with answers covering a range of 7th to 12th grade probability topics to identify areas of strength and support!
DOWNLOAD FREEIn order to use the fundamental counting principle:
Arthur has been told he can select a bag of chips and a drink as part of a meal deal.
There are 7 different flavors of chips and 11 different drinks. How many possible outcomes could Arthur select?
There are two sets to select from, chips and drinks.
2Identify the number of items to select from each set.
There are 7 different chip flavors and 11 different drinks.
3Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\bf{2}} if order doesnβt matter.
7\times 11=77There are 77 total choices that Arthur could select.
Bella is clothes shopping and can select a T-shirt, a pair of joggers, and a hoodie as part of a mix-and-match offer.
There are 4 different colors of T-shirts, 5 colors for the joggers, and 3 colors for the hoodie.
What is the number of possibilities Bella could select?
Identify the number of sets to be selected from.
There are three sets to select from.
Identify the number of items to select from each set.
The number of items from the three sets are 4, \, 5, and 3.
Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\bf{2}} if order doesnβt matter.
Using the counting principle, you multiply
4\times 5\times 3=60
There are 60 different possibilities that Bella could select.
A teacher is trying to pick two students to participate in a quiz. They must also decide which student will go first and which will go second in a round of the quiz. If there are 24 students to choose from, how many different options does the teacher have?
Identify the number of sets to be selected from.
There is one set to select from.
Identify the number of items to select from each set.
There are 24 items in the set.
Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\bf{2}} if order doesnβt matter.
Order matters because the teacher needs to select who will go first and who will go second.
24\times 23=552
There are 552 different options that the teacher could select.
15 teams in a league must play each other once. How many games in total will be played?
Identify the number of sets to be selected from.
There is one set to select from.
Identify the number of items to select from each set.
There are 15 items in the set.
Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\bf{2}} if order doesnβt matter.
Order doesnβt matter because the teams must only play each other once.
\cfrac{15\times 14}{2}=105
There will be 105 games played in total.
A teacher must choose a Head Boy and Head Girl along with a Deputy Head Boy and a Deputy Head Girl. There are 8 boys and 10 girls to select from. How many different combinations are possible?
Identify the number of sets to be selected from.
There are two sets to select from.
Identify the number of items to select from each set.
There are 8 items in the boy set and 10 in the girl set.
Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\bf{2}} if order doesnβt matter.
Order matters because there are different positions to fill.
If there are n items in one set and m items in the other set, you must calculate n\times \left( n-1 \right)\times m\times \left( m-1 \right).
8\times 7\times 10\times 9=5040
There are 5040 different combinations.
1. There are 7 starters and 12 main courses to choose from at a restaurant. How many possible ways are there of choosing a starter and main course?
For each 7 starters there are 12 possible main course choices, so calculate 7\times 12=84.
2. There are 6 starters, 8 main courses, and 4 desserts to choose from at a restaurant. How many different ways are there of choosing a starter, main course, and dessert?
For each 6 starters there are 8 possible main course choices and then 4 dessert choices, so calculate 6\times 8\times 4=192.
3. A teacher must choose two children from her class to show a visitor around the school. There are 22 children in her class. How many options does the teacher have to choose from?
Order doesnβt matter so calculate 22\times 21=462
and then half this answer
462\div 2=231.
4. A hockey league has 10 teams. Each team must play each other twice, home and away. How many games will be played in total?
Order matters so calculate 10\times 9=90.
5. A teacher must choose a Head Boy and Head Girl along with a Deputy Head Boy and a Deputy Head Girl. There are 6 boys and 7 girls to select from. How many different combinations are possible?
There are 6 choices for head boy and 7 for head girl.
Then there are 5 choices for deputy head boy and 6 for deputy head girl.
6\times 7\times 5\times 6=1260
6. A meal deal consists of one drink and one sandwich. There are 9 drinks and x sandwiches to choose from. Which of the following can not be the number of ways to choose a meal deal?
The number of ways would be 9\times x, therefore it must be a multiple of 9.
The fundamental counting principle is a basic rule in combinatorics that states if there are multiple independent events, the total number of possible outcomes is found by multiplying the number of ways each event can occur.
The fundamental counting principle is also known by several other names, including the fundamental counting rule, the multiplication principle or multiplication rule of counting, the counting rule, the rule of product, the product principle, the basic counting principle.
The fundamental counting principle is used in real life to calculate the total number of possible outcomes in multi-step processes, such as creating secure passwords, determining travel routes, organizing event seating arrangements, and designing unique license plates. It helps simplify complex choices by breaking down each independent decision point.
At Third Space Learning, we specialize in helping teachers and school leaders to provide personalized math support for more of their students through high-quality, online one-on-one math tutoring delivered by subject experts.
Each week, our tutors support thousands of students who are at risk of not meeting their grade-level expectations, and help accelerate their progress and boost their confidence.
Find out how we can help your students achieve success with our math tutoring programs.
Prepare for math tests in your state with these 3rd Grade to 8th Grade practice assessments for Common Core and state equivalents.
Get your 6 multiple choice practice tests with detailed answers to support test prep, created by US math teachers for US math teachers!