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Probability scale Tree diagram probability Venn diagramHere you will learn about compound probability for both independent and dependent variables and also how to use sample space diagrams and Venn diagrams for compound probabilities.
Students will first learn about compound probability as part of statistics and probability in 7 th grade and continue to learn about compound probability in high school.
Compound probability is how likely two or more events are to occur at the same time or in succession. To calculate the likelihood of a certain combination of outcomes, you can use the fundamental counting principle or represent the sample space with a diagram.
The fundamental counting principle says that if one event has m outcomes and a second independent event has n outcomes, then the total number of combined outcomes is m \times n.
For example,
A six-sided die is rolled and the suit of a card randomly chosen from a deck of cards is noted.
The number of different outcomes can be calculated by thinking about how many different options there are for each suit of a card.
Each suit of a card could be paired with 6 different numbers.
Since there are 4 suits, this means there will be 4 groups of 6 pairings.
4\times 6=24, so there are 24 different combinations of the numbers 1β6 and the 4 different suits of a card.
Step-by-step guide: Fundamental counting principle
Now letβs look at the same example, but in a sample space diagram.
Each row represents a different number rolled on the die. Each column represents a different suit of a card. There are 24 different outcomes for these combined events.
The probability of rolling a two and drawing a heart from the deck is \cfrac{1}{24} because this is one combination out of twenty-four possible combinations.
Step-by-step guide: Sample Space
For an overview of the rules for calculating compound probabilities, see also: How to calculate probability.
Use this quiz to check your grade 7 to 12 studentsβ understanding of probability. 15+ questions with answers covering a range of 7th to 12th grade probability topics to identify areas of strength and support!
DOWNLOAD FREEUse this quiz to check your grade 7 to 12 studentsβ understanding of probability. 15+ questions with answers covering a range of 7th to 12th grade probability topics to identify areas of strength and support!
DOWNLOAD FREEHow does this relate to 7 th grade math?
In order to calculate the total possible outcomes of compound events:
Lily can choose a sandwich and a dessert as part of her lunch combo. There are 5 types of sandwiches and 8 different desserts. How many possible combinations can Lily select?
There are two sets to select from, sandwiches and desserts.
2Identify the number of items to select from each set.
There are 5 types of sandwiches and 8 different desserts.
3Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\textbf{2}} if order doesnβt matter.
Using the counting principle, you multiply
5 \times 8=40There are 40 total combinations that Lily can select.
Tyrese is shopping for clothes and can pick a T-shirt, a pair of sweatpants, and a hoodie as part of a mix-and-match deal. There are 5 different T-shirt colors, 6 sweatpants colors, and 2 hoodie colors. How many possible combinations can Tyrese select?
Identify the number of sets to be selected from.
There are three sets to select from.
Identify the number of items to select from each set.
The number of items from the three sets are 5, \, 6 and 2.
Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\textbf{2}} if order doesnβt matter.
Using the counting principle, you multiply
5 \times 6 \times 2=60
There are 60 different possibilities that Tyrese could select.
A manager is selecting two employees to present at a company meeting, deciding who will present first and who will go second. If there are 15 employees to choose from, how many different ways can the manager make this selection?
Identify the number of sets to be selected from.
There is one set to select from.
Identify the number of items to select from each set.
There are 15 items in the set.
Multiply the number of items in each set. If selecting two items from a set, calculate \textbf{n}\times \left( \textbf{n}-\bf{1} \right) or \cfrac{\textbf{n}\times \left( \textbf{n}-\bf{1} \right)}{\textbf{2}} if order doesnβt matter.
Order matters because the manager needs to select who will go first and who will go second.
15 \times 14=210
There are 210 different combinations that the manager could select.
In order to find a probability using a sample space diagram:
A fair coin is flipped and the spinner is spun.
Write a list of all possible combinations of outcomes and find the probability of getting heads and spinning yellow.
Use information provided to decide whether to write a list or create a table to find all possible outcomes.
The coin has two outcomes: H and T, the spinner has 3 outcomes: yellow (Y), red (R) and green (G). You can write them as pairs, for example, (H, \, Y) for a flip of heads and a spin of yellow.
Systematically write the list or fill in the table by either listing outcomes or performing operations with values.
Start by listing all the head (H) outcomes in order, then the tails (T), to be sure that none get missed.
(H, \, Y), \, (H, \, R), \, (H, \, G), \, (T, \, Y), \, (T, \, R), \, (T, \, G).
Use the information from the list or table to find any probabilities required.
There is one possible outcome that has heads (H) and yellow (Y).
\textbf{(H, \, Y )}, \, (H, \, R), \, (H, \, G), \, (T, \, Y), \, (T, \, R), \, (T, \, G).
The probability is the ratio of the desired subset (heads and yellow) over the total possible outcomes.
P(\text { heads and yellow })=\cfrac{1}{6}.
Darshan will randomly be placed into 1 art class and 1 foreign language class. The options for art classes are: painting, theater, chorus and band. The options for foreign language classes are: French, Mandarin and Spanish.
Write a list of all possible combinations of outcomes and find the probability of Darshan being placed into chorus and French.
Use information provided to decide whether to write a list or create a table to find all possible outcomes.
There are 4 possible outcomes for the art class and 3 possible outcomes for the foreign language class.
Systematically write the list or fill in the table by either listing outcomes or performing operations with values.
Start by listing all the art classes. Then from each art class, create 3 branches for the foreign language classes.
Use the information from the list or table to find any probabilities required.
There is one possible outcome that is chorus and French.
The probability is the ratio of the desired subset (chorus and French) over the total possible outcomes.
\mathrm{P}(\text { chorus and French })=\cfrac{1}{12}.
The spinner is spun twice.
Write a list of all possible combinations of outcomes and find the probability of the sum being less than 4.
Use information provided to decide whether to write a list or create a table to find all possible outcomes.
Each spin has 5 outcomes, all equally likely. You can use a table to show all combinations of the spinners.
Systematically write the list or fill in the table by either listing outcomes or performing operations with values.
Use the information from the list or table to find any probabilities required.
There are three possible outcomes with a sum less than 4.
The probability is the ratio of the desired subset (sum less than 4 ) over the total possible outcomes.
P(\text { sum less than } 4)=\cfrac{3}{25}.
1. There are 5 appetizers and 11 main courses to choose from at a restaurant. How many possible ways are there of choosing an appetizer and main course?
For each 5 appetizers there are 11 possible main course choices, so calculate 5\times 11=55.
2. A baseball league has 9 teams. Each team must play each other twice, home and away. How many games will be played in total?
Order matters, because Team A vs B is different from Team B vs A.
Team A vs B is played at Team Aβs field, so it is home for Team A.
Team B vs A is played at Team Bβs field, so it is home for Team B.
Since order matters, follow the rule n \times(n-1).
Calculate 9 \times 8=72.
3. A teacher is trying to pick two students to participate in a quiz. If there are 24 students to choose from, how many different options does the teacher have?
Order doesnβt matter, because choosing Student 1 and Student 2 or Student 2 and Student 1 is the same outcome.
Since order doesnβt matter, follow the rule \cfrac{n \times(n-1)}{2}.
Calculate \cfrac{24 \times 23}{2}=276.
4. The sample space diagram shows the possible outcomes when a six-sided fair dice is rolled and a marble is chosen randomly.
Use the sample space diagram to find the probability of rolling an even number and choosing a pink marble.
There are 24 total outcomes and there are 3 that have an even number and a pink marble.
\cfrac{3}{24}=\cfrac{1}{8}
5. Three fair coins are flipped together. Each coin has either a head or a tail. Find the probability of getting all heads.
Below is the sample space of three coins flipped:
There is 1 outcome that is all heads, out of 8 outcomes in total.
P(\text { flipping heads three times })=\cfrac{1}{8}
6. Two bags each contain 3 numbered counters. Bag A contains the numbers 2, \, 7 and 9. Bag B contains the numbers 1, \, 3 and 5.
A counter from each bag is selected at random and their values multiplied together. Find the probability of getting a result that is a multiple of 7.
Below is the sample space of choosing a numbered counter from each bag and finding their product:
There are 3 outcomes that are multiples of 7, out of 9 outcomes in total.
\cfrac{3}{9}=\cfrac{1}{3}
It can be represented in fraction, decimal or percentage form.
It is the probability of a single event.
They are events that can happen at the same time. For example, when rolling a die, the outcomes of rolling an odd number or a 3 are mutually inclusive, because they can both happen.
They are events that cannot happen at the same time. For example, when rolling a die, the outcomes of rolling an odd number or an even number are mutually exclusive, because they cannot both happen.
See also: Mutually exclusive events
The probability that event B will happen, given that event A has already happened. In other words, the chance of B happening, if A happens first.
See also: Conditional probability
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