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Expanding expressions Algebraic expressions Square root Factoring out theHere you will learn about rearranging equations, including how to solve equations for a particular variable as well as change the subject of formulas.
Students first learn how to rearrange equations in 8 th grade math when they learn how to put linear equations in slope intercept form, y=mx+b. They expand this knowledge as they progress through Algebra I and Algebra II.
Rearranging equations means to solve an equation for a particular variable or change the subject of the equation to write it in a different way.
The strategies used to rearrange an equation are the same as when solving an equation for an unknown variable, which means using inverse operations (in the opposite order of the order of operations) to change the subject of the formula.
Letβs look at a side-by-side comparison of solving an equation for the unknown variable and rearranging an equation for a particular variable (changing the subject).
Remember, when solving any equation, be sure to do the same exact thing to both sides of the equal sign.
Step-by-step guide: Solving equations
How does this apply to high school math?
Use this worksheet to check your high school studentsβ understanding of rearranging equations. 15 questions with answers to identify areas of strength and support!
DOWNLOAD FREEUse this worksheet to check your high school studentsβ understanding of rearranging equations. 15 questions with answers to identify areas of strength and support!
DOWNLOAD FREEIn order to rearrange equations:
Solve the equation for y.
5x+5y=10In this case, solve the equation for y.
2Use inverse operations and/or the distributive property to isolate the variable.
First, subtract 5x from both sides of the equation because subtraction is the inverse operation to addition.
Then, divide both sides of the equation by 5 because division is the inverse operation of multiplication. Remember to divide every term by 5 .
3State the solution and simplify if possible.
y=2-xRearrange the equation for x.
p=2(x-3)Identify the variable you need to isolate.
In this case, solve for x.
Use inverse operations and/or the distributive property to isolate the variable.
Use the same solving strategies as you would when solving a regular equation for an unknown. In this case, first distribute the 2 to the parenthesis.
p=2\times{x}-2\times{3}
p=2x-6
Then add 6 to both sides of the equation because addition is the inverse operation of subtraction.
Then divide both sides of the equation by 2 , because division is the inverse operation of multiplication.
State the solution and simplify if possible.
Solve the formula for h.
A=bhIdentify the variable you need to isolate.
Change the subject of the formula from A to h.
Use inverse operations and/or the distributive property to isolate the variable.
In this case, to solve the formula for h , divide both sides of the formula by b because division is the inverse operation of multiplication.
State the solution and simplify if possible.
By solving for h , the subject of the formula changed from A to h.
Solve the equation for x.
y=x^{2}-4Identify the variable you need to isolate.
In this case, solve for x.
Use inverse operations and/or the distributive property to isolate the variable.
To solve this equation for x, first, add 4 to both sides because addition is the inverse operation of subtraction.
Then, take the square root of both sides because square root is the inverse operation of squaring (square root undoes squaring).
*Note: Remember, the square root has both a positive and negative root
State the solution and simplify if possible.
The solutions are x=\pm\sqrt{y+4}.
Solve the equation for x.
y=\sqrt{3x}+nIdentify the variable you need to isolate.
In this case, solve the equation for x.
Use inverse operations and/or the distributive property to isolate the variable.
To solve the equation for x, first subtract n from both sides of the equation.
Next, square both sides of the equation.
Then, divide both sides of the equation by 3 .
State the solution and simplify if possible.
You can leave the answer this way or distribute the binomial, (y-n)^2 to get y^2-2yn+n^2.
So the solution can be written as:
x=\cfrac{y^{2}-2yn+n^{2}}{3}
In order to rearrange equations with more than 1 of the same variable:
Rearrange \cfrac{a}{3}=\cfrac{2-7x}{x-5} to make x the subject.
Identify the variables you need to isolate.
Solve the equation for x. Notice how there are two terms with the variable x.
Use inverse operations to isolate the variables.
To solve the equation for x, first multiply both sides of the equation by 3 to remove the denominator of the fraction from the left side of the equals sign. Remember to distribute the 3 to the numerator.
Next, multiply both sides of the equation by the binomial (x-5) to remove the denominator on the right hand side of the equals sign. Remember to distribute a.
Next, rearrange the variables so that the x βs are on the same side of the equation. So, add 5a to both sides of the equation because addition is the inverse of subtraction.
Next, add 21x to both sides of the equation because addition is the inverse operation of subtraction.
Apply the strategy of factoring.
In order to write the equation with only one x term, apply the strategy of factoring.
x(a+21)=6+5a
Finally, divide both sides by the binomial (a+21) to isolate x.
State the solution and simplify if possible.
Solve the equation for z.
y=\cfrac{2xz}{z-x}Identify the variables you need to isolate.
Solve the equation for z. Notice how there are two terms with the variable z.
Use inverse operations to isolate the variables.
First, multiply both sides of the equation by the binomial (z-x) and distribute.
Bring all the z terms to one side of the equation and the terms without z βs to the other side.
Add xy to both sides, then subtract 2xz from both sides.
Apply the strategy of factoring.
Use the strategy of factoring to factor out z so that there is only one term with the variable z.
z(y-2x)=xy
Lastly, divide both sides by the binomial (y-2x) to isolate z.
State the solution and simplify if possible.
Step-by-step guide: Factoring GCF
1. Make a the subject of the formula h=3(a+7).
Solve the equation, h=3(a+7) for the variable a by first distributing the 3 into the binomial (a+7) then isolating a.
2. Solve the formula for h.
A=\cfrac{1}{2} \, bh
Solving the formula A=\cfrac{1}{2} \, bh for h means to change the subject from A to h.
3. Make c the subject of the formula g=\sqrt{5 c-r}
Solve the equation for c\text{:}
4. Solve p=b^{2}-9k for b.
Isolate the variable b\text{:}
5. Make d the subject of the formula y=\cfrac{3d+1}{4d}.
Rearrange the equation so that only one term contains the variable d then isolate this on one side of the equals sign:
6. Make e the subject of the formula.
\cfrac{q}{3}=\cfrac{6-2e}{e+1}
Rearrange the equation so that only one term contains the variable e then isolate this on one side of the equals sign:
Yes, you can rearrange any algebraic equation by changing the subject.
Yes, sometimes rearranging quadratic equations, linear equations, and/or any algebraic equation might be helpful when trying to graph them.
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