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Here you will learn about how to simplify radicals including the definition of a radical, the rules of radicals and how to write radicals in their simplest form.

Students first learn how to work with radicals when they learn about square roots and cube roots in 8 th grade and expand the knowledge as they progress through high school math.

**Simplifying radicals** or simplifying radical expressions is when you rewrite a radical in its simplest form by ensuring the number underneath the square root sign (the radicand) has no square numbers as factors. Make the number as small as possible by extracting square factors from underneath the root sign.

The radical sign (also known as square root symbol) is → \sqrt{\;\;\;}.

You can use the three properties of radicals, which can be derived from the laws of exponents (powers) to help you to simplify radicals:

**See also**: Laws of exponents

- Multiplying radicals: \sqrt{m} \times \sqrt{n}=\sqrt{m n}

- Dividing radicals: \sqrt{m} \div \sqrt{n}=\sqrt{\cfrac{m}{n}}=\cfrac{\sqrt{m}}{\sqrt{n}}

In the quotient, \sqrt{m} is in the numerator and \sqrt{n} is in the denominator.

- Squaring radicals: \sqrt{m} \times \sqrt{m}=\sqrt{m^2}=m

For example, let’s simplify \sqrt{20}.

20 is not a perfect square number, so let’s think about possible perfect square factors of 20.

4 is a factor of 20 and a perfect square number.

4 is a perfect square because 2 \times 2 =4.

\sqrt{20} can be written as \sqrt{4 \times 5}.

\sqrt{4 \times 5}=\sqrt{4} \times \sqrt{5} \sqrt{4}=2So, \sqrt{20} is simplified to be 2 \sqrt{5}.

\sqrt{20}=2 \sqrt{5}Let’s simplify a radical algebraic expression.

\sqrt{50 x^3}First, think of the perfect square factors of 50.

25 is a factor of 50 and it is a perfect square number.

Next, look at the exponent. If it is divisible by 2 it is considered a perfect square if not, it is not a perfect square. 3 is the exponent which means it is not a perfect square.

Rewrite x^3 where one factor is a perfect square.

In this case, x^3 can be rewritten as x^2 \times x.

\begin{aligned}&\begin{aligned}& \sqrt{50 x^3}=\sqrt{25 \times 2 \times x^2 \times x} \\\\ & \sqrt{25} \times \sqrt{2} \times \sqrt{x^2} \times \sqrt{x} \\\\ & \sqrt{25}=5\end{aligned}\\\\ &\sqrt{x^2}=x\end{aligned}\sqrt{50 x^3} simplifies to be 5 x \sqrt{2 x}.

\sqrt{50 x^3}=5 x \sqrt{2 x}Teaching how to simplify radicals in your algebra lessons? Want to identify areas of strength and support without making your own questions? Check student understanding across algebra with these 10 quick questions and answers.

DOWNLOAD FREETeaching how to simplify radicals in your algebra lessons? Want to identify areas of strength and support without making your own questions? Check student understanding across algebra with these 10 quick questions and answers.

DOWNLOAD FREEHow does this relate to 8 th grade math and high school math?

**Grade 8 – Expressions and Equations (8.EE.A.2)**Use square root and cube root symbols to represent solutions to equations of the form x^2 = p and x^3 = p, where p is a positive rational number. Evaluate square roots of small perfect squares and cube roots of small perfect cubes. Know that \sqrt{2} is irrational.

**High School Number and Quantity – The Real Number System (HSN-RN.B.3)**

Explain why the sum or product of two rational numbers is rational; that the sum of a rational number and an irrational number is irrational; and that the product of a nonzero rational number and an irrational number is irrational.

In order to simplify a radical:

**Find the largest square number that is a factor of the number under the root.****Rewrite the radical as a product of this square number and another number, then evaluate the root of the square number.****Write the simplified answer.**

Simplify the radical.

\sqrt{8}**Find the largest square number that is a factor of the number under the root.**

Thinking about some of the perfect square numbers.

\begin{aligned} &1 = 1 \times 1 \\ &4 = 2 \times 2 \\ &9 = 3 \times 3 \\ &16 = 4 \times 4 \\ &25 = 5 \times 5 \\ &36 = 6 \times 6\end{aligned}4 is a perfect square number and a factor of 8.

2 \times 4 = 82**Rewrite the radical as a product of this square number and another number, then evaluate the root of the square number.**

\sqrt{2} → This is irrational and cannot be simplified, so leave it as is.

\sqrt{4} → This expression can be simplified. \sqrt{4}=2

3**Write the simplified answer.**

Simplify the radical.

\sqrt{45}**Find the largest square number that is a factor of the number under the root.**

Thinking about some of the perfect square numbers.

\begin{aligned} &1 = 1 \times 1 \\ &4 = 2 \times 2 \\ &9 = 3 \times 3 \\ &16 = 4 \times 4 \\ &25 = 5 \times 5 \\ &36 = 6 \times 6 \end{aligned}

9 is a perfect square number and a factor of 45.

\sqrt{45}=\sqrt{5 \times 9}=\sqrt{5} \times \sqrt{9}

\sqrt{5} → This is irrational and cannot be simplified, so leave it as is.

\sqrt{9} → This expression can be simplified. \sqrt{9}=3

**Write the simplified answer.**

\sqrt{45}=3 \sqrt{5}

Simplify the radical.

\sqrt{240}**Find the largest square number that is a factor of the number under the root.**

Thinking about some of the perfect square numbers.

\begin{aligned} &1 = 1 \times 1 \\ &4 = 2 \times 2 \\ &9 = 3 \times 3 \\ &16 = 4 \times 4 \\ &25 = 5 \times 5 \\ &36 = 6 \times 6 \\ &49 = 7 \times 7 \\ &64 = 8 \times 8 \\ &81 = 9 \times 9 \end{aligned}

4 and 16 are perfect square numbers and factors of 240.

Use the perfect square factor that is larger. So, in this case use 16.

16 \times 15 = 240

\sqrt{240}=\sqrt{15 \times 16}=\sqrt{15} \times \sqrt{16}

\sqrt{15} → This is irrational and cannot be simplified, so leave it as is.

\sqrt{16} → This expression can be simplified. \sqrt{16}=4

**Write the simplified answer.**

\sqrt{240}=4 \sqrt{15}

In order to simplify a radical with a variable:

**If the exponent is even, go to step \bf{3} . If the exponent is odd, go to step \bf{2} .****Subtract \bf{1} from the exponent and rewrite the expression as a product.****Even exponents are perfect squares, take half of the exponent.****Write the simplified answer.**

Simplify the radical.

\sqrt{x^{10}}**If the exponent is even, go to step \bf{3} . If the exponent is odd, go to step \bf{2} .**

The exponent is 10 which is an even number.

**Subtract \bf{1} from the exponent and rewrite the expression as a product.**

The exponent is even.

**Even exponents are perfect squares, take half of the exponent.**

Even exponents are perfect squares. In this case, x^{10}=x^5 \times x^5

So, to take the square root, you can just divide the exponent by 2.

**Write the simplified answer.**

\sqrt{x^{10}}=x^5

Simplify the expression.

\sqrt{y^9}**If the exponent is even, go to step \bf{3} . If the exponent is odd, go to step \bf{2} .**

The exponent is 9 which is an odd number.

**Subtract \bf{1} from the exponent and rewrite the expression as a product.**

In this case, you can rewrite the expression, y^9 to be, y^1 \times y^8.

y^8 is a perfect square expression because, y^8=y^4 \times y^4.

\sqrt{y^1 \times y^8}=\sqrt{y} \times \sqrt{y^8}

\sqrt{y} → This expression is considered to be irrational and cannot be simplified so leave as is.

\sqrt{y^8} → This expression can be simplified. \sqrt{y^8}=y^4

**Even exponents are perfect squares, take half of the exponent.**

The original expression had an odd exponent.

**Write the simplified answer.**

\sqrt{y^9}=y^4 \sqrt{y}

Simplify the radical.

\sqrt{x^6 y^3}**If the exponent is even, go to step \bf{3} . If the exponent is odd, go to step \bf{2} .**

In this case, you have two variables. x^6 has an even exponent and y^3 has an odd exponent.

**Subtract \bf{1} from the exponent and rewrite the expression as a product.**

In this case, you can rewrite y^3 the expression to be, y^1 \times y^2.

y^2 is a perfect square expression because, y^2=y^1 \times y^1.

\sqrt{y^1 \times y^2}=\sqrt{y} \times \sqrt{y^2}

\sqrt{y} → This expression is considered irrational and cannot be simplified so leave as is.

\sqrt{y^2} → This expression can be simplified. \sqrt{y^2}=y^1

**Even exponents are perfect squares, take half of the exponent.**

x^6 has an even exponent. So, x^6 is a perfect square because x^3 \times x^3=x^6.

\sqrt{x^6}=x^3

**Write the simplified answer.**

\sqrt{x^6 y^3}=x^3 y \sqrt{y}

- Be sure to review the concept of perfect square numbers with students before simplifying radicals.

- Demonstrate alternate strategies for simplifying the number under the radical, such as prime factorization, for students that struggle with math facts.

- Instead of giving students worksheets to practice, have them engage in game playing such as scavenger hunts or using digital platforms.

**Incorrectly rewriting the number under the square root sign (the radicand) as a product of any two factors**

One of these factors must be a square number in order for you to be able to simplify the radical. For example, rewriting \sqrt{48} as \sqrt{6 \times 8} instead of \sqrt{16 \times 3}.

**Not simplifying fully**

Always check that there are no square factors of the number under the root. For example, \sqrt{32}=2 \sqrt{8} instead of fully simplifying to be 4 \sqrt{2}.

**Thinking that only variables that have perfect square exponents are perfect squares**

For example, thinking that \sqrt{x^9}=x^3 instead of \sqrt{x^9}=\sqrt{x} \times \sqrt{x^8}=x^4 \sqrt{x}.

- Adding radicals
- Subtracting radicals
- Rationalize the denominator
- Multiplying radicals
- Dividing radicals

1. Simplify the square root.

\sqrt{16}

4

8

256

32

16 is a perfect square number because 4 \times 4 = 16. So, \sqrt{16}=4.

2. Simplify the radical.

\sqrt{20}

10

5 \sqrt{4}

2 \sqrt{5}

4 \sqrt{5}

Thinking about the perfect square numbers, 4 is the largest perfect square factor of 20. So, rewrite the expression to be, \sqrt{20}=\sqrt{4 \times 5}=\sqrt{4} \times \sqrt{5}.

\sqrt{4} → This is a perfect square so it can be simplified to be \sqrt{4}=2.

\sqrt{5} → This is irrational and cannot be simplified.

So, \sqrt{20}=2 \sqrt{5}.

3. Simplify the radical.

\sqrt{108}

3 \sqrt{12}

6 \sqrt{3}

3 \sqrt{6}

4 \sqrt{27}

The largest perfect square factor of 108 is 36.

So, rewrite the expression to be, \sqrt{108}=\sqrt{36 \times 3}=\sqrt{36} \times \sqrt{3}.

\sqrt{36} → This is a perfect square so it simplifies to be \sqrt{36}=6.

\sqrt{3} → This is irrational so it cannot be simplified.

\sqrt{108}=6 \sqrt{3}

4. Simplify the expression.

\sqrt{y^{25}}

y^5

y^{12.5}

\sqrt{y^5}

y^{12} \sqrt{y}

y^{25} has an odd exponent so it is not a perfect square expression. Subtracting 1 from the exponent and rewriting to the expression as a product forces part of the expression to be simplified.

y^{25}=y \times y^{24}

So, \sqrt{y^{25}}=\sqrt{y \times y^{24}}=\sqrt{y} \times \sqrt{y^{24}}

\sqrt{y} → This is irrational and cannot be simplified.

\sqrt{y^{24}} → This is a perfect square expression and can be simplified to be y^{12}.

The simplified answer is:

\sqrt{y^{25}}=y^{12} \sqrt{y}.

5. Simplify the expression.

\sqrt{r^7 s^2}

r^3 s \sqrt{r}

r^3 s^2 \sqrt{r}

s \sqrt{r^7}

r s \sqrt{r}

To simplify the expression, \sqrt{r^7 s^2}, look at each variable separately.

\begin{aligned}& \sqrt{r^7 s^2}=\sqrt{r^7} \times \sqrt{s^2} \\\\ & \sqrt{r^7}=\sqrt{r \times r^7}=\sqrt{r} \times \sqrt{r^6} \end{aligned}

\sqrt{r} → This is irrational and cannot be simplified.

\sqrt{r^6} → This is a perfect square expression and can be simplified to be r^3.

\sqrt{s^2} is a perfect square expression because s \times s=s^2.

\sqrt{s^2} → Simplifies to be s.

So, \sqrt{r^7 s^2}=r^3 s \sqrt{r}.

6. Simplify the expression.

\sqrt{32 x^8}

16 x

4 \sqrt{2 x^8}

4 x^4 \sqrt{2}

2 x^4 \sqrt{4}

Rewrite \sqrt{32 x^8} to be \sqrt{32} \times \sqrt{x^8}.

Thinking about the perfect square numbers. 16 is the largest perfect square factor of 32.

\sqrt{32}=\sqrt{16} \times \sqrt{2}

\sqrt{16} → This is a perfect square number and simplifies to be 4.

\sqrt{2} → This is irrational and cannot be simplified.

\sqrt{x^8} → The exponent is even so this is a perfect square expression. It simplifies to be x^4 (take half of the original exponent).

The simplified answer is: \sqrt{32 x^8}=4 x^4 \sqrt{2}.

There are decimals that are perfect squares such as 0.25. So, is a rational expression \sqrt{0.25}=0.5.

Rational exponents can be used to rewrite radical expressions. For example \sqrt{x}=x^{\frac{1}{2}} where \cfrac{1}{2} is the fractional exponent representing square root. You will learn how to convert between radical form and exponential form in algebra.

Yes, there are polynomials that are perfect square expressions. For example, \sqrt{(x+3)^2}=x+3. You work with simplifying polynomials under radicals in algebra 2 and precalculus.

Yes, there are radical equations that you will learn how to solve in algebra 1 and algebra 2 classes.

Square roots of prime numbers are considered irrational and cannot be simplified.

A complex number is in the form of a+b i where i=\sqrt{-1}. You will work with complex numbers and their conjugates in precalculus.

The square root of negative numbers is considered to be imaginary numbers. For example, \sqrt{-4}=2 i.

The step-by-step approach to simplifying cube roots is very similar to simplifying square roots. You will look for perfect cube factors of the number instead of perfect square factors of the number.

- Radical functions
- Vectors
- Trig graphs
- Quadratic Equations

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