Math resources Ratio and proportion

Proportion

Direct and inverse variation

Direct and inverse variation

Here you will learn about direct and inverse variation, including the concepts of direct proportion and inverse proportion. You will look at solving some real-life word problems involving these different proportional relationships.

Students will first learn about direct and inverse variation as part of ratios and proportional relationships in 7th grade.

What are direct and inverse variation?

Direct and inverse variation are two different types of proportional relationships that describe how quantities are related to each other.

  • Direct variation, or direct proportion, is a relationship between two quantities in which, as one quantity increases, the other quantity also increases.

For example,

The cost of a banana is 70 cents. As the number of bananas increases, so does the cost; 3 bananas would cost 3 times the cost of one banana (\$2.10).

If y is directly proportional to x (y\propto{x}), then y=kx where k is the constant of proportionality.

Step-by-step guide: Directly proportional

  • Inverse variation, or inverse proportion, is a relationship between two quantities in which one quantity increases while the other decreases, and vice versa. This is also called indirect variation.

For example, it takes 1 worker 9 hours to dig a hole. As the number of workers increases, the number of hours it takes to dig the same hole decreases. 3 workers would take a third of the time ( 3 hours).

To calculate inverse variation problems, you need to appreciate that multiplication and division are inverse operations of each other.

If y is inversely proportional to x (y\propto\cfrac{1}{x}), then y=\cfrac{k}{x} where k is the constant of proportionality.

Step-by-step guide: Inversely proportional

What are direct and inverse variation?

What are direct and inverse variation?

Common Core State Standards

How does this relate to 7th grade math and high school math?

  • Grade 7 – Ratios and Proportional Relationships (7.RP.A.2)
    Recognize and represent proportional relationships between quantities.

  • High School – Functions – Interpreting Functions (HS.F.IF.B.4)
    For a function that models a relationship between two quantities, interpret key features of graphs and tables in terms of the quantities, and sketch graphs showing key features given a verbal description of the relationship.

    Key features include: intercepts; intervals where the function is increasing, decreasing, positive, or negative; relative maximums and minimums; symmetries; end behavior; and periodicity.

[FREE] Direct Variation Worksheet (Grade 7 and 8)

[FREE] Direct Variation Worksheet (Grade 7 and 8)

[FREE] Direct Variation Worksheet (Grade 7 and 8)

Use this worksheet to check your 7th and 8th grade students’ understanding of direct variation. 15 questions with answers to identify areas of strength and support!

DOWNLOAD FREE
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[FREE] Direct Variation Worksheet (Grade 7 and 8)

[FREE] Direct Variation Worksheet (Grade 7 and 8)

[FREE] Direct Variation Worksheet (Grade 7 and 8)

Use this worksheet to check your 7th and 8th grade students’ understanding of direct variation. 15 questions with answers to identify areas of strength and support!

DOWNLOAD FREE

How to use direct and inverse variation

In order to answer word problems involving direct and inverse variation:

  1. Determine the type of proportionality relationship between the two quantities.
  2. Calculate the constant of proportionality, \textbf{k} .
  3. Calculate the unknown value.

Direct and inverse variation examples

Example 1: direct proportion

A t-shirt costs \$4. How much do 5 t-shirts cost?

  1. Determine the type of proportionality relationship between the two quantities.

As the number of t-shirts increases, so does the cost. This is an example of direct variation, or direct proportion.

2Calculate the constant of proportionality, \textbf{k} .

For direct proportion, the constant of proportionality k is the cost of one t-shirt.

As this is a given value (a t-shirt costs \$4 ) you can say k=4 and so y=4x where the y value would represent the total cost of x number of t-shirts.

3Calculate the unknown value.

Substituting x=5 into y=4x, you have y=4\times{5}=20.

4Write the solution.

The cost of 5 t-shirts is \$20.

Example 2: direct proportion

7 bags of candy weigh 350 grams. How much do 10 bags of candy weigh?

Determine the type of proportionality relationship between the two quantities.

Calculate the constant of proportionality, \textbf{k} .

Calculate the unknown value.

Write the solution.

Example 3: direct proportion

8 laps of a race track has a total of 12 \, km. What would the distance be for 20 laps of the race track?

Determine the type of proportionality relationship between the two quantities.

Calculate the constant of proportionality, \textbf{k} .

Calculate the unknown value.

Write the solution.

Example 4: inverse proportion

A worker takes 10 days to fit a bathroom. How long would it take 2 workers to fit a bathroom?

Determine the type of proportionality relationship between the two quantities.

Calculate the constant of proportionality, \textbf{k} .

Calculate the unknown value.

Write the solution.

Example 5: inverse proportion

An oil tank takes 25 hours to be filled by 3 hose pipes. How long does it take 5 hose pipes to fill the same oil tank?

Determine the type of proportionality relationship between the two quantities.

Calculate the constant of proportionality, \textbf{k} .

Calculate the unknown value.

Write the solution.

Example 6: inverse proportion

10 computers can do a task in 15 minutes. How long does it take 3 computers to do the same task?

Determine the type of proportionality relationship between the two quantities.

Calculate the constant of proportionality, \textbf{k} .

Calculate the unknown value.

Write the solution.

Teaching tips for direct and inverse variation

  • Start by explaining that the constant of variation is a fixed number that defines the relationship between two variables in both direct and inverse variation.

  • Draw graphs to show how quantities relate in direct variation (a straight line passing through the origin) and in inverse variation (a hyperbola). Tables can also help students see patterns in values.

  • Teach students to apply inequalities to explore limits in direct and inverse variation.

    For example, in direct variation y=3x, setting x\leq{10} shows that y grows proportionally up to a maximum.

    In inverse variation y=\cfrac{12}{x}, using x>0 highlights that as x increases, y decreases but never reaches zero.

  • Provide worksheets with a variety of practice questions on direct and inverse variation. Start with straightforward problems to identify constants of variation, then include word problems that require students to set up and solve equations, ensuring they understand how to manipulate both sides of the equation.

  • To integrate more advanced concepts, challenge students to work with rational expressions and polynomial equations involving variables x and y, where y increases with changes in x.

    Incorporate problems that require them to use square roots and exponents, helping them see the connections between these concepts and variation principles.

Easy mistakes to make

  • Modeling assumption
    Whenever you solve word problems for proportion, you assume everything has the same value. If the question involves the costs of pencils, you assume each pencil costs the same. If the question involves the number of people working, you assume all the workers work at the same rate.

  • Misunderstanding inverse proportion
    Direct proportion is described as β€œas one value increases, so does the other.” Inverse proportion is therefore considered to be the opposite where β€œas one value decreases, so does the other”.

    This is not true. An inversely proportional or inverse relationship shows that when one value increases, the other decreases. As a graph, this would look like a reciprocal graph.

  • Mistaking an inverse variation problem for a direct variation problem
    For example, if 3 people take 12 hours to build a wall, 6 people take 24 hours to build the same size wall. This is not true as you assume everyone works at the same rate and so the wall should be built in less time if more people are building it.

    As the number of people increases, the time taken to build the wall decreases and so if you have 6 builders (double the original amount), the time it takes to build the wall should be 6 hours (half of the original amount). The type of proportion must be determined for every proportionality question.

  • Writing money incorrectly
    Money is used in some proportional word problems. If an answer is 4.1 you may be tempted to write it as \$4.1, but the correct way of writing it would be \$4.10.

  • Writing time incorrectly
    Time is used in some proportional word problems. If an answer is 7.25 you may be tempted to write it as 7 hours 25 minutes, but it would be 7 hours 15 minutes. (Remember there are 60 minutes in an hour).

Practice direct and inverse variation questions

1. One tennis ball weighs 57 grams. Find the weight of 4 tennis balls.

7 grams

GCSE Quiz False

228 grams

GCSE Quiz True

14.25 grams

GCSE Quiz False

61 grams

GCSE Quiz False

k=57 and y=kx where y is the weight of x number of tennis balls.

 

This means that y=57x.

 

When x=4, \, y=57\times 4=228 grams.

2. One worker takes 30 hours to build a wall. Find the time it would take 5 workers to build a similar wall.

150 hours

GCSE Quiz False

35 hours

GCSE Quiz False

6 hours

GCSE Quiz True

120 hours

GCSE Quiz False

k=30 and y=\cfrac{k}{x} where y is the time taken to build a wall with x number of people.

 

This means that y=\cfrac{30}{x}.

 

When x=5, \, y=30\div{5}=6 hours.

3. 4 computer games cost \$18. Find the cost of 5 computer games.

\$23.50
GCSE Quiz False

\$22
GCSE Quiz False

\$24.50
GCSE Quiz False

\$22.50
GCSE Quiz True

k=\cfrac{y}{x} where y is the cost and x Β is the number of computer games.Β 

 

k=\cfrac{18}{4} = 4.5

 

This means that 1 Β computer game costs \$4.50

 

And so y=4.5x

 

When k=4.5, \, y=4.5\times{3}=\${22.50}

4. 7 workers take 20 weeks to build a house. How long would it take 10 workers to build the same house?

17 weeks

GCSE Quiz False

28.6 weeks

GCSE Quiz False

14 weeks

GCSE Quiz True

140 weeks

GCSE Quiz False

k=xy. When x=7, \, y=20 and so k=7 \times 20=140.

 

This means that it would take 1 person 140 weeks to build the house and so y=\cfrac{140}{x}.

 

When x=10, \, y=140\div{10}=14 weeks.

5. 5 pens cost 65 cents. Find the cost of 8 pens.

\$1.04
GCSE Quiz True

\$0.13
GCSE Quiz False

\$0.82
GCSE Quiz False

\$104
GCSE Quiz False
k=\cfrac{y}{x}.

 

When x=5, \, y=65 and so k=65\div{5}=13.

 

This means that 1 pen costs \$0.13 and so y=0.13x.

 

When x=8, \, y=0.13\times{8}=\${1.04}

6. 4 machines take 15 hours to complete a job. Find how long it would take 3 machines to complete the same job.

45 hours

GCSE Quiz False

5 hours

GCSE Quiz False

60 hours

GCSE Quiz False

20 hours

GCSE Quiz True

k=xy. When x=4, \, y=15 and so k=4 \times 15=60.

 

This means that it would take 1 machine 60 hours to complete the job and so y=\cfrac{60}{x}.

 

When x=3, \, y=60\div{3}=20 hours.

Direct and inverse variation FAQs

What is direct variation?

Direct variation describes a relationship between two variables in which one variable increases or decreases proportionally with the other.

The direct variation equation is y=kx where k is the constant of variation.

What is inverse variation?

Inverse variation occurs when one variable increases as the other decreases. The product of the two variables remains constant.

The inverse variation equation is y=\cfrac{k}{x} where k is the constant of variation.

When do students learn about direct and inverse variation?

Students typically learn about direct and inverse variation in middle school (Grades 7-8) as they explore basic proportional relationships.

In high school, concepts are covered in more depth in Algebra 1 and Algebra II, where students work with equations and real-world applications.

Advanced courses like Pre-Calculus may revisit these concepts through functions and transformations.

What is joint variation?

Joint variation is a type of proportional relationship where a variable depends on the product of two or more other variables. It’s represented by the equation z=kxy.

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