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Combining like termsHere you will learn about simplifying expressions, including using the distributive property and combining like terms.
Students will first learn about simplifying expressions as part of expressions and equations in 6th grade.
Simplifying expressions involves using the properties of operations to create equivalent algebraic expressions.
For example,
Simplify 4(x+7)-x.
First, look at 4(x+7) which is β4 times the sum of x and 7.β
Notice that each method shows 4(x+7)=4x+28.
Since 4(x+7)-x=4x+28-x, you can continue to simplify by combining the like terms, in this case the x s.
Use the commutative property to change the order:
4x+28-x=4x-x+28
Next, letβs simplify the 4x-x .
Visually, if you have 4 positive x ‘s and we subtract an x, you are left with 3 positive x ‘s:
So, 4x-x=3x.
This means that 4x+28-x can be simplified to 3x+28.
You cannot simplify any further because β3xβ and β+28β are not like terms. One has the variable x, and the other is a constant.
How does this relate to 6th grade math?
Use this worksheet to check your 6th grade studentsβ understanding of simplifying expressions. 15 questions with answers to easily identify areas of strength and support!
DOWNLOAD FREEUse this worksheet to check your 6th grade studentsβ understanding of simplifying expressions. 15 questions with answers to easily identify areas of strength and support!
DOWNLOAD FREEIn order to simplify expressions:
Simplify 3 \, (5 + p).
3 \, (5 + p) is β3 times the sum of 5 and p.β
There are 3 different ways to solve:
Notice that each method shows 3 \, (5 + p) = 15 + 3p.
2Combine like terms.
You cannot simplify any further because β+3pβ and β15ββ are not like terms. One has the variable p, and the other is a constant.
3Write the simplified expression.
3 \, (5 + p) simplified is 15 + 3p.
Simplify 2 \, (2m + 6) + 1.
Multiply the terms within the parentheses by the term on the outside.
2 \, (2m + 6) is β2 times the sum of 2m and 6.β
There are 3 different ways to solve:
Combine like terms.
You can simplify further because β+12β and β+1β are like terms: 12 + 1 = 13.
Write the simplified expression.
2 \, (2m + 6) + 1 simplified is 4m + 13.
Simplify 4 \, (8-k) + 3k.
Multiply the terms within the parentheses by the term on the outside.
4 \, (8-k) is β4 times the difference of 8 and k.β
There are 3 different ways to solve:
Combine like terms.
Since β-4kβ and β+3kβ are like terms, you can simplify further and combine them: -4k + 3k.
Visually if you have 4 negative ks and 3 positive ks, each negative and positive create a zero pair, leaving 1 negative k :
So, -4k + 3k = -k.
Write the simplified expression.
4 \, (8-k) + 3k simplified is 32-k.
Simplify 9 \, (1 + 2y) - 5y.
Multiply the terms within the parentheses by the term on the outside.
9 \, (1 + 2y) is β9 times the sum of 1 and 2y.β
Distribute the 9 to the 1 and the +2y.
So, 9 \, (1 + 2y)-5y = 9 + 18y-5y.
Combine like terms.
You can simplify further because β+18yβ and β-5yβ are like terms: 18y-5y.
Visually if you have 18 positive y s and then subtract 5 \, y s, there are 13 positive y s left:
So, 18y-5y = 13y.
Write the simplified expression.
9 \, (1 + 2y)-5y simplified is 9 + 13y.
Simplify 7 \, (h + 4t)-9t.
Multiply the terms within the parentheses by the term on the outside.
7 \, (h + 4t) is β7 times the sum of h and +4t.β
Distribute the 7 to the h and the 4t.
So, 7\, (h + 4t)-9t = 7h + 28t-9t.
Combine like terms.
You can simplify further because β+28tβ and β-9tβ are like terms: 28t-9t = 19t.
Write the simplified expression.
7 \, (h + 4t)-9t simplified is 7h + 19t.
Write the simplified expression for the perimeter of the shape.
Multiply the terms within the parentheses by the term on the outside.
The perimeter of the rectangle is 2l + 2w = 2 \, (x-2) + 2 \, (2x + 3).
\hspace{1.5cm} 2 \, (x-2) \hspace{2cm} + \hspace{2cm} 2 \, (2x + 3)
\hspace{0.8cm} 2 \, (x-2) is β2 times \hspace{3cm} 2 \, (2x + 3) is β2 times
\hspace{0.3cm} the difference of x and 2.β \hspace{2.8cm} the sum of 2x and 3.β
Distribute the 2 to the x and the -2. \hspace{0.8cm} Distribute the 2 to the 2x and the 3.
So, 2 \, (x-2) + 2 \, (2x + 3) = 2x-4 + 4x + 6.
Combine like terms.
You can simplify further because β+2xβ and β+4xβ are like terms: 2x + 4x = 6x.
β-4β and β6β are also like terms: -4 + 6.
Visually if you have 4 negatives and add 6 positives, each negative and positive create a zero pair, leaving 2 positives:
So, -4 + 6 = 2.
Write the simplified expression.
2 \, (x-2) + 2 \, (2x + 3) simplified is 6x + 2.
Use this worksheet to check your 6th grade studentsβ understanding of simplifying expressions. 15 questions with answers to easily identify areas of strength and support!
DOWNLOAD FREEUse this worksheet to check your 6th grade studentsβ understanding of simplifying expressions. 15 questions with answers to easily identify areas of strength and support!
DOWNLOAD FREE1. Simplify 4 \, (d + 10).
4 \, (d + 10) is β4 times the sum of d and 10.β
There are 3 different ways to solve:
2. Simplify 3 \, (1 + 3f)-4f.
Simplify the parentheses first.
3 \, (1 + 3f) is β3 times the sum of 1 and 3f.β
There are 3 different ways to solve:
You can simplify further because β+9fβ and β-4fβ are like terms: 9f-4f.
Visually if you have 9 positive f s and then subtract 4 \, f s, there are 5 positive f s left:
So, 9f-4f = 5f.
3 \, (1 + 3f)-4f simplified is 5f + 3.
*Remember, because of the commutative property 3 + 5f = 5f + 3.
3. Simplify 2 \, (x-4) + 9x.
Simplify the parentheses first.
2 \, (x-4) is β2 times the difference of x and 4.β
There are 3 different ways to solve:
You can simplify further because β2xβ and β+9xβ are like terms: 2x + 9x.
Visually if you have 2 positive x s and then add 9 \, x s, there are 11 positive x s left:
So, 2x + 9x = 11x.
2 \, (x-4) + 9x simplified is 11x-8.
4. Simplify 6 \, (4m + 7)-30.
Simplify the parentheses first.
6 \, (4m + 7) is β6 times the sum of 4m and 7.β
Distribute the 6 to the 4m and the 7.
So, 6 \, (4m + 7)-30 = 24m + 42-30.
You can simplify further because β+42β and β-30β are like terms: 42-30 = 12.
6 \, (4m + 7)-30 simplified is 24m + 12.
5. Simplify 11 \, (n + 2b)-15b.
Simplify the parentheses first.
11 \, (n + 2b) is β11 times the sum of n and 2b.β
Distribute the 11 to the n and the 2b.
So, 11 \, (n + 2b)-15b = 11n + 22b-15b
You can simplify further because β+22bβ and β-15bβ are like terms: 22b-15b = 7b.
11 \, (n + 2b)-15b simplified is 11n + 7b.
6. Write the simplified expression for the perimeter of the shape.
To calculate the perimeter, add all side lengths together by combining the like terms.
The simplified expression for the perimeter is 8x + 22.
Yes, you can use factoring to reverse the distributive property.
Yes, in 7th grade, students will learn to simplify rational expressions that are equal to linear equations, including fractions with variables in the numerator and/or the denominator and expressions.
In 8th grade, students will expand on this knowledge by including variables with exponents and continuing into high school, where algebraic expressions are simplified within inequalities.
No, the distributive property can be used with multiplication and division. For example,
55 \div 5
=(45+10) \div 5
=45 \div 5+10 \div 5
=9+2
=11
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