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Types of triangles Perimeter Area Calculator skills Rearranging equations FractionsHere you will learn about trig formulas, or trigonometry formulas, including the three trigonometric functions; the sine function, Sin, the cosine function, Cos, and the tangent function, Tan.
You will also look at the inverse trigonometric functions, the sine rule, cosine rule, and the trigonometric formula for the area of a triangle.
Students will first learn about trig formulas as part of trigonometric functions in high school.
Trig formulas, or trigonometry formulas, are formulas that are used to represent relationships between the parts of a triangle including the side lengths, angles and the area.
To solve problems using trig formulas, you need to be able to use the information provided to deduce which trigonometric formula you need to use.
Use this quiz to check your grade 9 to 12 students’ understanding of Trigonometry. 15+ questions with answers covering a range of 9th to 12th grade trigonometry topics to identify areas of strength and support!
DOWNLOAD FREEUse this quiz to check your grade 9 to 12 students’ understanding of Trigonometry. 15+ questions with answers covering a range of 9th to 12th grade trigonometry topics to identify areas of strength and support!
DOWNLOAD FREEBasic trigonometry focuses on the right-angled triangle.
The three trigonometric functions you use are sine (sin), cosine (cos) and tangent (tan). These three functions relate an angle to two sides of a right-angled triangle, giving us the three trigonometric ratios.
The letter x represents a value, hence, f(x) is a function of the value x.
The symbol \theta represents the angle.
The letter O represents the opposite side to the angle \theta.
The letter A represents the adjacent side to the angle \theta.
The letter H represents the hypotenuse of the right-angled triangle (which is always the side of the triangle facing the right-angle). Also known as the longest side of the triangle.
Step-by-step guide: SOHCAHTOA
When you know two of the three sides of a right angled triangle and you want to find a missing angle, you need to use inverse trigonometric functions. The three inverse trigonometric functions are:
Step-by-step guide: Trig functions
You can use trigonometry in all types of triangles including scalene, equilateral and isosceles.
The sine rule (sometimes called the law of sines) is the relationship between the sine of an angle, and the side opposite that angle.
More specifically the ratio of the sine of an angle and the opposing side to that angle is the same for all three angles / sides. As a formula, this is written as
\cfrac{a}{\sin{A}}=\cfrac{b}{\sin{B}}=\cfrac{c}{\sin{C}}
Where a, \, b, and c are the three sides of a triangle, and A, \, B, and C are the angles that face their opposing side (see the diagram below).
Notice that the upper case letters denote the angles, and the lower case letters denote the side lengths where a is opposite A, \, b is opposite B, and c is opposite C.
The equation above shows how all three side lengths, divided by the sine of the angle facing that side, are the same value. You only need to work with a pair of letters, giving us the working formula for the law of sines.
\cfrac{a}{\sin{A}}=\cfrac{b}{\sin{B}}
You can use the sine rule to find:
Step-by-step guide: Law of sines
For example,
Below is a non-right angled triangle. You can use the law of sines to find the length AB.
The cosine rule (sometimes called the law of cosines ) is the relationship between the cosine of an angle, and all three sides of the triangle.
As a formula, this is written as
a^{2}=b^{2}+c^{2}-2bc\cos(A)
Where a, \, b, and c are the three sides of a triangle, and A is the angle between the two sides of b and c (see the diagram below).
Notice that the upper case A is an angle, and the lower case letters are the side lengths where a is opposite A, and b and c are the two sides that surround the angle A.
You need to use the cosine rule when you don’t know one of the four values of a, \, b, \, c, or A.
You can use the cosine rule to find
Step-by-step guide: Law of cosines
For example,
Below is a non-right angled triangle. You can use the law of cosine to find the length BC.
You can calculate the area of any triangle if you need to know two sides and the included angle between those two sides. The formula is
A=\cfrac{1}{2} \, ab\sin(C)
Where C is the angle between the two sides of a and b (see the diagram below).
You can also find a missing angle knowing the area of the triangle and by rearranging the formula to find the angle C.
C=\sin^{-1}\left(\cfrac{2A}{ab}\right)
You can find a missing side length knowing the area of the triangle and rearranging the formula to find a missing side length a.
a=\cfrac{2A}{b\sin(C)}
For example,
You can find the area of the triangle below using the trigonometric formula for the area of any triangle.
In order to determine which trigonometric formula you need to use, the flow chart below can help you decide.
Remembering that, to find the area of any triangle, you can use the sine rule for area.
How does this relate to high school math?
In order to solve problems using trigonometry formulas:
Calculate the length of the side labeled x. Write your answer correctly to the nearest hundredth.
Using the flowchart,
This means that you need to use either of the three trig ratios of sine, cosine or tangent. You can work out which one in the next step.
2Label each side and angle appropriately.
From the angle of 20^{\circ},
As you know the opposite side and you want to find the hypotenuse, the trigonometric ratio that you have to use is \sin(\theta)=\cfrac{O}{H}.
Here, you used the abbreviation SOHCAHTOA, where SOH is the sine ratio S, of the opposite O, and the hypotenuse H.
3Substitute known values into the formula.
As O=10, \, H=x, and \theta=20, substituting these values into the formula \sin(\theta)=\cfrac{O}{H}, you have
\sin(20)=\cfrac{10}{x}.4Solve for the unknown value.
Multiplying both sides by x gives us
x\times\sin(20)=10.Dividing both sides by \sin(20) gives us
x=\cfrac{10}{\sin(20)}=29.238044…This means that the length x=29.24\text{ cm (nearest hundredth)}
Determine the size of the missing angle, marked \theta in the triangle below. Write your answer correctly to the nearest hundredth.
Determine which trigonometry formula is needed to answer the question.
Using the flowchart,
This means that you need to use either of the three trig ratios of sine, cosine or tangent. You can work out which one in the next step.
Label each side and angle appropriately.
From the angle of \theta,
As you know the adjacent side and the hypotenuse, the trigonometric ratio that you have to use is \cos(\theta)=\cfrac{A}{H}.
However, as you need to find the missing angle, you need to use the inverse trigonometric formula \theta=\cos^{-1}\left(\cfrac{A}{H}\right).
Here, you used the abbreviation SOHCAHTOA, where CAH is the cosine ratio C, of the adjacent A, and the hypotenuse H.
Substitute known values into the formula.
As A=2, \, H=2.8, and \theta is unknown, substituting these values into the formula \theta=\cos^{-1}\left(\cfrac{A}{H}\right), you have
\theta=\cos^{-1}\left(\cfrac{2}{2.8}\right).
Solve for the unknown value.
This means that the angle \theta=44.42^{\circ}\text{ (nearest hundredth)}.
Determine the missing length x of the right-angled triangle below. Write your answer to the nearest hundredth.
Determine which trigonometry formula is needed to answer the question.
Using the flowchart,
This means that you need to use either of the three trig ratios of sine, cosine or tangent. You can work out which one in the next step.
Label each side and angle appropriately.
From the angle of 15^{\circ},
As you know the opposite side and the adjacent side, the trigonometric ratio that you have to use is \tan(\theta)=\cfrac{O}{A}.
Here, you used the abbreviation SOHCAHTOA, where TOA is the tangent ratio T, of the opposite O, and the adjacent A.
Substitute known values into the formula.
As A=7, \, O=x, and \theta=15, substituting these values into the formula \tan(\theta)=\cfrac{O}{A}, you have
\tan(15)=\cfrac{x}{7}.
Solve for the unknown value.
Multiplying both sides by 7 gives us
7\times\tan(15)=x.
This means that x=7\tan(15)=1.875644347...
The length x=1.88\text{ cm (nearest hundredth)}.
Determine the length of the side labeled x for the triangle below. Write your answer correctly to the nearest hundredth.
Determine which trigonometry formula is needed to answer the question.
Using the flowchart,
For this question, you can only use the cosine rule (the law of cosines), a^{2}=b^{2}+c^{2}-2bc\cos(A).
Label each side and angle appropriately.
From the angle at A of 27^{\circ},
Substitute known values into the formula.
As A=27, \, a=x, \, b=15, and c=10, substituting these into the cosine rule a^{2}=b^{2}+c^{2}-2bc\cos(A), you have x^{2}=15^{2}+10^{2}-2\times{15}\times{10}\times\cos(27)
Solve for the unknown value.
The length x=7.60\text{ cm (nearest hundredth)}.
Determine the size of the missing angle \theta. Write your answer to the nearest hundredth.
Determine which trigonometry formula is needed to answer the question.
Using the flowchart,
For this question, you can only use the sine rule (the law of sines), \cfrac{a}{\sin{A}}=\cfrac{b}{\sin{B}}=\cfrac{c}{\sin{C}}.
Label each side and angle appropriately.
From the angle at A of \theta,
Substitute known values into the formula.
As a=6.5, \, A=\theta, \, b=7, and B=52^{\circ}, substituting these into the sine rule \cfrac{a}{\sin{A}}=\cfrac{b}{\sin{B}}, you have \cfrac{6.5}{\sin{\theta}}=\cfrac{7}{\sin{52}}.
Remember that you do not need to use all three parts of the formula for the sine rule so you only have one equals sign.
Solve for the unknown value.
Multiplying both sides by \sin({\theta}), you have
6.5=\cfrac{7\sin{\theta}}{\sin{52}}
Multiplying both sides by \sin{{52}}, you have
6.5\sin{52}=7\sin{\theta}
Dividing both sides by 7, you have
\cfrac{6.5\sin{52}}{7}=\sin{\theta}
Calculating the inverse sine of each side, you have
\sin^{-1}\left(\cfrac{6.5\sin{52}}{7}\right)=\theta
This gives the value \theta=47.03114122…=47.03^{\circ}\text{ (nearest hundredth)}.
Calculate the area of the triangle below. Write your answer correctly to the nearest hundredth.
Determine which trigonometry formula is needed to answer the question.
As you are calculating the area of the triangle, you use the sine rule for area Area=\cfrac{1}{2} \, ab\sin(C).
Label each side and angle appropriately.
From the angle at C of 39^{\circ},
Substitute known values into the formula.
As a=5, \, b=7, and C=39, substituting these into the formula for the area of a triangle using the sine rule Area=\cfrac{1}{2} \, ab\sin{C}, you have A=\cfrac{1}{2}\times{5}\times{7}\times\sin{39}.
Solve for the unknown value.
As you are finding the area, the units are in cm^{2}.
This gives the solution A=11.01 \, cm^{2}\text{ (nearest hundredth)}.
1. Determine the size of the missing side marked x in the triangle below. Write your answer to the nearest hundredth.
After labeling the triangle with O, \, A and H,
\begin{aligned}x&=\cfrac{8}{\cos{51}} \\\\ &=12.71212583… \\\\ &=12.71\text{ cm (nearest hundredth)} \end{aligned}
2. Determine the size of the missing angle marked \theta in the triangle below. Write your answer to the nearest hundredth.
After labeling the triangle with O, \, A and H,
SOH CAH TOA
\begin{aligned}\tan({\theta})&=\cfrac{8}{16} \\\\ \theta&=\tan^{-1}\left(\cfrac{8}{16}\right) \\\\ &=26.56505118… \\\\ &=26.57^{\circ}\text{ (nearest hundredth)} \end{aligned}
3. Determine the size of the missing angle marked \theta in the triangle below. Write your answer to a suitable degree of accuracy.
After labeling the triangle with O, \, A and H,
SOH CAH TOA
\begin{aligned}\tan({\theta})&=\cfrac{5}{3} \\\\ \theta&=\tan^{-1}\left(\cfrac{5}{3}\right) \\\\ &=59.03624347… \\\\ &=59.04^{\circ}\text{ (nearest hundredth)} \end{aligned}
4. Determine the size of the missing length marked x in the triangle below. Write your answer to the nearest hundredth.
Labeling the sides and angles, you have
As you know the two side lengths of b and c and the included angle at A, you need to use the cosine rule (the law of cosines) to determine the length of side x.
\begin{aligned}a^{2}&=b^{2}+c^{2}-2bc\cos(A) \\\\ x^{2}&=7^{2}+7^{2}-2\times{7}\times{7}\times\cos(45) \\\\ x^2&=98-98\cos(45) \\\\ x^2&=28.70353544… \\\\ x&=\sqrt{28.70353544…} \\\\ x&=5.357568053… \\\\ x&=5.36\text{ cm (nearest hundredth)} \end{aligned}
5. Determine the size of the missing angle marked \theta in the triangle below. Write your answer to the nearest hundredth.
Labeling the sides and angles, you have
As you know the angle at C the length of side c, the length of side b and you want to determine the angle at B, you need to use the sine rule (the law of sines) to determine the length of angle \theta.
Being careful with the labeling and the correct version of the sine rule, you have
\begin{aligned}\cfrac{\sin{B}}{b}&=\cfrac{\sin{C}}{c} \\\\ \cfrac{\sin{\theta}}{21}&=\cfrac{\sin{34}}{18} \\\\ \sin{\theta}&=\cfrac{\sin{34}}{18}\times{21} \\\\ \theta&=\sin^{-1}\left(\cfrac{21\sin{34}}{18}\right) \\\\ \theta&=40.72217103… \\\\ \theta&=40.72^{\circ}\text{ (nearest hundredth)} \\\end{aligned}
6. Determine the area of the triangle below. Write your answer to the nearest hundredth.
As you know the included angle between two side lengths, you can find the area of a triangle using sine where
a=3.2 \, cm, \, b=8.1 \, cm and C=41^{\circ}.
\begin{aligned}A&=\cfrac{1}{2} \, ab\sin{C} \\\\ &=\cfrac{1}{2}\times{3.2}\times{8.1}\times\sin{41} \\\\ &=12.96\sin{41} \\\\ &=8.502525016… \\\\ A&=8.50\text{ cm}^{2}\text{ (nearest hundredth)} \end{aligned}
Here is a list of trig formulas you may need to know:
◦ Basic trigonometric formulas
◦ Inverse trigonometric formulas
◦ Trigonometry identities
◦ Reciprocal identities
◦ Periodic identities
◦ Co-function identities
◦ Sum and difference identities
◦ Double angle identities
◦ Triple angle identities
◦ Half angle identities
◦ Product identities
◦ Sum to product identities
The Pythagorean identity is a fundamental trigonometric identity that relates the squares of the sine and cosine of an angle. It is expressed as: \sin^{2}{\theta} + \cos^{2}{\theta}=1.
This identity states that for any angle \theta, the sum of the square of the sine of the angle and the square of the cosine of the angle always equals 1. It is derived from Pythagoras’ theorem applied to a right triangle in the unit circle.
A trigonometry table is a chart that lists the values of trigonometric functions—such as sine, cosine, and tangent—for various angles, typically in degrees or radians. These tables were historically used to find the values of these functions before the widespread use of calculators.
Reciprocal identities are trigonometric identities that express each trigonometric function as the reciprocal of another function. For example:
◦ Secant or \sec \theta \, (\sec\theta=\cfrac{1}{\sin{\theta}})
◦ Cosecant or \cosec \theta \, (\csc\theta=\cfrac{1}{\cos{\theta}})
◦ Cotangent or \cot \theta \, (\cot\theta=\cfrac{1}{\tan{\theta}})
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