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Addition and subtraction Negative numbersVector notation
Column vectors
Adding vectorsHere you will learn about vector subtraction, including representing subtracting vectors graphically and understanding the subtraction of vectors as magnitude.
Students will first learn about the subtraction of vectors as a part of Vector and Matrix Quantities in high school mathematics.
Vector subtraction is subtracting one vector from another vector.
To do this, subtract the horizontal components (top numbers) of the column vector and subtract the vertical components (bottom numbers) of the column vector.
For example, look at vector \mathbf{a} and vector \mathbf{b}.
\mathbf{a}= \left(\begin{aligned} 5\\ 4\\ \end{aligned}\right) \quad \mathbf{b}= \left(\begin{aligned} 3\\ 1\\ \end{aligned}\right) \mathbf{a}-\mathbf{b}= \left(\begin{aligned} 5\\ 4\\ \end{aligned}\right) -\ \left(\begin{aligned} 3\\ 1\\ \end{aligned}\right) =\ \left(\begin{aligned} 2\\ 3\\ \end{aligned}\right)Subtracting vectors is based on the addition of vectors. The first vector stays the same, but the second vector reverses to the opposite direction to become a negative vector. Using the inverse allows you to change vector subtraction to vector addition.
\mathbf{a}-\mathbf{b}=\mathbf{a}+-\mathbf{b}Using vector \mathbf{a} and vector \mathbf{b}, letβs see what happens.
\mathbf{a}= \left(\begin{aligned} 5\\ 4\\ \end{aligned}\right) \mathbf{b}= \left(\begin{aligned} 3\\ 1\\ \end{aligned}\right)The direction of the vector \mathbf{-b} is opposite to the direction of the original vector \mathbf{b}, but has the same magnitude of the resultant vector, or distance from the initial point or starting point.
-\mathbf{b}= \left(\begin{aligned} -3\\ -1\\ \end{aligned}\right)You know from vector addition that when adding two vectors, you add the second on to the end of the first, as shown below.
The final answer is known as the resultant vector or new vector.
\mathbf{a}-\mathbf{b}=\textbf{a}+ -\textbf{b}= \left(\begin{aligned} 5\\ 4\\ \end{aligned}\right) +\ \left(\begin{aligned} -3\\ -1\\ \end{aligned}\right) =\ \left(\begin{aligned} 2\\ 3\\ \end{aligned}\right)Therefore,
\mathbf{a}-\mathbf{b}= \left(\begin{aligned} 5\\ 4\\ \end{aligned}\right) -\ \left(\begin{aligned} 3\\ 1\\ \end{aligned}\right) =\ \left(\begin{aligned} 2\\ 3\\ \end{aligned}\right)
How does this relate to high school math?
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DOWNLOAD FREEIn order to subtract a vector from an original vector:
Subtract the vectors below.
\left(\begin{aligned} 6\\ 4\\ \end{aligned}\right) -\ \left(\begin{aligned} 4\\ 3\\ \end{aligned}\right)Subtract the second top number from the first top number.
6-4=22Subtract the \textbf{y} components.
Subtract the second bottom number from the first bottom number.
4-3=13Write the resultant vector.
Write the two answers as a column vector.
\left(\begin{aligned} 6\\ 4\\ \end{aligned}\right) -\ \left(\begin{aligned} 4\\ 3\\ \end{aligned}\right) =\ \left(\begin{aligned} 2\\ 1\\ \end{aligned}\right)Solve.
\left(\begin{aligned} 3\\ 2\\ \end{aligned}\right) -\ \left(\begin{aligned} 5\\ 1\\ \end{aligned}\right)Subtract the \textbf{x} components.
Subtract the second top number from the first top number.
3-5=-2
Subtract the \textbf{y} components.
Subtract the second bottom number from the first bottom number.
2-1=1
Write the resultant vector.
Write the two answers as a column vector.
\left(\begin{aligned}
3\\
2\\
\end{aligned}\right)
-\
\left(\begin{aligned}
5\\
1\\
\end{aligned}\right)
=\
\left(\begin{aligned}
-2\\
1\\
\end{aligned}\right)
Solve.
\left(\begin{aligned} 2\\ 4\\ \end{aligned}\right) -\ \left(\begin{aligned} 2\\ 6\\ \end{aligned}\right)Subtract the \textbf{x} components.
Subtract the second top number from the first top number.
2-2=0
Subtract the \textbf{y} components.
Subtract the second bottom number from the first bottom number.
4-6= -2
Write the resultant vector.
Write the two answers as a column vector.
Solve.
\left(\begin{aligned} -4\\ 3\\ \end{aligned}\right) -\ \left(\begin{aligned} 2\\ 1\\ \end{aligned}\right)Subtract the \textbf{x} components.
Subtract the second top number from the first top number.
-4-2=-6
Subtract the \textbf{y} components.
Subtract the second bottom number from the first bottom number.
3-1=2
Write the resultant vector.
Write the two answers as a column vector.
\left(\begin{aligned}
-4\\
3\\
\end{aligned}\right)
-\
\left(\begin{aligned}
2\\
1\\
\end{aligned}\right)
=\
\left(\begin{aligned}
-6\\
2\\
\end{aligned}\right)
Solve.
\left(\begin{aligned} -5\\ 2\\ \end{aligned}\right) -\ \left(\begin{aligned} -3\\ -2\\ \end{aligned}\right)Subtract the \textbf{x} components.
Subtract the second top number from the first top number.
-5-(-3)=-2
Subtract the \textbf{y} components.
Subtract the second bottom number from the first bottom number.
2-(-2)=4
Write the resultant vector.
Write the two answers as a column vector.
\left(\begin{aligned}
-5\\
2\\
\end{aligned}\right)
-\
\left(\begin{aligned}
-3\\
-2\\
\end{aligned}\right)
=\
\left(\begin{aligned}
-2\\
4\\
\end{aligned}\right)
Solve.
\left(\begin{aligned} 2\\ -1\\ \end{aligned}\right) -\ \left(\begin{aligned} -4\\ -3\\ \end{aligned}\right)Subtract the \textbf{x} components.
Subtract the second top number from the first top number.
2--4=6
Subtract the \textbf{y} components.
Subtract the second bottom number from the first bottom number.
-1--3=2
Write the resultant vector.
Write the two answers as a column vector.
1) Work out \textbf{v}-\textbf{w} :
\textbf{v}= \left(\begin{aligned} 7\\ 3\\ \end{aligned}\right) \text{and}\ \textbf{w}= \left(\begin{aligned} 4\\ 1\\ \end{aligned}\right)
2) Work out \textbf{c}-\textbf{d} :
\textbf{c}= \left(\begin{aligned} 6\\ 2\\ \end{aligned}\right) \text{and}\ \textbf{d}= \left(\begin{aligned} 3\\ 7\\ \end{aligned}\right)
3) Work out \textbf{b}-\textbf{a} :
\textbf{a}= \left(\begin{aligned} -1\\ 6\\ \end{aligned}\right) \text{and}\ \textbf{b}= \left(\begin{aligned} 5\\ 4\\ \end{aligned}\right)
4) Work out \textbf{p}-\textbf{q} :
\textbf{p}= \left(\begin{aligned} -3\\ 6\\ \end{aligned}\right) \text{and}\ \textbf{q}= \left(\begin{aligned} -2\\ 4\\ \end{aligned}\right)
5) Work out \textbf{s}-\textbf{r} :
\textbf{r}= \left(\begin{aligned} 3\\ 5\\ \end{aligned}\right) \text{and}\ \textbf{s}= \left(\begin{aligned} -2\\ -1\\ \end{aligned}\right)
6) Work out \textbf{e}-\textbf{d} :
\textbf{d}= \left(\begin{aligned} -2\\ 6\\ \end{aligned}\right) \text{and}\ \textbf{e}= \left(\begin{aligned} -4\\ 3\\ \end{aligned}\right)
Vector subtraction using the head-to-tail method involves placing the tail of the second vector at the head of the first vector. The resultant vector then goes from the tail of the first vector to the head of the second vector. It’s crucial to maintain the correct order to ensure precise results in vector operations.
Common mistakes in vector subtraction include neglecting vector direction, confusing the head-to-tail order, misunderstanding vector components, and forgetting to account for negative vectors. Visualization and careful attention to these aspects help prevent errors and ensure accurate results in vector mathematics.
Yes, vector subtraction can be simplified by breaking it into components. By decomposing vectors into horizontal and vertical components, students can subtract corresponding components separately. This method aids in clarity and accuracy when performing vector subtraction in two-dimensional space.
Vector subtraction is equivalent to adding the negative of a vector. When subtracting a vector, you can achieve the same result by adding its negative and finding the vector sum. Paying attention to signs and understanding this relationship simplifies vector operations and provides a conceptual bridge between vector addition and subtraction.
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