Law of sines

Here is everything you need to know about the Law of Sines. You will learn what it is and how to use it to find the missing sides and angles of a triangle.

Students first learn how to work with the law of sines in geometry and expand that knowledge as they progress through algebra 2 and precalculus.

What is the law of sines?

The Law of Sines (or the sine rule) is a proportional relationship between the size of an angle in a triangle and its opposite side.

The Law of Sines is used to find the missing sides and missing angles of a triangle.

Recall that SOHCAHTOA is used to find missing sides and angles in right triangles (right-angled triangles).

The Law of Sines can be used with any oblique triangle and also with right triangles.

The proportional relationship is:

\cfrac{\sin(A)}{a}=\cfrac{\sin(B)}{b}=\cfrac{\sin(C)}{c}

Law of Sines 1 US

Notice that angle A (vertex A ) is across from side a, angle B (vertex B ) is across side b, and angle C (vertex C ) is across side c.

Law of Sines 2 US

Even though there are three relationships in a triangle between the three angles and their opposite sides, you only need to use two of them for the Law of Sines.

This would look like:

\cfrac{\sin(A)}{a}=\cfrac{\sin(B)}{b}

The law of sines in this form is useful to find a missing angle. By rearranging the law of sines, the reciprocal is also useful to know if you want to find a missing side length:

\cfrac{a}{\sin(A)}=\cfrac{b}{\sin(B)}\left(=\cfrac{c}{\sin(C)}\right)

What is the Law of Sines?

What is the Law of Sines?

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[FREE] Trigonometry Check for Understanding Quiz (Grade 9 to 12)

[FREE] Trigonometry Check for Understanding Quiz (Grade 9 to 12)

[FREE] Trigonometry Check for Understanding Quiz (Grade 9 to 12)

Use this quiz to check your grade 9 to 12 students’ understanding of Trigonometry. 15+ questions with answers covering a range of 9th to 12th grade trigonometry topics to identify areas of strength and support!

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Common Core State Standards

How does this relate to high school math?

  • High School Geometry – Similarity, Right Triangles, and Trigonometry – HSG-SRT.D.10 (+)
    Prove the Laws of Sines and Cosines and use them to solve problems.

  • High School Geometry – Similarity, Right Triangles, and Trigonometry – HSG-SRT.D.11 (+)
    Understand and apply the Law of Sines and the Law of Cosines to find unknown measurements in right and non-right triangles (example, surveying problems, resultant forces).

How to use the law of sines

In order to use the law of sines to find missing sides and angles:

  1. Label each angle \textbf{(A, B, C)} and each side \textbf{(a, b, c)} of the triangle.
  2. Use the law of sines to write the proportional relationship.
  3. Solve for the missing side or angle.

Law of sines examples

Example 1: finding a missing side of a triangle.

Find the length of side AB. Write your answer to two decimal places.

Law of Sines 3 US

  1. Label each angle \textbf{(A, B, C)} and each side \textbf{(a, b, c)} of the triangle.

Law of Sines 4 US

Side AB is labeled c, so you are solving for c.

2Use the law of sines to write the proportional relationship.

Using the values known and the law of sines, the proportional relationship is:

\cfrac{\sin(C)}{c}=\cfrac{\sin(A)}{a}

Substitute in the values:

\cfrac{\sin(73)}{c}=\cfrac{\sin(55)}{6}

3Solve for the missing side or angle.

Multiply both sides of the equation by c .

\cfrac{\sin(73)}{c}\times{c}=\cfrac{\sin(55)}{6}\times{c}

\sin(73)=\cfrac{\sin(55)}{6}\times{c}

Multiply both sides by 6 .

\sin(73)\times{6}=\cfrac{\sin(55)}{6}\times{c}\times{6}

6\sin(73)=c\sin(55)

Divide both sides by \sin(55) .

\cfrac{6\sin(73)}{\sin(55)}=\cfrac{c\sin(55)}{\sin(55)}

\cfrac{6\sin(73)}{\sin(55)}=c

Use the calculator to calculate the value of c .

c=7.00\mathrm{~cm}\text{ (2dp)}

Example 2: finding a missing side of a triangle.

Find side BC. Write your answer to two decimal places.

Law of Sines 5 US

Label each angle \textbf{(A, B, C)} and each side \textbf{(a, b, c)} of the triangle.

Use the law of sines to write the proportional relationship.

Solve for the missing side or angle.

Example 3: finding a missing side of a triangle.

Find the length AC. Write your answer to two decimal places.

Law of Sines 7 US

Label each angle \textbf{(A, B, C)} and each side \textbf{(a, b, c)} of the triangle.

Use the law of sines to write the proportional relationship.

Solve for the missing side or angle.

Example 4: finding a missing angle of a triangle.

Find the measure of the missing angle \theta. Write your answer to one decimal place.

Law of Sines 9 US

Label each angle \textbf{(A, B, C)} and each side \textbf{(a, b, c)} of the triangle.

Use the law of sines to write the proportional relationship.

Solve for the missing side or angle.

Example 5: finding a missing angle of a triangle.

Find the measure of the missing angle \theta. Write your answer to one decimal place.

Law of Sines 12 US

Label each angle \textbf{(A, B, C)} and each side \textbf{(a, b, c)} of the triangle.

Use the law of sines to write the proportional relationship.

Solve for the missing side or angle.

Example 6: finding a missing angle of a triangle.

Find the measure of the missing angle \theta.

Law of Sines 15 US

Label each angle \textbf{(A, B, C)} and each side \textbf{(a, b, c)} of the triangle.

Use the law of sines to write the proportional relationship.

Solve for the missing side or angle.

Teaching tips for Law of Sines

  • Provide opportunities for students to investigate the law of sines.

  • Give students different scenarios to determine when the law of sines works. For example, when the triangle has known parts set up as ASA, AAS, SAS, SSS\text{.}

  • Accurately construct triangles for students to investigate the law of sines. What happens with similar triangles? What happens if one angle is double the original size?

Easy mistakes to make

  • Labeling the triangle incorrectly
    Labeling the triangle incorrectly can lead to incorrect calculations and incorrect use of the law of sines. For example, this triangle has been incorrectly labeled with the side next to the angle.

    Law of Sines 17 US

    Remember, the correct way is to label the angles and across from the angle is the side, for example:

    Law of Sines 18 US

  • Mixing up when to use the sine and inverse sine function
    Remember that when finding a side, you have to use the sine function. When finding a missing angle, you need to use the inverse sine function (\sin^{-1}).

  • Mixing up the radian measure and degree measure when using trigonometric functions
    For example, when finding a missing angle of a triangle, be sure to express the angle in degree measure. So, in your calculator be sure the β€˜mode’ is in degrees, not radians.

  • Using the incorrect set up for the sine rule formula
    It should not be too difficult to rearrange the formula once you have substituted the values, however small errors will make an impact on your solution.

  • Canceling out sine functions
    For example, when calculating the value for a in example 2, the following calculation error is made.

    \begin{aligned}\cfrac{a}{\sin(41)}&=\cfrac{3.4}{\sin(27)} \\\\ a&=\cfrac{3.4\sin(41)}{\sin(27)} \\\\ &=\cfrac{3.4\times{41}}{27} \\\\ &=5.16\text{ (2dp)} \end{aligned}

Law of sines practice questions

1. Find the length of BC. Write your answer to two decimal places.

 

Law of Sines 19 US

6.29\mathrm{~cm}
GCSE Quiz False

4.95\mathrm{~cm}
GCSE Quiz False

6.07\mathrm{~cm}
GCSE Quiz False

6.11\mathrm{~cm}
GCSE Quiz True

First label the angles and sides of the triangle.

 

Law of Sines 20 US

 

In this case, side BC is labeled a. Using the law of sines, the proportional relationship is:

 

\cfrac{a}{\sin(A)}=\cfrac{c}{\sin(C)}

 

Substitute the known values and solve for a.

 

\begin{aligned}\cfrac{a}{\sin(48)}&=\cfrac{5.5}{\sin(42)} \\\\ a&=\cfrac{5.5}{\sin(42)}\times\sin(48) \\\\ a&=6.11\mathrm{~cm} \end{aligned}

2. Find the length PQ. Write your answer to two decimal places.

 

Law of Sines 21 US

88.02\mathrm{~mm}
GCSE Quiz True

34.37\mathrm{~mm}
GCSE Quiz False

99.69\mathrm{~mm}
GCSE Quiz False

88.21\mathrm{~mm}
GCSE Quiz False

First label the sides and the angles of the triangle using A, B, C.

 

Law of Sines 22 US

 

Using the law sines, the correct proportional relationship is:

 

\cfrac{b}{\sin(B)}=\cfrac{c}{\sin(C)}

 

Substitute in the values.

 

\begin{aligned}\cfrac{55}{\sin(32)}&=\cfrac{c}{\sin(58)} \\\\ c&=\cfrac{55}{\sin(32)}\times\sin(58) \\\\ &=88.02\mathrm{~mm} \end{aligned}

3. Find the unknown side length XY. Write your answer to two decimal places.

 

Law of Sines 23 US

7.16\mathrm{~cm}
GCSE Quiz False

6.09\mathrm{~cm}
GCSE Quiz True

5.83\mathrm{~cm}
GCSE Quiz False

7.47\mathrm{~cm}
GCSE Quiz False

First, label the triangle using A, B, C and a, b, c.

 

Law of Sines 24 US

 

Using the law of sines, the proportional relationship is:

 

\cfrac{a}{\sin(A)}=\cfrac{c}{\sin(C)}

 

Substitute in the values.

 

\begin{aligned}\cfrac{6.6}{\sin(60)}&=\cfrac{c}{\sin(53)} \\\\ c&=\cfrac{6.6}{\sin(60)}\times\sin(53) \\\\ &=6.09\mathrm{~cm} \end{aligned}

4. Find the measure of the angle \theta. Write your answer to the nearest whole degree.

 

Law of Sines 25 US

66^{\circ}
GCSE Quiz False

70^{\circ}
GCSE Quiz True

0.016^{\circ}
GCSE Quiz False

1^{\circ}
GCSE Quiz False

First, label the triangle using A, B, C and a, b, c.

 

Law of Sines 26 US

 

Using the law of sines, the proportional relationship is:

 

\cfrac{\sin(B)}{b}=\cfrac{\sin(C)}{c}

 

Substitute in the values:

 

\begin{aligned}\cfrac{\sin(\theta)}{7.4}&=\cfrac{\sin(68)}{7.3} \\\\ \sin(\theta)&=\cfrac{\sin(68)}{7.3}\times{7.4} \\\\ \sin(\theta)&=0.9398850033… \\\\ \theta&=\sin^{-1}(0.9398850033…) \\\\ \theta&=70^{\circ}\text{ (2sf)} \end{aligned}

5. Find the measure of angle \theta. Write your answer to two decimal places.

 

Law of Sines 27 US

27.58^{\circ}
GCSE Quiz True

51.90^{\circ}
GCSE Quiz False

28.16^{\circ}
GCSE Quiz False

32.51^{\circ}
GCSE Quiz False

First, label the triangle using A, B, C and a, b, c.

 

Law of Sines 28 US

 

Using the law of sines, the proportional relationship is:

 

\cfrac{\sin(A)}{a}=\cfrac{\sin(C)}{c}

 

Substitute in the values:

 

\begin{aligned}\cfrac{\sin(62)}{8.2}&=\cfrac{\sin(\theta)}{4.3} \\\\ \sin(\theta)&=\cfrac{\sin(62)}{8.2}\times{4.3} \\\\ \sin(\theta)&=0.4630091036… \\\\ \theta&=\sin ^{-1}(0.4630091036) \\\\ \theta&=27.58^{\circ}\text{ (2dp)} \end{aligned}

6. Find the measure of the unknown angle which is labeled as \theta. Round your answer to the nearest tenth.

 

Law of Sines 29 US

72^{\circ}
GCSE Quiz False

22.5^{\circ}
GCSE Quiz False

64.7^{\circ}
GCSE Quiz True

55.4^{\circ}
GCSE Quiz False

Label the triangle using A, B, C and a, b, c.

 

Law of Sines 30 US

 

Using the law of sines, make the proportional relationship.

 

\cfrac{\sin(A)}{a}=\cfrac{\sin(B)}{b}

 

Substitute in the values:

 

\begin{aligned}\cfrac{\sin(\theta)}{10}&=\cfrac{\sin(36)}{6.5} \\\\ \sin(\theta)&=\cfrac{\sin(36)}{6.5}\times{10} \\\\ \sin(\theta)&=0.9042850035… \\\\ \theta&=\sin^{-1}(0.9042850035…) \\\\ \theta&=64.72^{\circ}\text{ (3sf)} \end{aligned}

Law of sines FAQs

Can you use the law of sines (sine law or sine formula) on right triangles?

Yes, you can use the law of sines to find the missing angles and sides of right triangles. The right angle and the hypotenuse would be one of the ratios you would use.

Does the reciprocal of the law of sines work?

Yes, you can use the reciprocal of the law of sines meaning that you can write the proportion as \cfrac{a}{\sin(A)}=\cfrac{b}{\sin(B)}=\cfrac{c}{\sin(C)}.

Do all of the trigonometric functions have laws like the law of sines and the law of cosines?

No, not all the trigonometric functions have laws or rules.

What is the ambiguous case with the law of sines?

The ambiguous case of the law of sines is when it is used to find a missing side length of a triangle and the result has two possible solutions for the measure of the same side. This will happen when the triangle has two sides and a non-included angle or (SSA) set up.

Can you use the law of sines to find the area of a triangle?

The law of sines can be helpful to find a missing side length, such as the base or the height of the triangle. Similarly, the law of cosines can also be used to help find the area of a triangle.

Is there a law of tangents rule?

There is a law of tangents, but it is rarely or never taught in high school. However, if you pursue mathematics in college, there is a possibility you will learn about it.

The next lessons are

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